title:2022年上海市大学生程序设计竞赛个人题解date:2022-10-19tags:ACM,题解author:Linno2022年上海市大学生程序设计竞赛个人题解题目链接:https://ac.nowcoder.com/acm/contest/41614补题进度:6/14A-AnotherA+BProblem因为只有6个位置是空的,直接枚举10610^6106种情况判字符串是否可行即可。#includeusingnamespacestd;stringE,C;stringss[]={"0","1","2","3","4","5","6","7","8","9"};intex[20],n