草庐IT

python - 带有可拖动点的可拖动线

coder 2023-08-23 原文

我需要在 figureCanvas 中有 2 个可拖动点。但是我有一个补充约束:这 2 个点必须用一条线连接起来。 当我拖动一个点时,当然(否则它不会很有趣),必须动态绘制线,并且仍然链接到 2 个点。

我设法创建了 2 个可拖动点,主题如下: Matplotlib drag overlapping points interactively

我修改了一些代码以通过 FigureCanvas 的子类使用它(稍后将图形包含在 PyQt 应用程序中):

import matplotlib.pyplot as plt
import matplotlib.patches as patches


class DraggablePoint:

    # https://stackoverflow.com/questions/21654008/matplotlib-drag-overlapping-points-interactively

    lock = None #  only one can be animated at a time

    def __init__(self, parent, x=0.1, y=0.1):

        self.parent = parent
        self.point = patches.Ellipse((x, y), 0.01, 0.03, fc='r', alpha=0.5)
        self.x = x
        self.y = y
        parent.fig.axes[0].add_patch(self.point)
        self.press = None
        self.background = None
        self.connect()


    def connect(self):

        'connect to all the events we need'

        self.cidpress = self.point.figure.canvas.mpl_connect('button_press_event', self.on_press)
        self.cidrelease = self.point.figure.canvas.mpl_connect('button_release_event', self.on_release)
        self.cidmotion = self.point.figure.canvas.mpl_connect('motion_notify_event', self.on_motion)


    def on_press(self, event):

        if event.inaxes != self.point.axes: return
        if DraggablePoint.lock is not None: return
        contains, attrd = self.point.contains(event)
        if not contains: return
        self.press = (self.point.center), event.xdata, event.ydata
        DraggablePoint.lock = self

        # draw everything but the selected rectangle and store the pixel buffer
        canvas = self.point.figure.canvas
        axes = self.point.axes
        self.point.set_animated(True)
        canvas.draw()
        self.background = canvas.copy_from_bbox(self.point.axes.bbox)

        # now redraw just the rectangle
        axes.draw_artist(self.point)

        # and blit just the redrawn area
        canvas.blit(axes.bbox)


    def on_motion(self, event):

        if DraggablePoint.lock is not self:
            return
        if event.inaxes != self.point.axes: return
        self.point.center, xpress, ypress = self.press
        dx = event.xdata - xpress
        dy = event.ydata - ypress
        self.point.center = (self.point.center[0]+dx, self.point.center[1]+dy)

        canvas = self.point.figure.canvas
        axes = self.point.axes
        # restore the background region
        canvas.restore_region(self.background)

        # redraw just the current rectangle
        axes.draw_artist(self.point)

        # blit just the redrawn area
        canvas.blit(axes.bbox)


    def on_release(self, event):

        'on release we reset the press data'
        if DraggablePoint.lock is not self:
            return

        self.press = None
        DraggablePoint.lock = None

        # turn off the rect animation property and reset the background
        self.point.set_animated(False)
        self.background = None

        # redraw the full figure
        self.point.figure.canvas.draw()

        self.x = self.point.center[0]
        self.y = self.point.center[1]

    def disconnect(self):

        'disconnect all the stored connection ids'

        self.point.figure.canvas.mpl_disconnect(self.cidpress)
        self.point.figure.canvas.mpl_disconnect(self.cidrelease)
        self.point.figure.canvas.mpl_disconnect(self.cidmotion)

future 的图上只有 2 个点,我可以通过 self.parent 从类 DraggablePoint 访问另一个点。

我想我需要在 on_motion 函数中在两点之间画一条线。但我试过了,一无所获。 您知道如何实现这一目标吗?

