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leetcode 572. Subtree of Another Tree 另一棵树的子树 (简单)

一、题目大意给你两棵二叉树root和subRoot。检验root中是否包含和subRoot具有相同结构和节点值的子树。如果存在,返回true;否则,返回false。二叉树tree的一棵子树包括tree的某个节点和这个节点的所有后代节点。tree也可以看做它自身的一棵子树。示例1:输入:root=[3,4,5,1,2],subRoot=[4,1,2]输出:true示例2:输入:root=[3,4,5,1,2,null,null,null,null,0],subRoot=[4,1,2]输出:false提示:root树上的节点数量范围是[1,2000]subRoot树上的节点数量范围是[1,1000

It is currently in use by another Gradle instance

FAILURE:Buildfailedwithanexception.*Whatwentwrong:CouldnotcreateserviceoftypeTaskHistoryRepositoryusingTaskExecutionServices.createTaskHistoryRepository().>Timeoutwaitingtolocktaskhistorycache(/Volumes/MacUser/macbook/lab/aws/training/gradle_student_mgmt/.gradle/4.5.1/taskHistory).Itiscurrentlyinuse

It is currently in use by another Gradle instance

FAILURE:Buildfailedwithanexception.*Whatwentwrong:CouldnotcreateserviceoftypeTaskHistoryRepositoryusingTaskExecutionServices.createTaskHistoryRepository().>Timeoutwaitingtolocktaskhistorycache(/Volumes/MacUser/macbook/lab/aws/training/gradle_student_mgmt/.gradle/4.5.1/taskHistory).Itiscurrentlyinuse