我有一个只用float填充的Python列表:list_num=[0.41,0.093,0.002,1.59,0.0079,0.080,0.375]我需要将此列表四舍五入以获得:list_num_rounded=[0.4,0.09,0.002,1.5,0.007,0.08,0.3]问题:将1.59四舍五入到1.5很容易做到。但是,我的问题是float小于1。问题:基本上,我需要将所有float向下舍入,以便:如果float尝试:这是我尝试过的:list_num_rounded=[]foreleminlist_num:ifelem>0.01andelem0.001andelem0.1:l
我的程序在尝试将字符串从字符串列表转换为float时出错。该列表从CSV文本文件中的一行读取,然后分成一个列表。我如何进行这项工作,为什么会出错?以下是相关的代码:defMain():srcf=open(bkp,'r')forlineinsrcf:liLn=line.split(',')...然后调用下面的函数...defPred_PSME(liLn):dbh=float(liLn[6])这是文件中的行:1345327,20486,"ABCO","冷杉","Y","Y","31.496","0.0779","19.3567","0.5602","0",1,"0.9268","11.89
我有以下Pandas数据框:importpandasaspdimportnumpyasnpdf=pd.DataFrame({"first_column":[0,0,0,1,1,1,0,0,1,1,0,0,0,0,1,1,1,1,1,0,0]})>>>dffirst_column00102031415160708191100110120130141151161171181190200first_column是0和1的二进制列。有连续的“集群”,它们总是成对出现,至少有两个。我的目标是创建一个“计算”每组行数的列:>>>dffirst_columncounts000100200313413
我有如下数据列表:[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,747,752,753,754,755,756,757,758,759,760,761,762,763,764,765,766,767,768,769,770,771,772,773,774,775,776,777,778,779,780,781,782,783,784,785,786,787,788,