什么是最优雅的做法'string'=>['s','st','str','stri','strin','string']我一直在想一个类轮，但我不能完全做到。欢迎任何解决方案，谢谢。 最佳答案 这个怎么样？s='string'res=s.length.times.map{|len|s[0..len]}res#=>["s","st","str","stri","strin","string"] 关于ruby-'string'到['s','st','str','stri','strin','s

最近在使用httpclient进行post时远程接口发生报错报错信息：org.springframework.http.converter.HttpMessageNotReadableException:JSONparseerror:Unrecognizedtoken'Alarm':wasexpecting(JSONString,Number,Array,Objectortoken'null','true'or'false');nestedexceptioniscom.fasterxml.jackson.core.JsonParseException:Unrecognizedtoken'Ala