我想通过php显示mysql数据库中的用户详细信息,并在android textview中显示。场景是这样的:当用户登录到他的帐户时,他将被重定向到包含 4 个按钮的仪表板,即:newsfeed、profile、calendar 和 about。当用户单击个人资料按钮时,用户详细信息(如他的姓氏、名字、中间名等)将显示在 TextView 中。当我运行我的应用程序时,它不显示任何内容,但在我的 php 脚本中它返回用户详细信息。这里似乎有什么问题?
这是我的java代码:
package sscr.stag;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.app.ProgressDialog;
import android.content.SharedPreferences;
import android.os.AsyncTask;
import android.os.Bundle;
import android.preference.PreferenceManager;
import android.util.Log;
import android.widget.TextView;
public class AdProfile extends Activity {
// All xml labels
TextView txtFname;
TextView txtMname;
TextView txtLname;
// Progress Dialog
private ProgressDialog pDialog;
// Creating JSON Parser object
JSONParser jsonParser = new JSONParser();
// Profile json object
JSONArray user;
JSONObject hay;
// Profile JSON url
private static final String PROFILE_URL ="http://www.stagconnect.com/StagConnect/admin/TestProfile.php";
// ALL JSON node names
private static final String TAG_PROFILE = "user";
// private static final String TAG_ID = "id";
private static final String TAG_USERNAME = "username";
private static final String TAG_FIRSTNAME = "first_name";
private static final String TAG_MIDDLENAME = "middle_initial";
private static final String TAG_LASTNAME = "last_name";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.adminprofile);
txtFname = (TextView) findViewById(R.id.fname);
txtMname = (TextView) findViewById(R.id.mname);
txtLname = (TextView) findViewById(R.id.lname);
// Loading Profile in Background Thread
new LoadProfile().execute();
}
class LoadProfile extends AsyncTask<String, String, String> {
public void test(){
hay = new JSONObject();
// Storing each json item in variable
try {
String firstname = hay.getString(TAG_FIRSTNAME);
String middlename = hay.getString(TAG_MIDDLENAME);
String lastname = hay.getString(TAG_LASTNAME);
// displaying all data in textview
txtFname.setText("Firstname: " + firstname);
txtMname.setText("Middle Name: " + middlename);
txtLname.setText("Last Name " + lastname);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(AdProfile.this);
pDialog.setMessage("Loading profile ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(false);
pDialog.show();
}
/**
* getting Profile JSON
* */
protected String doInBackground(String... args) {
// Building Parameters
SharedPreferences sp = PreferenceManager.getDefaultSharedPreferences(AdProfile.this);
String post_username = sp.getString("username", "anon");
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", post_username));
// getting JSON string from URL
JSONObject json = jsonParser.makeHttpRequest(PROFILE_URL, "POST",
params);
// Check your log cat for JSON reponse
Log.d("Profile JSON: ", json.toString());
try {
// profile json object
user = json.getJSONArray(TAG_PROFILE);
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
protected void onPostExecute(String file_url) {
// dismiss the dialog after getting all products
pDialog.dismiss();
// updating UI from Background Thread
test();
}
}
}
这是我的 php 脚本:
<?php
require('admin.config.inc.php');
if (!empty($_POST)) {
//initial query
$query = "Select last_name, first_name, middle_initial, designation FROM admin where username = :user";
$query_params = array(':user' => $_POST['username']);
//execute query
try {
$stmt = $db -> prepare($query);
$result = $stmt -> execute($query_params);
} catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error!";
die(json_encode($response));
}
// Finally, we can retrieve all of the found rows into an array using fetchAll
$rows = $stmt -> fetchAll();
if ($rows) {
$response["success"] = 1;
$response["message"] = "Post Available!";
$response["user"] = array();
foreach($rows as $row) {
$user = array();
$user["designation"] = $row["designation"];
