我正在尝试在这样的文档中对字段status进行异或:{"_id":ObjectId("58c51e1aedb6e4000410ddbf"),"query":"developer","user_id":"1413322622039651","status":1,"links":["840673302343483394","840672745222483968","840672580717686785","840672427550089216","840582170548850688","840581988918669312"],"links_size":6,"created":ISODa
我想在每次访问我的文档时将views计数加1。到目前为止，我的代码是:Document.find({}).sort('date',-1).limit(limit).exec();$inc在哪里适合？ 最佳答案 从未使用过mongoose，但很快查看了文档here看起来这对你有用:#createqueryconditionsandupdatevariablesvarconditions={},update={$inc:{views:1}};#updatedocumentsmatchingconditionModel.update(co
我想在每次访问我的文档时将views计数加1。到目前为止，我的代码是:Document.find({}).sort('date',-1).limit(limit).exec();$inc在哪里适合？ 最佳答案 从未使用过mongoose，但很快查看了文档here看起来这对你有用:#createqueryconditionsandupdatevariablesvarconditions={},update={$inc:{views:1}};#updatedocumentsmatchingconditionModel.update(co
...(...=someunrelatedcode)varmongoose=require('mongoose');vardb=mongoose.connect('mongodb://localhost/test');...dataSchema=newSchema({'url':{type:String,index:true},'user_id':{type:Schema.ObjectId,index:true}});varWebsite=mongoose.model('websites',dataSchema);...Website.findOne({url:"someurl.com
当我想在nodejs中包含我的模型和Mongoose时，我遇到了一个问题，我正在创建一个具有这样架构的模型varmongoose=require('mongoose'),Schema=mongoose.Schema;varUsers=newSchema({idUser:{type:String},username:{type:String}});//middlewareUsers.pre('save',function(next,done){notify(this.get('email')+done);//somethinggoeswrongnext(newError('somethi
我有一个模型架构:varA=newSchema({a:String,b:[{ba:Integer,bb:String}]},{collection:'a'});然后varM=mongoose.model("a",A);varsaveid=null;varm=newM({a:"Hello"});m.save(function(err,model){saveid=model.id;});//saymgettheidas"1"然后m['b'].push({ba:235,bb:"World"});m.save(function(err,model){console.log(model.id);
我有一个模型架构:varA=newSchema({a:String,b:[{ba:Integer,bb:String}]},{collection:'a'});然后varM=mongoose.model("a",A);varsaveid=null;varm=newM({a:"Hello"});m.save(function(err,model){saveid=model.id;});//saymgettheidas"1"然后m['b'].push({ba:235,bb:"World"});m.save(function(err,model){console.log(model.id);
这是我当前的架构品牌:varmongoose=require('mongoose');varSchema=mongoose.Schema;varBrandSchema=newmongoose.Schema({name:{type:String,lowercase:true,unique:true,required:true},photo:{type:String,trim:true},email:{type:String,lowercase:true},year:{type:Number},timestamp:{type:Date,default:Date.now},descripti
我的问题有点幼稚，但我到处搜索都找不到答案。我有一个user的架构name:{type:String},relations:[{entity:mongoose.Schema.Types.ObjectId,year:{type:Number}}]我想用relations.entity=R1更新用户的年份我可以使用update函数对其进行更新vartoupdate={}toupdate["relations.$.year"]=1900;User.update({'relations.entity':'R1'},{"$set":toupdate},function(err,results){
如何在mongoose中定义以下MongoDB聚合查询:db.contacts.aggregate([{$group:{"_id":{code:"$Code",name:"$Name"}}}])查询的目的是提取不同代码和名称的列表。我目前的型号代码是:'usestrict';varmongoose=require('mongoose'),Schema=mongoose.Schema,ObjectId=Schema.ObjectId;varfields={Code:{type:String},Name:{type:String}};varcontactSchema=newSchema(f
