使用以下设置....MyUIMenuItem*someAction=[[MyUIMenuItemalloc]initWithTitle:@"Something"action:@selector(menuItemSelected:)];MyUIMenuItem*someAction2=[[MyUIMenuItemalloc]initWithTitle:@"Something2"action:@selector(menuItemSelected:)];....-(IBAction)menuItemSelected:(id)sender{UIMenuController*mmi=(UIMen

我想要在长按UITableViewCell以显示自定义UIMenuItems时弹出的UIMenuController。我在viewDidLoad中设置自定义项UIMenuItem*testMenuItem=[[UIMenuItemalloc]initWithTitle:@"Test"action:@selector(test:)];[[UIMenuControllersharedMenuController]setMenuItems:@[testMenuItem]];然后我设置所有正确的委托(delegate)方法。-(BOOL)tableView:(UITableView*)tabl