我尝试使用i18n但它不起作用i18n在下面。http://beego.me/docs/module/i18n.mdrouters/init.go://Initializedlanguagetypelist.langs:=strings.Split(models.Cfg.MustValue("lang","types"),"|")names:=strings.Split(models.Cfg.MustValue("lang","names"),"|")langTypes=make([]*langType,0,len(langs))fori,v:=rangelangs{langTypes
我有以下字符串:-1,856,32,0,0,0.000000,0.0000000,0,0,137,0,0,0,1400,0,101,0,0,0,42,00,0,0,0,0,0,0,00,0,0,0,0,0,554,0-1,841,1,0,0,0.000000,0.0000000,0,0,163,0,0,0,1820,0,120,0,0,0,43,00,0,0,0,0,0,0,00,0,0,0,0,0,517,0然后我使用分隔符-1拆分它,这意味着将有一个由2个元素组成的数组(我们称它为array1)。现在,假设array1的第一个元素我想用\r\n再次拆分它,这将是一个数组(array