这是我的收藏:{"_id":10926400,"votes":131,"author":"Jesse","comments":[{"id":1,"votes":31,"author":"Mirek"},{"id":2,"votes":13,"author":"Leszke"}]},{"_id":10926401,"votes":75,"author":"Mirek","comments":[{"id":1,"votes":17,"author":"Jesse"},{"id":2,"votes":29,"author":"Mirek"}]}我想要每个author的$sumvotes和co
我正在尝试在填充方法中使用查询条件。如果使用条件，则仍会填充所有记录，但不满足条件的记录会将填充字段设置为空，例如:varquery=BookModel.find();query.populate('author','name',{name:'author1'});query.find(function(err,books){console.log(books);});Thentheoutputis:[{author:{_id:4ea0db52e09aa6aad2e831fe,name:'author1'},title:'book1',_id:4ea0dbebc191848704000
我在获取数据时遇到了一些问题。我有Mongoose方案。PostSchema.methods.getAuthor=function(){this.model('User').findById(this.author).exec(function(err,author){if(author){console.log(author.username);returnauthor.username;};});};mongoose.model('Post',PostSchema);和获取方法exports.getPost=function(req,res){returnPost.findById
如果我有一个具有以下架构的集合:{"author":…,"title":…,"pages":…,"publishDate":…,}其中author和title是复合索引的一部分。我想找到所有作者和标题可能是以下之一的文档:"Melville","MobyDick""Orwell","1984""Tolkien","TheHobbit"如何使用"$in"语句来实现？我可以用"$or"做到这一点，但性能是灾难性的。 最佳答案 如果您更改架构以将那对键放入单独的子文档中，则可以使用$in执行此操作:{key:{author:'Melvil
我是nodejs/mongo/mongoose的新手，我正在尝试做一件非常简单的事情。我有以下架构:varauthorSchema=mongoose.Schema({name:String,});Author=mongoose.model('Author',authorSchema);varbookSchema=mongoose.Schema({title:String,isbn:String,pages:Number,author:{type:mongoose.Schema.ObjectId,ref:'Author',index:true}});Book=mongoose.model
我正在尝试更新用户的角色。所以我尝试使用管理员用户执行以下命令(它具有dbOwner和userAdmin权限，并直接在UnitTestDb上创建)db.runCommand({"updateUser":"unittestuser1","roles":[{"role":"Testentity_readwrite","db":"UnitTestDb"},{"role":"Testentity_read","db":"UnitTestDb"}]}我直接在“UnitTestDb”上运行这个命令，角色“Testentity_read”也是直接在这个数据库中创建的。我收到以下错误:{"ok":0,
我正在Flask+MongoDB(w/pymongo)中制作一个迷你Twitter克隆作为学习练习，我需要一些帮助来连接来自两个集合的数据。我知道并理解无法在MongoDB中完成连接，这就是为什么我要问如何在Python中完成。我有一个集合来存储用户信息。文档看起来像这样:{"_id":ObjectId("51a6c4e3eedc89e34ee46e32"),"email":"alex@email.com","message":[ObjectId("51a6c5e1eedc89e34ee46e36")],"pw_hash":"alexhash","username":"alex","w
在MongoDB页面中:http://www.mongodb.org/display/DOCS/Insertingdoc={author:'joe',created:newDate('03/28/2009'),title:'Yetanotherblogpost',text:'Hereisthetext...',tags:['example','joe'],comments:[{author:'jim',comment:'Idisagree'},{author:'nancy',comment:'Goodpost'}]}db.posts.insert(doc);db.posts.find(
作为mongodb的老手，我创建了如下结构:User:{name:str,email:...}Gift:{#authorandreceiverrefertoUserobjectsobviouslyauthor:object_id(...),receiver:object_id(...),name:str...}我想在mongoid中正确映射它:classUserincludeMongoid::Documenthas_many:giftsendclassGiftincludeMongoid::Documentbelongs_to:userend但是，映射不正确。g=Gift.first;
我知道有很多话题都在讨论这个问题，但我无法弄清楚我的实现过程中出了什么问题。我有以下文件:{"_id":ObjectId("510a353929e16756d5000009"),"skills":[["UserEmbed::Author::Skills::Copywriting","UserEmbed::Author::Skills::Proofreading","UserEmbed::Author::Skills::Proofreading","UserEmbed::Author::Skills::Translation","UserEmbed::Author::Skills::Tr
