我正在尝试根据 official api docs 注册一个 Office365 Api webhook .我在 postman 中试过了，一切都按预期工作。

Java 版本:1.7(我知道...)

我正在使用 Play 框架版本 1.2.7.2

HttpClient: org.apache.http.client.HttpClient

相关文档:

The subscription process goes as follows:

A client app makes a subscription request (POST) for a specific resource. It includes a notification URL, among other properties.

The Outlook notifications service tries to validate the notification URL with the listener service. It includes a validation token in the validation request.

If the listener service successfully validates the URL, it returns a success response within 5 seconds as follows:

Sets the content type in the response header to text\plain. Includes the same validation token in the response body. Returns an HTTP 200 response code. The listener can discard the validation token subsequently. Depending on the URL validation result, the Outlook notifications service sends a response to the client app:

If URL validation was successful, the service creates the subscription with a unique subscription ID and sends the response to the client. If URL validation was unsuccessful, the service sends an error response with an error code and other details. Upon receiving a successful response, the client app stores the subscription ID to correlate future notifications with this subscription.

postman 请求:

两个请求都被wireshark拦截了:

postman :

Ý`!Ë2@ʸ1cÊþßV:
ðîPOST /api/v2.0/me/subscriptions HTTP/1.1
Content-Type: application/json
cache-control: no-cache
Postman-Token: a24df796-c49e-4245-a1cf-0949cd6538b6
Authorization: Bearer ###
User-Agent: PostmanRuntime/7.4.0
Accept: */*
Host: localhost:3000
accept-encoding: gzip, deflate
content-length: 430
Connection: keep-alive

{
    "@odata.type":"#Microsoft.OutlookServices.PushSubscription",
    "ChangeType": "Created, Deleted, Updated",
    "ClientState": "some-token",
    "NotificationURL": "https://###/office365/receive.php?subId=5",
    "Resource": "https://outlook.office.com/api/v2.0/me/Calendars('###')/events"
}

(在 wireshark 中捕获)(### 部分已删除信息，我确保 auth 和 ids 匹配)

在 ###/office365/receive.php 处有一个 php 脚本，它只是回显 $_GET['validationtoken']。这在 Postman 中非常有效。

在 Java 中，我创建了一个具有相同 header 和相同正文的请求

E/@@5â$¸³zêð-gÄV$
Là¼Là¼POST /api/v2.0/me/subscriptions HTTP/1.1
Accept: */*
Content-Type: application/json
Authorization: Bearer ###
Content-Length: 476
Host: localhost:3000
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.5.2 (Java/1.7.0_80)
Accept-Encoding: gzip,deflate

{
    "@odata.type":"#Microsoft.OutlookServices.PushSubscription",
    "ChangeType": "Created, Deleted, Updated",
    "ClientState": "1fdb3e372212622e0b7e68abe09e1201a81a8bcc040cce9a6f013f71a09bfbe1",
    "NotificationURL": "https://###/office365/receive.php",
    "Resource": "https://outlook.office.com/api/v2.0/me/Calendars('###')/events"
}

我验证了请求的所有(重要)部分完全相同。

我的 java 代码有点复杂，无法在此处完整分享，但重要的部分是:

// build url
private final RequestBuilder getRequest (String url) {
    RequestBuilder req  = RequestBuilder.create(getMethod()); // e.g. POST
    req.setUri(overwriteBaseUrl(url) + getPath());

    // headers is a hashmap<String, String>
    for (String key: headers.keySet()) {
        req.setHeader(key, headers.get(key));
    }

    // set body (handle empty cases)
    String body = getBody();
    if (body == null) {
        body = "";
    }

    req.setEntity(new StringEntity(body, "UTF-8"));

    return req;
}

public void send (HttpClient client, Office365Credentials cred, String url) throws IOException, InvalidCrmCredentialsException, MalformedResponseException {
    // creates request (with headers, body, etc)
    RequestBuilder req = getRequest(url);
    // adds auth
    addAuthHeaderToRequest(cred, req);

    // execute the request
    Response response;
    try {
         response = new Response(client.execute(req.build()));
    } catch (ConnectionPoolTimeoutException e) {
        // The 10 second limit has passed
        throw new MalformedResponseException("Response missing (response timed out)!", e);
    }

    // check for 401, not authorized
    if (response.getStatus() == 401) {
        throw new InvalidCrmCredentialsException("401 - Not authorized! " + req.getUri().toString());
    }

    // process response
    processResponse(response);
}

HttpClient 的构造如下:

    int CONNECTION_TIMEOUT_MS = 10 * 1000; // 10 second timeout
    RequestConfig requestConfig = RequestConfig.custom()
            .setConnectionRequestTimeout(CONNECTION_TIMEOUT_MS)
            .setConnectTimeout(CONNECTION_TIMEOUT_MS)
            .setSocketTimeout(CONNECTION_TIMEOUT_MS)
            .build();

    client = HttpClientBuilder.create().setDefaultRequestConfig(requestConfig).build();

无论我设置多高的限制，我都得不到响应，office api。甚至没有错误响应。

TL;DR:我的请求在 postman 中工作正常，在 Java 中完全相同的请求超时(无论超时长度如何)

最佳答案

问题是，org.apache.http.client.HttpClient 不是线程安全的(至少对于 play framework 1.2.7 而言)。由于 play 框架重用线程，我最好的猜测是，它从未收到答案(因为 webhook 注册请求比正常请求花费的时间稍长)。

我切换到 WS，play 框架本身提供的 http 客户端。这样做的缺点是它对所有 http 动词的支持有限。

新方法如下所示:

private final WS.WSRequest getRequest (String url) {
    WS.WSRequest req = WS.url(overwriteBaseUrl(url) + getPath());

    for (String key: headers.keySet()) {
        req.setHeader(key, headers.get(key));
    }

    String body = getBody();
    if (body == null) {
        body = "";
    }

    req.body(body);

    return req;
}

public void send (WSMockableSender client, Office365Credentials cred, String url) throws IOException, InvalidCrmCredentialsException, MalformedResponseException {

    WS.WSRequest req = getRequest(url);
    addAuthHeaderToRequest(cred, req);

    // execute the request
    WSResponse response;
    response = new WSResponse(client.post(req));

    System.out.println("Response received!");

    // check for 401, not authorized
    if (response.getStatus() == 401) {
        throw new InvalidCrmCredentialsException("401 - Not authorized! " + req.url);
    }

    processResponse(response);
}

关于java - 在 Java Apache 中相同的请求超时，在 postman 中工作正常，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/53194046/