最佳答案

好吧,我终于找到了解决方案。我把它贴在这里供可能需要它的人使用。这段代码基本上允许有 2 个由一条线链接的可拖动点。如果您移动其中一个点,则直线随之而来。在科学应用中建立基线非常有用。

import matplotlib.pyplot as plt
import matplotlib.patches as patches
from matplotlib.lines import Line2D


class DraggablePoint:

    # http://stackoverflow.com/questions/21654008/matplotlib-drag-overlapping-points-interactively

    lock = None #  only one can be animated at a time

    def __init__(self, parent, x=0.1, y=0.1, size=0.1):

        self.parent = parent
        self.point = patches.Ellipse((x, y), size, size * 3, fc='r', alpha=0.5, edgecolor='r')
        self.x = x
        self.y = y
        parent.fig.axes[0].add_patch(self.point)
        self.press = None
        self.background = None
        self.connect()

        if self.parent.list_points:
            line_x = [self.parent.list_points[0].x, self.x]
            line_y = [self.parent.list_points[0].y, self.y]

            self.line = Line2D(line_x, line_y, color='r', alpha=0.5)
            parent.fig.axes[0].add_line(self.line)


    def connect(self):

        'connect to all the events we need'

        self.cidpress = self.point.figure.canvas.mpl_connect('button_press_event', self.on_press)
        self.cidrelease = self.point.figure.canvas.mpl_connect('button_release_event', self.on_release)
        self.cidmotion = self.point.figure.canvas.mpl_connect('motion_notify_event', self.on_motion)


    def on_press(self, event):

        if event.inaxes != self.point.axes: return
        if DraggablePoint.lock is not None: return
        contains, attrd = self.point.contains(event)
        if not contains: return
        self.press = (self.point.center), event.xdata, event.ydata
        DraggablePoint.lock = self

        # draw everything but the selected rectangle and store the pixel buffer
        canvas = self.point.figure.canvas
        axes = self.point.axes
        self.point.set_animated(True)
        if self == self.parent.list_points[1]:
            self.line.set_animated(True)
        else:
            self.parent.list_points[1].line.set_animated(True)
        canvas.draw()
        self.background = canvas.copy_from_bbox(self.point.axes.bbox)

        # now redraw just the rectangle
        axes.draw_artist(self.point)

        # and blit just the redrawn area
        canvas.blit(axes.bbox)


    def on_motion(self, event):

        if DraggablePoint.lock is not self:
            return
        if event.inaxes != self.point.axes: return
        self.point.center, xpress, ypress = self.press
        dx = event.xdata - xpress
        dy = event.ydata - ypress
        self.point.center = (self.point.center[0]+dx, self.point.center[1]+dy)

        canvas = self.point.figure.canvas
        axes = self.point.axes
        # restore the background region
        canvas.restore_region(self.background)

        # redraw just the current rectangle
        axes.draw_artist(self.point)

        if self == self.parent.list_points[1]:
            axes.draw_artist(self.line)
        else:
            self.parent.list_points[1].line.set_animated(True)
            axes.draw_artist(self.parent.list_points[1].line)

        self.x = self.point.center[0]
        self.y = self.point.center[1]

        if self == self.parent.list_points[1]:
            line_x = [self.parent.list_points[0].x, self.x]
            line_y = [self.parent.list_points[0].y, self.y]
            self.line.set_data(line_x, line_y)
        else:
            line_x = [self.x, self.parent.list_points[1].x]
            line_y = [self.y, self.parent.list_points[1].y]

            self.parent.list_points[1].line.set_data(line_x, line_y)

        # blit just the redrawn area
        canvas.blit(axes.bbox)


    def on_release(self, event):

        'on release we reset the press data'
        if DraggablePoint.lock is not self:
            return

        self.press = None
        DraggablePoint.lock = None

        # turn off the rect animation property and reset the background
        self.point.set_animated(False)
        if self == self.parent.list_points[1]:
            self.line.set_animated(False)
        else:
            self.parent.list_points[1].line.set_animated(False)

        self.background = None

        # redraw the full figure
        self.point.figure.canvas.draw()

        self.x = self.point.center[0]
        self.y = self.point.center[1]

    def disconnect(self):

        'disconnect all the stored connection ids'

        self.point.figure.canvas.mpl_disconnect(self.cidpress)
        self.point.figure.canvas.mpl_disconnect(self.cidrelease)
        self.point.figure.canvas.mpl_disconnect(self.cidmotion)

更新:

如何在 PyQt5 中使用 DraggablePoint 类:

#!/usr/bin/python
# -*-coding:Utf-8 -*

import sys
import matplotlib
matplotlib.use("Qt5Agg")
from PyQt5 import QtWidgets, QtGui

from matplotlib.backends.backend_qt5agg import FigureCanvasQTAgg as FigureCanvas
from matplotlib.figure import Figure

# Personnal modules
from drag import DraggablePoint


class MyGraph(FigureCanvas):

    """A canvas that updates itself every second with a new plot."""

    def __init__(self, parent=None, width=5, height=4, dpi=100):

        self.fig = Figure(figsize=(width, height), dpi=dpi)
        self.axes = self.fig.add_subplot(111)

        self.axes.grid(True)

        FigureCanvas.__init__(self, self.fig)
        self.setParent(parent)

        FigureCanvas.setSizePolicy(self,
                                   QtWidgets.QSizePolicy.Expanding,
                                   QtWidgets.QSizePolicy.Expanding)
        FigureCanvas.updateGeometry(self)

        # To store the 2 draggable points
        self.list_points = []


        self.show()
        self.plotDraggablePoints([0.1, 0.1], [0.2, 0.2], [0.1, 0.1])


    def plotDraggablePoints(self, xy1, xy2, size=None):

        """Plot and define the 2 draggable points of the baseline"""

        # del(self.list_points[:])
        self.list_points.append(DraggablePoint(self, xy1[0], xy1[1], size))
        self.list_points.append(DraggablePoint(self, xy2[0], xy2[1], size))
        self.updateFigure()


    def clearFigure(self):

        """Clear the graph"""

        self.axes.clear()
        self.axes.grid(True)
        del(self.list_points[:])
        self.updateFigure()


    def updateFigure(self):

        """Update the graph. Necessary, to call after each plot"""

        self.draw()

if __name__ == '__main__':

    app = QtWidgets.QApplication(sys.argv)
    ex = MyGraph()
    sys.exit(app.exec_())

关于python - 带有可拖动点的可拖动线,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28001655/

有关python - 带有可拖动点的可拖动线的更多相关文章

  1. python - 如何使用 Ruby 或 Python 创建一系列高音调和低音调的蜂鸣声? - 2

    关闭。这个问题是opinion-based.它目前不接受答案。想要改进这个问题?更新问题,以便editingthispost可以用事实和引用来回答它.关闭4年前。Improvethisquestion我想在固定时间创建一系列低音和高音调的哔哔声。例如:在150毫秒时发出高音调的蜂鸣声在151毫秒时发出低音调的蜂鸣声200毫秒时发出低音调的蜂鸣声250毫秒的高音调蜂鸣声有没有办法在Ruby或Python中做到这一点?我真的不在乎输出编码是什么(.wav、.mp3、.ogg等等),但我确实想创建一个输出文件。

  2. Python 相当于 Perl/Ruby ||= - 2

    这个问题在这里已经有了答案:关闭10年前。PossibleDuplicate:Pythonconditionalassignmentoperator对于这样一个简单的问题表示歉意,但是谷歌搜索||=并不是很有帮助;)Python中是否有与Ruby和Perl中的||=语句等效的语句?例如:foo="hey"foo||="what"#assignfooifit'sundefined#fooisstill"hey"bar||="yeah"#baris"yeah"另外,类似这样的东西的通用术语是什么?条件分配是我的第一个猜测,但Wikipediapage跟我想的不太一样。

  3. java - 什么相当于 ruby​​ 的 rack 或 python 的 Java wsgi? - 2

    什么是ruby​​的rack或python的Java的wsgi?还有一个路由库。 最佳答案 来自Python标准PEP333:Bycontrast,althoughJavahasjustasmanywebapplicationframeworksavailable,Java's"servlet"APImakesitpossibleforapplicationswrittenwithanyJavawebapplicationframeworktoruninanywebserverthatsupportstheservletAPI.ht

  4. 华为OD机试用Python实现 -【明明的随机数】 2023Q1A - 2

    华为OD机试题本篇题目:明明的随机数题目输入描述输出描述:示例1输入输出说明代码编写思路最近更新的博客华为od2023|什么是华为od,od薪资待遇,od机试题清单华为OD机试真题大全,用Python解华为机试题|机试宝典【华为OD机试】全流程解析+经验分享,题型分享,防作弊指南华为o