$user["middlename"] = $row["middle_initial"];
$user["firstname"] = $row["first_name"];
$user["lastname"] = $row["last_name"];
//update our repsonse JSON data
array_push($response["user"], $user);
}
// echoing JSON response
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No user available!";
die(json_encode($response));
}
} else {}
?>
<form action="TestProfile.php" method="POST">
Username: <input type="text" name="username">
<input type="submit" value="Submit">
</form>
这是我的 php 脚本的输出(JSON 响应):
{"success":1,"message":"Post Available!","user":[{"designation":"Student Affairs Office in charge","middlename":"","firstname":"test","lastname":"test"}]}
最佳答案
这是json对象
JSONObject json = jsonParser.makeHttpRequest(PROFILE_URL, "POST",
params);
需要在doInbackground中返回json。返回的结果是 onPostExecute
然后
test(json);
然后在测试中你可以解析json
编辑:
你还需要改变
AsyncTask<String, String, String>
到
AsyncTask<String, String, JSONObject>
然后
protected JSONObject doInBackground(String... args) {
JSONObject json=null;
// Building Parameters
SharedPreferences sp = PreferenceManager.getDefaultSharedPreferences(AdProfile.this);
String post_username = sp.getString("username", "anon");
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", post_username));
// getting JSON string from URL
json = jsonParser.makeHttpRequest(PROFILE_URL, "POST",
params);
// Check your log cat for JSON reponse
Log.d("Profile JSON: ", json.toString());
try {
// profile json object
user = json.getJSONArray(TAG_PROFILE);
} catch (JSONException e) {
e.printStackTrace();
}
return json;
}
然后在onPostExecute
@Override
protected void onPostExecute(JSONObject result) {
super.onPOstExecute(result);
// dismiss the dialog after getting all products
pDialog.dismiss();
// updating UI from Background Thread
test(result);
}
在测试
public void test(JSONObject response){
{
// parse response here and set text to textview
}
或者
你在doInbackgrond中解析在onPostExecute中更新textview吗
编辑:
代码:
public class AddProfile extends Activity {
// All xml labels
TextView txtFname;
TextView txtMname;
TextView txtLname;
// Progress Dialog
private ProgressDialog pDialog;
// Profile json object
JSONArray user;
JSONObject hay;
// Profile JSON url
private static final String PROFILE_URL = "http://www.stagconnect.com/StagConnect/admin/TestProfile.php";
// ALL JSON node names
private static final String TAG_PROFILE = "user";
// private static final String TAG_ID = "id";
private static final String TAG_USERNAME = "username";
private static final String TAG_FIRSTNAME = "first_name";
private static final String TAG_MIDDLENAME = "middle_initial";
private static final String TAG_LASTNAME = "last_name";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.adminprofile);
txtFname = (TextView) findViewById(R.id.fname);
txtMname = (TextView) findViewById(R.id.lname);
txtLname = (TextView) findViewById(R.id.mname);
// Loading Profile in Background Thread
new LoadProfile().execute();
}
class LoadProfile extends AsyncTask<String, String, String> {
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(AddProfile.this);
pDialog.setMessage("Loading profile ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(false);
pDialog.show();
}
/**
* getting Profile JSON
* */
protected String doInBackground(String... args) {
// Building Parameters
String json = null;
try {
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", "admin"));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(PROFILE_URL);
httppost.setEntity(new UrlEncodedFormEntity(params));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
json = EntityUtils.toString(resEntity);
Log.i("Profile JSON: ", json.toString());
} catch (Exception e) {
e.printStackTrace();
}
return json;
}
@Override
protected void onPostExecute(String json) {
super.onPostExecute(json);
