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swift - 如何获取并添加到 Syncano 对 user_profile 的引用

如标题所示,我有问题如何添加到syncano对user_profile的引用,如果有人可以告诉我一个提示?所以这是我的代码:funcsaveName(){letUerextra=userextra()Uerextra.name=(self.dict.objectForKey("first_name")as?String)!Uerextra.lastName=(self.dict.objectForKey("last_name")as?String)!Uerextra.avatarUrl=self.dict.objectForKey("picture")?.objectForKey("d

swift - 无法在 Xcode 7.3.1 上使用类型为 'Result<Any>' 的参数列表调用类型为 '(int,int)' 的初始值设定项

在Xcode7.3.1的playground上尝试这个会给我编译错误:Cannotinvokeinitializerfortype'Result'withanargumentlistoftype'(int,int)'不过在Xcode7.3上它运行良好。这是代码:importUIKitpublicenumResult{caseSuccess(T)caseFailure(ErrorType)publicinit(_value:T){self=.Success(value)}publicinit(_error:ErrorType){self=.Failure(error)}}funchand

iOS 本地通知 : app is not asking for permissions to notify the user

我不确定这是否是一个奇怪的错误,但在我的-(BOOL)application:(UIApplication*)applicationdidFinishLaunchingWithOptions:(NSDictionary*)launchOptions我有以下几行代码来请求用户权限://RegisterforPushNotitications,ifrunningiOS8if([applicationrespondsToSelector:@selector(registerUserNotificationSettings:)]){UIUserNotificationTypeuserNotif

ios - 如何在 iOS 上使用 Sign In with Google 修复 `The user canceled the sign-in flow.`?

我正在将SigninwithGoogle与iOSFirebaseSDK集成。当用户点击GIDSignIn按钮时,应用程序会显示一条警告,显示“MyAPP”想要使用Google.com登录,但警告很快就会消失。我在didSignInForuser:GIDGoogleUser方法中得到的错误如下:2019-02-2116:54:13.104279+0530MyApp[18743:185089][Warning]Attemptingtoloadtheviewofaviewcontrollerwhileitisdeallocatingisnotallowedandmayresultinunde

swift - 如何从嵌套的父 firebase 获取 user_id

我想根据user_id检索站点信息,我正在使用以下查询来检索站点信息ref=Database.database().reference()self.ref.child("sites").queryOrdered(byChild:"user_id").queryEqual(toValue:"DxMYXkVqnZMC6NEZxdSQF3G2ZJ53").observe(.childAdded,with:{snapshotinif(snapshot.valueisNSNull){print("Notfound")}else{print("found")}})如果它的store_name、id

ios - UIPageController : Turning the page forward then backward quickly only updates the first page

我的类SliderPgaeViewController:UIPageViewController具有如下滚动过渡样式:classSliderPgaeViewController:UIPageViewController,UIPageViewControllerDelegate,UIPageViewControllerDataSource,PlayerUpdatePageControllerDelegate{varlastPendingIndex:Int=0varsliderPageDelegate:SliderPageDelegate?=nilletplayerManager=Play

Linux下报错MySQL Access denied for user ‘root‘@‘localhost‘ (using password: YES)解决方案

1.先进入root模式2.进入#vim/etc/my.cnf在[mysqld]后面任意一行添加“skip-grant-tables”用来跳过密码验证的过程,保存退出3.systemctlrestartmysql#重启服务 或者  servicemysqldrestart#重启服务4.mysql-uroot-p没有密码可以直接进入5.updatemysql.usersetauthentication_string=PASSWORD('你的新密码')whereUSER='root';6.flushprivileges;#刷新权限表7.再次vim/etc/my.cnf删除添加的skip-grant-

swift - 错误 : cannot convert value of type '() -> ()' to closure result type 'String' using Swift + PromiseKit

我不熟悉Swift中的promise,并使用PromiseKit尝试在Playground上创建一个非常简单的响应并尝试使用它。我有以下代码:importUIKitimportPromiseKitfuncfoo(_error:Bool)->Promise{returnPromise{fulfill,rejectinif(!error){fulfill("foo")}else{reject(Error(domain:"",code:1,userInfo:nil))}}}foo(true).then{response->Stringin{print(response)}}但是我得到以下错误

ios - 为非用户对象保存获取 "User cannot be saved unless they have been authenticated via logIn or signUp"

这太奇怪了。昨晚开始出现,今天早上消失了,现在又出现了。我正在尝试将当前用户保存为关注者,将另一个用户保存为关注对象。代码是:letfollow=PFObject(className:"Follow")follow["follower"]=PFUser.currentUser()follow["following"]=["__type":"Pointer","className":"_User","objectId":objectId]follow.saveInBackgroundWithBlock{(success,error)->Voidiniferror!=nil{print(e

ios - alamofire post 方法中的 response.result.value 为 nil

letparametersDictionary=["email":"name@gmail.com","password":"password"]Alamofire.request("http://nanosoftech.com/store/user_check",method:.post,parameters:(parametersDictionaryasNSDictionary)as?Parameters,encoding:JSONEncoding.default,headers:nil).responseJSON{responseinprint("response:",respon