  5. python - 如何读取 MIDI 文件、更改其乐器并将其写回? - 2

    我想解析一个已经存在的.mid文件,改变它的乐器,例如从“acousticgrandpiano”到“violin”,然后将它保存回去或作为另一个.mid文件。根据我在文档中看到的内容,该乐器通过program_change或patch_change指令进行了更改,但我找不到任何在已经存在的MIDI文件中执行此操作的库.他们似乎都只支持从头开始创建的MIDI文件。 最佳答案 MIDIpackage会为您完成此操作,但具体方法取决于midi文件的原始内容。一个MIDI文件由一个或多个音轨组成,每个音轨是十六个channel中任何一个上的

  6. 「Python|Selenium|场景案例」如何定位iframe中的元素? - 2

    本文主要介绍在使用Selenium进行自动化测试或者任务时,对于使用了iframe的页面,如何定位iframe中的元素文章目录场景描述解决方案具体代码场景描述当我们在使用Selenium进行自动化测试的时候,可能会遇到一些界面或者窗体是使用HTML的iframe标签进行承载的。对于iframe中的标签,如果直接查找是无法找到的,会抛出没有找到元素的异常。比如近在咫尺的例子就是,CSDN的登录窗体就是使用的iframe,大家可以尝试通过F12开发者模式查看到的tag_name,class_name,id或者xpath来定位中的页面元素,会抛出NoSuchElementException异常。解决

  7. python ffmpeg 使用 pyav 转换 一组图像 到 视频 - 2

    2022/8/4更新支持加入水印水印必须包含透明图像,并且水印图像大小要等于原图像的大小pythonconvert_image_to_video.py-f30-mwatermark.pngim_dirout.mkv2022/6/21更新让命令行参数更加易用新的命令行使用方法pythonconvert_image_to_video.py-f30im_dirout.mkvFFMPEG命令行转换一组JPG图像到视频时,是将这组图像视为MJPG流。我需要转换一组PNG图像到视频,FFMPEG就不认了。pyav内置了ffmpeg库,不需要系统带有ffmpeg工具因此我使用ffmpeg的python包装p

  8. Python 刷Leetcode题库,顺带学英语单词(31) - 2

    ValidPalindromeGivenastring,determineifitisapalindrome,consideringonlyalphanumericcharactersandignoringcases. [#125]Example:"Aman,aplan,acanal:Panama"isapalindrome."raceacar"isnotapalindrome.Haveyouconsiderthatthestringmightbeempty?Thisisagoodquestiontoaskduringaninterview.Forthepurposeofthisproblem

  9. python - 是否可以使用 Ruby 或 Python 禁用 anchor /引用来发出有效的 YAML? - 2

    是否可以在PyYAML或Ruby的Psych引擎中禁用创建anchor和引用(并有效地显式列出冗余数据)?也许我在网上搜索时遗漏了一些东西,但在Psych中似乎没有太多可用的选项,而且我也无法确定PyYAML是否允许这样做.基本原理是我必须序列化一些数据并将其以可读的形式传递给一个不是真正的技术同事进行手动验证。有些数据是多余的,但我需要以最明确的方式列出它们以提高可读性(anchor和引用是提高效率的好概念,但不是人类可读性)。Ruby和Python是我选择的工具,但如果有其他一些相当简单的方法来“展开”YAML文档,它可能就可以了。 最佳答案

  10. ruby-on-rails - 带有 Zeus 的 RSpec 3.1,我应该在 spec_helper 中要求 'rspec/rails' 吗? - 2

    使用rspec-rails3.0+,测试设置分为spec_helper和rails_helper我注意到生成的spec_helper不需要'rspec/rails'。这会导致zeus崩溃:spec_helper.rb:5:in`':undefinedmethod`configure'forRSpec:Module(NoMethodError)对thisissue最常见的回应是需要'rspec/rails'。但这是否会破坏仅使用spec_helper拆分rails规范和PORO规范的全部目的?或者这无关紧要,因为Zeus无论如何都会预加载Rails?我应该在我的spec_helper中做

随机推荐