// dismiss the dialog after getting all products
pDialog.dismiss();
try
{
hay = new JSONObject(json);
JSONArray user = hay.getJSONArray("user");
JSONObject jb= user.getJSONObject(0);
String firstname = jb.getString("firstname");
String middlename = jb.getString("middlename");
String lastname = jb.getString("lastname");
// displaying all data in textview
txtFname.setText("Firstname: " + firstname);
txtMname.setText("Middle Name: " + middlename);
txtLname.setText("Last Name " + lastname);
}catch(Exception e)
{
e.printStackTrace();
}
}
}
}
json
{ // json object node
"success": 1,
"message": "Post Available!",
"user": [ // json array user
{ // json object node
"designation": "Student Affairs Office in-charge",
"middlename": "",
"firstname": "Jose Patrick",
"lastname": "Ocampo"
}
]
}
浏览器截图
关于android - 通过json在textview中显示数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21093869/
我得到了一个包含嵌套链接的表单。编辑时链接字段为空的问题。这是我的表格:Editingkategori{:action=>'update',:id=>@konkurrancer.id})do|f|%>'Trackingurl',:style=>'width:500;'%>'Editkonkurrence'%>|我的konkurrencer模型:has_one:link我的链接模型:classLink我的konkurrancer编辑操作:defedit@konkurrancer=Konkurrancer.find(params[:id])@konkurrancer.link_attrib
我主要使用Ruby来执行此操作,但到目前为止我的攻击计划如下:使用gemsrdf、rdf-rdfa和rdf-microdata或mida来解析给定任何URI的数据。我认为最好映射到像schema.org这样的统一模式,例如使用这个yaml文件,它试图描述数据词汇表和opengraph到schema.org之间的转换:#SchemaXtoschema.orgconversion#data-vocabularyDV:name:namestreet-address:streetAddressregion:addressRegionlocality:addressLocalityphoto:i
尝试通过RVM将RubyGems升级到版本1.8.10并出现此错误:$rvmrubygemslatestRemovingoldRubygemsfiles...Installingrubygems-1.8.10forruby-1.9.2-p180...ERROR:Errorrunning'GEM_PATH="/Users/foo/.rvm/gems/ruby-1.9.2-p180:/Users/foo/.rvm/gems/ruby-1.9.2-p180@global:/Users/foo/.rvm/gems/ruby-1.9.2-p180:/Users/foo/.rvm/gems/rub
我正在使用puppet为ruby程序提供一组常量。我需要提供一组主机名,我的程序将对其进行迭代。在我之前使用的bash脚本中,我只是将它作为一个puppet变量hosts=>"host1,host2"我将其提供给bash脚本作为HOSTS=显然这对ruby不太适用——我需要它的格式hosts=["host1","host2"]自从phosts和putsmy_array.inspect提供输出["host1","host2"]我希望使用其中之一。不幸的是,我终其一生都无法弄清楚如何让它发挥作用。我尝试了以下各项:我发现某处他们指出我需要在函数调用前放置“function_”……这
我正在编写一个gem,我必须在其中fork两个启动两个webrick服务器的进程。我想通过基类的类方法启动这个服务器,因为应该只有这两个服务器在运行,而不是多个。在运行时,我想调用这两个服务器上的一些方法来更改变量。我的问题是,我无法通过基类的类方法访问fork的实例变量。此外,我不能在我的基类中使用线程,因为在幕后我正在使用另一个不是线程安全的库。所以我必须将每个服务器派生到它自己的进程。我用类变量试过了,比如@@server。但是当我试图通过基类访问这个变量时,它是nil。我读到在Ruby中不可能在分支之间共享类变量,对吗?那么,还有其他解决办法吗?我考虑过使用单例,但我不确定这是
在我的Controller中,我通过以下方式在我的index方法中支持HTML和JSON:respond_todo|format|format.htmlformat.json{renderjson:@user}end在浏览器中拉起它时,它会自然地以HTML呈现。但是,当我对/user资源进行内容类型为application/json的curl调用时(因为它是索引方法),我仍然将HTML作为响应。如何获取JSON作为响应?我还需要说明什么? 最佳答案 您应该将.json附加到请求的url,提供的格式在routes.rb的路径中定义。这
我的最终目标是安装当前版本的RubyonRails。我在OSXMountainLion上运行。到目前为止,这是我的过程:已安装的RVM$\curl-Lhttps://get.rvm.io|bash-sstable检查已知(我假设已批准)安装$rvmlistknown我看到当前的稳定版本可用[ruby-]2.0.0[-p247]输入命令安装$rvminstall2.0.0-p247注意:我也试过这些安装命令$rvminstallruby-2.0.0-p247$rvminstallruby=2.0.0-p247我很快就无处可去了。结果:$rvminstall2.0.0-p247Search
所以我在关注Railscast,我注意到在html.erb文件中,ruby代码有一个微弱的背景高亮效果,以区别于其他代码HTML文档。我知道Ryan使用TextMate。我正在使用SublimeText3。我怎样才能达到同样的效果?谢谢! 最佳答案 为SublimeText安装ERB包。假设您安装了SublimeText包管理器*,只需点击cmd+shift+P即可获得命令菜单,然后键入installpackage并选择PackageControl:InstallPackage获取包管理器菜单。在该菜单中,键入ERB并在看到包时选择
我在理解Enumerator.new方法的工作原理时遇到了一些困难。假设文档中的示例:fib=Enumerator.newdo|y|a=b=1loopdoy[1,1,2,3,5,8,13,21,34,55]循环中断条件在哪里,它如何知道循环应该迭代多少次(因为它没有任何明确的中断条件并且看起来像无限循环)? 最佳答案 Enumerator使用Fibers在内部。您的示例等效于:require'fiber'fiber=Fiber.newdoa=b=1loopdoFiber.yieldaa,b=b,a+bendend10.times.m
我试图在索引页中创建一个超链接,但它没有显示,也没有给出任何错误。这是我的index.html.erb代码。ListingarticlesTitleTextssss我检查了我的路线,我认为它们也没有问题。PrefixVerbURIPatternController#Actionwelcome_indexGET/welcome/index(.:format)welcome#indexarticlesGET/articles(.:format)articles#indexPOST/articles(.:format)articles#createnew_articleGET/article