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hadoop - Apache-PIG 脚本 : ERROR Invalid field projection on joined variable

我创建的Pig脚本有效,除非我尝试在我加入的字段上使用GENERATE。cc_data=LOAD'default.complaint1'USINGorg.apache.hive.hcatalog.pig.HCatLoader();cc2_data=LOAD'default.complaint2'USINGorg.apache.hive.hcatalog.pig.HCatLoader();combined=joincc_databycomplaintid,cc2_databycomplaintid;如果我对我的组合执行DESCRIBE,它会显示如下:合并:{cc_data::datere

mysql - 配置单元 : why is metastore_db created in my project folder?

我把hive-site.xml在我的spark/confdir并将其配置为连接到thrift://:9083而且我没有使用derby我有mysql-connector-jar在hive/lib文件夹中,每次我创建hive表和存储数据时,所有数据都存储在metastore_db中在我的项目目录中,而不是在我的hdfs://:9000/user/hive/warehouse中,所以如果我删除metastore_db数据就会丢失。conf/hive-site.xmljavax.jdo.option.ConnectionURLjdbc:mysql://saurab:3306/metastore

maven - 奥齐 : Could not resolve dependencies for project org. Apache .奥齐 :oozie-sharelib-oozie:jar:4. 0.1

我在尝试构建oozie时遇到错误。Hadoop版本:Hadoop2.4.0JDK:1.8我使用这个命令来运行oozie:./mkdistro.sh-DskipTests运行上面的代码会出现以下错误:我不确定发生了什么问题。[INFO]ReactorSummary:[INFO][INFO]ApacheOozieMain.................................SUCCESS[3.519s][INFO]ApacheOozieClient...............................SUCCESS[1:27.702s][INFO]ApacheOozie

hadoop - Apache pig -错误 2229 : Couldn't find matching uid -1 for project

运行Pig脚本时出现以下异常。ERROR2229:Couldn'tfindmatchinguid-1forproject(Name:ProjectType:bytearrayUid:-1Input:0Column:12)org.apache.pig.impl.logicalLayer.FrontendException:ERROR2000:ErrorprocessingruleColumnMapKeyPrune.Try-tColumnMapKeyPruneatorg.apache.pig.newplan.optimizer.PlanOptimizer.optimize(PlanOpti

hadoop - "Hadoop-Solr Lucidworks Project"检索输入名称路径

我正在使用这个项目:https://github.com/lucidworks/hadoop-solr有谁知道在哪个值中保存了正在处理的文档的名称(或路径)。我想将此值检索到SolrAdmin(将一个字段及其名称添加到我的架构中)。这可能吗?示例:我希望能够看到文档的名称,查询从中返回相同的结果。我正在使用此命令运行项目:hadoopjarsolr-hadoop-job-2.2.5.jarcom.lucidworks.hadoop.ingest.IngestJob-Dlww.commit.on.close=true-DcsvDelimiter=-clscom.lucidworks.ha

hadoop - pig : Invalid field Projection; Projected Field does not exist

describefilter_records;这给了我以下格式:filter_records:{details1:(firstname:chararray,lastname:chararray,age:int,gender:chararray),details2:(firstname:chararray,lastname:chararray,age:int,gender:chararray)}我想显示details1和details2中的firstname。我试过这个:display_records=FOREACHfilter_recordsGENERATEdisplay1.first

php - Symfony2 : what Symfony git repository can I use to start a project?

你能给我一些关于如何创建新的Symfony2项目的信息吗?我开始从github获取symfony/symfony-sandbox作为tar-ball。然后我删除了它旧的src/vendor内容。我使用git子模块获取最新的供应商库。(fabpot/Symfony、学说、迁移……)。问题是与最新的fabpot/Symfony代码相比,沙箱似乎过时了。所以我开始修改更改的内容(FoundationBundle重命名,一些方法签名更改(如registerContainerConfiguration,...)。我仍然得到这个错误:Symfony\Components\HttpKernel\Ex

php - 在 Google API v2 中,为什么会发生错误 "The project id used to call the Google Play Developer API has not been linked"?

当我使用GoogleAPIv2时,获取一个inapplisting,我在进行API调用时遇到以下错误:{"error":{"errors":[{"domain":"androidpublisher","reason":"projectNotLinked","message":"TheprojectidusedtocalltheGooglePlayDeveloperAPIhasnotbeenlinkedintheGooglePlayDeveloperConsole."}],"code":403,"message":"TheprojectidusedtocalltheGooglePlayD

php - Project Euler #19 代码似乎是正确的。我错过了什么?

问题19:Youaregiventhefollowinginformation,butyoumayprefertodosomeresearchforyourself.1Jan1900wasaMonday.ThirtydayshasSeptember,April,JuneandNovember.Alltheresthavethirty-one,SavingFebruaryalone,Whichhastwenty-eight,rainorshine.Andonleapyears,twenty-nine.Aleapyearoccursonanyyearevenlydivisibleby4,b

php - Composer : List Project Scripts and Plugins?

composer是否有任何内置的方式来显示当前项目中的插件列表?或者是通过vendor中的composer.json文件查找Composer插件的唯一选择,例如$findvendor-namecomposer.json|xargsgrep-i-r'composer-plugin' 最佳答案 由于Composer插件必须需要composer-plugin-api包(参见Composerdocumentation),您可以使用此命令列出插件:composerdependscomposer-plugin-api此处有更多详细信息:http