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python - 准确度分值Error : Can't Handle mix of binary and continuous target

我正在使用来自scikit-learn的linear_model.LinearRegression作为预测模型。它有效,而且非常完美。我在使用accuracy_score指标评估预测结果时遇到问题。这是我的真实数据:array([1,1,0,0,0,0,1,1,0,0,1,1,0,0,0,0,0])我的预测数据:array([0.07094605,0.1994941,0.19270157,0.13379635,0.04654469,0.09212494,0.19952108,0.12884365,0.15685076,-0.01274453,0.32167554,0.32167554,

java - 接口(interface)和继承 : "return type int is not compatible"

publicinterfaceMyInterface{publicintmyMethod();}publicclassSuperClass{publicStringmyMethod(){return"SuperClass";}}publicclassDerivedClassextendsSuperClassimplementsMyInterface{publicStringmyMethod(){...}//thislinedoesn'tcompilepublicintmyMethod(){...}//thisisalsounabletocompile}当我尝试编译DerivedClas

ios - flutter IOS : CocoaPods could not find compatible versions for pod "simple_permissions":

我是Flutter的新手,并在Flutter中开发Permission演示。我使用了simple_permission插件,这个插件在android中工作,但在ios中它给了我以下错误:CocoaPodscouldnotfindcompatibleversionsforpod"simple_permissions":Insnapshot(Podfile.lock):simple_permissions(from`.symlinks/plugins/simple_permissions/ios`)InPodfile:simple_permissions(from`.symlinks/pl

android - OnGlobalLayoutListener : deprecation and compatibility

我必须使用OnGlobalLayoutListener对象,然后删除监听器,我遇到了不推荐使用的方法的问题,我使用以下代码解决了这个问题。protectedvoidonCreate(BundlesavedInstanceState){finalLinearLayoutllTotal=(LinearLayout)findViewById(R.id.mmc_ll);ViewTreeObservervto=llTotal.getViewTreeObserver();if(vto.isAlive()){vto.addOnGlobalLayoutListener(newOnGlobalLayou

node.js - W : Failed to fetch http://deb. debian.org/debian/dists/jessie-updates/main/binary-amd64/Packages 404 未找到 [IP : 151. 101.140.204 80]

我正在尝试让一个项目在Deepin上本地运行。该项目依赖于Node6.10,我知道它是一个旧版本,但它可以工作。当Dockerfile尝试运行sudoapt-getupdate时,会出现以下错误:W:Failedtofetchhttp://deb.debian.org/debian/dists/jessie-updates/main/binary-amd64/Packages404NotFound[IP:151.101.140.20480]奇怪的是,我昨天刚刚在Macbook上部署了它,没有出现这样的问题。有什么想法吗?提到的重复问题对我没有帮助,因为我不依赖DebianJessie的

c++ - 从 std::binary_function (或 std::unary 函数)继承有什么好处?

从std::binary_function(或std::unary_function)继承有什么好处?例如我有这样的代码:classPerson{public:Person();Person(inta,std::stringn);Person(constPerson&src);intage;std::stringname;};Person::Person():age(0),name(""){};Person::Person(inta,std::stringn):age(a),name(n){};Person::Person(constPerson&src){age=src.age;na

c++ - 错误 C2679 : binary '>>' : no operator found which takes a right-hand operand of type 'std::string' (or there is no acceptable conversion)

请不要与标题混淆,因为它已经有人问过了,但上下文不同VisualC++Compiler(VS2008)中的以下代码没有被编译,而是抛出了这个异常:std::ifstreaminput(fileName);while(input){strings;input>>s;std::cout但是这段代码在cygwing++中编译得很好。有什么想法吗? 最佳答案 您是否包含以下所有标题?我猜你忘了.附带说明:应该是std::cout和std::endl. 关于c++-错误C2679:binary'>

binary - 从整数转换为其二进制表示

有没有人知道Go中是否有任何内置功能可以将任何一种数字类型转换为其二进制数字形式。例如,如果123是输入,则字符串"1111011"将是输出。 最佳答案 strconv包有FormatInt,它接受int64并让您指定基数。n:=int64(123)fmt.Println(strconv.FormatInt(n,2))//1111011演示:http://play.golang.org/p/leGVAELMhvhttp://golang.org/pkg/strconv/#FormatIntfuncFormatInt(iint64,b

linux - 如何检测文本文件中的无效 utf8 unicode/binary

我需要检测存在无效(非ASCII)utf-8、Unicode或二进制字符的损坏文本文件。�>t�ï¿ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½ï¿½w�ï¿ï¿½ï¿½ï¿½ï¿

c++ - "Launch Failed. Binary Not Found."雪豹和Eclipse C/C++ IDE问题

不是问题,我刚刚在互联网上搜索了这个问题的解决方案,并认为我会与SO的好人分享。我会用简单的术语来说明它,以便新手可以使用它。:)(抱歉,如果这是错误的地方-只是想提供帮助。)几乎所有尝试使用EclipseC/C++IDE的OSXSnowLeopard用户都会出现此问题,但对于在Leopard中使用EclipseC/C++IDE的人(如我)来说尤其烦人,并且升级后无法再使用Eclipse。当用户去构建/编译/链接他们的软件时,就会出现这个问题。他们收到以下错误:LaunchFailed.BinaryNotFound.此外,左侧项目窗口中的“二进制”分支根本不存在。问题:SnowLeop