我使用的似乎是创建连接View的常用技巧://aCustomerhasmanyOrders;showthemtogetherinoneview:function(doc){if(doc.Type=="customer"){emit([doc._id,0],doc);}elseif(doc.Type=="order"){emit([doc.customer_id,1],doc);}}我知道我可以使用以下查询来获取单个customer和所有相关的Order:?startkey=["some_customer_id"]&endkey=["some_customer_id",2]但现在我非常将
考虑这个数组:[["B","C","C","C","C","B","B","C","A","A"],["B","A","C","B","B","A","B","B","A","A"],["B","C","B","C","A","A","A","B","C","B"],["B","B","B","A","C","B","A","C","B","A"],["A","A","A","C","A","C","C","B","A","C"],["A","B","B","A","A","C","B","C","C","C"],["C","B","A","A","C","B","B","C","A"
我有一个像这样的树结构数据:[{id:54,name:123,children:[{id:54,name:123,children:[{id:154,name:1234,children[]...}]}]},{...}]我使用的是Angular2。据我所知,每当输入发生变化并且您的变化检测策略是onPush时,变化检测就会启动。.为了优化树结构更新(例如,在嵌套级别切换节点或更改此类节点的任何属性),我使用了Immutable.Immutable如何帮助我优化更新?我读到Immutable会在数据发生变化时重用旧数据的引用来构造新对象。如何有效地使用不可变数据结构来更新嵌套级别的节点?