草庐IT

prio_lock

全部标签

go - 为什么在 Go 中锁定比 Java 慢得多?很多时间花在 Mutex.Lock() Mutex.Unlock()

我编写了一个小型Go库(go-patan),用于收集某些变量的运行最小值/最大值/平均值/标准偏差。我将它与等效的Java实现(patan)进行了比较,令我惊讶的是Java实现要快得多。我想明白为什么。该库基本上由一个简单的数据存储和一个序列化读取和写入的锁组成。这是代码片段:typeStorestruct{durationsmap[string]*Distributioncountersmap[string]int64samplesmap[string]*Distributionlock*sync.Mutex}func(store*Store)addSample(keystring,

Caused by: java.lang.IllegalStateException: failed to obtain node locks, tri

我的情况是生产环境中,elasticsearch突然崩溃,然后起不来了。我的日志目录在vim/var/log/elasticsearch/my-elk-cluster.log日志信息为Causedby:java.lang.IllegalStateException:failedtoobtainnodelocks,tried[[/data/elk_data/my-elk-cluster]]withlockid[0];maybetheselocationsarenotwritableormultiplenodeswerestartedwithoutincreasing[node.max_local

go - 对 Go 中的 Locks/Mutex 感到困惑

我正在尝试构建map。通常所有读取都可以并行完成,除非写入时,所有读取都需要锁定。我以为我了解Mutex在go中的工作原理,但显然我不了解。我首先尝试使用RWMutex写锁:typepersonstruct{sync.RWMutexageint}funcmain(){a:=person{age:3}fmt.Println(a.age)gofunc(){a.Lock()time.Sleep(5*time.Second)a.age=4fmt.Println(a.age)a.Unlock()}()fmt.Println(a.age)fmt.Println("main",a.age)time.

go - 对 Go 中的 Locks/Mutex 感到困惑

我正在尝试构建map。通常所有读取都可以并行完成,除非写入时,所有读取都需要锁定。我以为我了解Mutex在go中的工作原理,但显然我不了解。我首先尝试使用RWMutex写锁:typepersonstruct{sync.RWMutexageint}funcmain(){a:=person{age:3}fmt.Println(a.age)gofunc(){a.Lock()time.Sleep(5*time.Second)a.age=4fmt.Println(a.age)a.Unlock()}()fmt.Println(a.age)fmt.Println("main",a.age)time.

docker启动es报错:failed to obtain node locks...

在学习es时,使用docker启动时发现一直报错:java.lang.IllegalStateException:failedtoobtainnodelocks,tried[[/usr/share/elasticsearch/data]]withlockid[0];maybetheselocationsarenotwritableormultiplenodeswerestartedwithoutincreasing[node.max_local_storage_nodes](was[1])?Likelyrootcause:java.nio.file.AccessDeniedException:

关于Elasticsearch 报错failed to obtain node locks....

在学习Elasticsearch的时候出现了一下错误:版本:7.12.1java.lang.IllegalStateException:failedtoobtainnodelocks,tried[[/usr/share/elasticsearch/data]]withlockid[0];maybetheselocationsarenotwritableormultiplenodeswerestartedwithoutincreasing[node.max_local_storage_nodes](was[1])?主要解决方法主要原因有三种:1、进程冲突:通过ps-aux|grepelastic

dictionary - golang struct concurrent read and write without Lock 也运行ok?

concurrentMap()函数有WARNING:DATARACE,和fatalerror:concurrentmapreadandmapwriteconcurrentStruct()有警告:数据竞争,但运行正常为什么struct可以DATARACE?packagemainimport("sync")funcmain(){//concurrentMap()concurrentStruct()//concurrentStructWithMuLock()}typeMetadatastruct{musync.RWMutex//?keybool}//concurrentStruct并发操作结

dictionary - golang struct concurrent read and write without Lock 也运行ok?

concurrentMap()函数有WARNING:DATARACE,和fatalerror:concurrentmapreadandmapwriteconcurrentStruct()有警告:数据竞争,但运行正常为什么struct可以DATARACE?packagemainimport("sync")funcmain(){//concurrentMap()concurrentStruct()//concurrentStructWithMuLock()}typeMetadatastruct{musync.RWMutex//?keybool}//concurrentStruct并发操作结

go - sync.Mutex.Lock 是 FIFO 吗?

如果很多线程锁定在mutex上它们是按FIFO顺序排队,还是goroutine在解锁时获取锁有一定的随机性? 最佳答案 来自source://Mutexfairness.////Mutexcanbein2modesofoperations:normalandstarvation.//InnormalmodewaitersarequeuedinFIFOorder,butawokenupwaiter//doesnotownthemutexandcompeteswithnewarrivinggoroutinesover//theowner

go - sync.Mutex.Lock 是 FIFO 吗?

如果很多线程锁定在mutex上它们是按FIFO顺序排队,还是goroutine在解锁时获取锁有一定的随机性? 最佳答案 来自source://Mutexfairness.////Mutexcanbein2modesofoperations:normalandstarvation.//InnormalmodewaitersarequeuedinFIFOorder,butawokenupwaiter//doesnotownthemutexandcompeteswithnewarrivinggoroutinesover//theowner