我创建了一个棋盘,但我不喜欢我的switchcase语句的外观。我想一定有办法压缩它,但我找不到。也许你们中的一些人可以帮助我。补充说明,棋子是二维数组(arr2):[["R","N","B","Q","K","B","N","R"],["P","P","P","P","P","P","P","P"],["0","0","0","0","0","0","0","0"],["0","0","0","0","0","0","0","0"],["0","0","0","0","0","0","0","0"],["0","0","0","0","0","0","0","0"],["p","p"
我有很多几乎相同的测试。为了DRY和可扫描性,我想将测试抽象为一个函数,然后使用一些参数调用该函数。然后该函数将调用它并将规范添加到套件中。它似乎可以工作,除了规范不会以与其他规范相同的方式运行,并且beforeEach不会在公共(public)函数中定义的规范之前被调用。define(['modules/MyModule','jasmine/jasmine'],function(MyModule){describe('myModule',function(){functioncommonTests(params){it('shouldpassthistestOK',function(
我想同时创建两个数组b和c。我知道有两种方法可以实现它。第一种方法是b=([i,i*2]foriin[0..10])c=([i,i*3]foriin[0..10])alert"b=#{b}"alert"c=#{c}"这种方法对于只创建一个数组非常方便。我不可能是获得更好计算性能的更好方法。第二种方法是b=[]c=[]foriin[0..10]b.push[i,i*2]c.push[i,i*3]alert"b=#{b}"alert"c=#{c}"这个方法看起来计算效率不错但是有两行b=[]c=[]必须先写。我不想写这两行,但我还没有找到答案的好主意。如果不对b和c的数组进行初始化,我们就