mooncatventures-group
全部标签 这是我的文档架构:{"_id":ObjectId("5203c8b91afdd7160c6ecfd3"),"answer_calls":"","start":"10:00","end":"10:30","VDN_name":"SP_SYNDICATED_7","total_calls":"1","date":"01/07/2013","abandoned_calls":"","voicemail_calls":""}我尝试通过聚合框架:>dir.aggregate([{$group:{_id:{fecha:"$date",hora:"$start"},llamadas:{$sum:"$
在下面的查询中{$group:{_id:{success:'$success',responseCode:'$responseCode',label:'$label'},max_timeStamp:{$timeStamp:1},count_responseCode:{$sum:1},avg_value:{$sum:"$value"},count_success:{$sum:1}}}_id:{success:'$success',responseCode:'$responseCode',label:'$label'},如何翻译成在javamongodb驱动中使用。我试过了BasicDBL
我有以下文档结构{"app_id":"DHJFK67JDSJjdasj909","date":ISODate("2014-08-07T00:00:00.000Z"),"event_count":100,"events":[{"type":0,"value":12},{"type":10,"value":24},{"type":20,"value":36},{"type":30,"value":43}],"unique_events":[{"type":0,"value":5},{"type":10,"value":8},{"type":20,"value":12},{"type":30
我有两个系列。其中一个我希望添加对另一个的引用并在返回时填充它。这是我试图实现的示例json:{"title":"SomeTitle","uid":"some-title","created_at":"1412159926","updated_at":"1412159926","id":"1","metadata":{"date":"2016-10-17","description":"adescription"},"tags":[{"name":"Tag1","uid":"tag-1"},{"name":"Tag2","uid":"tag-2"},{"name":"Tag3","ui
(1)我已将以下内容添加到集合中:{"_id":1,"hitsPerOneSecond":[2,3,5,4,1,2,3,4,1,2],"startTime":ISODate("2012-04-07T10:41:33.380Z"),"returnCodeHits":{"300":5,"200":12},"xxxServer":"xxx:8100","statsSummarizedToSeconds":10,"pathStats_xxx_api_get_version":[0.2280779683225852,0.030849283020361273,0.9947690473370484]
这是我的查询,db.product.aggregate([{$match:{categoryID:4}},{"$group":{"_id":{"productID":"$productID","articleID":"$articleID","colour":"$colour","set&size":{"sku":"$skuID","size":"$size"},},}},{"$group":{"_id":{"productID":"$_id.productID","colour":"$_id.colour"},"size":{"$addToSet":{"sku":"$_id.set&
我使用mongodb2.6。我以这种形式存储了我的数据:{"_id":"my-sensor-1","points":[{"timeStamp":NumberLong("1453468362174"),"value":41},{"timeStamp":NumberLong("1453468483297"),"value":66},{"timeStamp":NumberLong("1453468485568"),"value":49},...]}为了聚合文档,我进行如下查询:db.pointsTest.aggregate([{$match:{$and:[{"points.timeStamp
我正在使用一个脚本来删除mongo上的重复项,它在一个包含10个项目的集合中工作,我将其用作测试,但是当我用于包含600万个文档的真实集合时,我得到了一个错误。这是我在Robomongo中运行的脚本(现在称为Robo3T):varbulk=db.getCollection('RAW_COLLECTION').initializeOrderedBulkOp();varcount=0;db.getCollection('RAW_COLLECTION').aggregate([//Grouponuniquevaluestoring_idvaluestoarrayandcount{"$grou
我正在使用一个脚本来删除mongo上的重复项,它在一个包含10个项目的集合中工作,我将其用作测试,但是当我用于包含600万个文档的真实集合时,我得到了一个错误。这是我在Robomongo中运行的脚本(现在称为Robo3T):varbulk=db.getCollection('RAW_COLLECTION').initializeOrderedBulkOp();varcount=0;db.getCollection('RAW_COLLECTION').aggregate([//Grouponuniquevaluestoring_idvaluestoarrayandcount{"$grou
在mongodb聚合调用中,如何使用$group运算符将管道中的所有文档分组为单个结果?假设我有一个如下所示的记录集合:{user_id:234,signup_date:2013-06-27}我想使用聚合函数在数据库中查询在给定日期范围内注册的用户列表,并将其作为列表返回。我想要一个看起来像这样的结果:{users:[234,235,236]}我的查询如下所示:db.users.aggregate([{$match:{signup_date:{$gte:date_begin_variable,$lt:date_end_variable}},到目前为止,一切都很好。我现在有一个记录子集,