草庐IT

ssl - Java SSL - InstallCert 识别证书,但仍然出现 "unable to find valid certification path"错误?

coder 2024-03-21 原文

我以为我遇到了和其他人一样的问题,我一直在经历无数类似的问题和潜在的解决方案,但没有运气。

我使用的信任库是 cacerts,位于 Java 1.6.0 JRE 的 lib/security 中(build 1.6.0_20-b02...这可能是问题的根源吗?)。我也尝试过 jssecacerts。

使用 InstallCert(根据发布的其他类似问题),我可以看到我的证书实际上已安装且有效(并且我已将其删除、重新导入等以确保我看到正确的数据):

java InstallCert <my host name>
Loading KeyStore jssecacerts...
Opening connection to <my host name>:443...
Starting SSL handshake...
No errors, certificate is already trusted

checkin keytool 和 Portecle,重新导入证书(我尝试使用 -showcert 从 openssl 生成,从浏览器导出并通过 scp 处理它,等等)给我“这已经存在于这里的另一个别名下"类型的消息。因此,证书进入工具的方式似乎没有任何问题。

在代码中强制使用明确的 trustStore 路径没有任何区别,在所有情况下,当我打开调试(通过 javax.net.debug 的 setProperty 到“全部”)时,我最终看到的是:

main, SEND TLSv1 ALERT:  fatal, description = certificate_unknown
main, WRITE: TLSv1 Alert, length = 2 [Raw write]: length = 7 0000: 15
03 01 00 02 02 2E                               ....... main, called
closeSocket() main, handling exception:
javax.net.ssl.SSLHandshakeException:
sun.security.validator.ValidatorException: PKIX path building failed:
sun.security.provider.certpath.SunCertPathBuilderException: unable to
find valid certification path to requested target

不幸的是,我不能允许通过实现我自己的 TrustManager 来覆盖检查 - 它必须实际检查。

我从主机获得的证书有许多扩展名(确切地说是 9 个),这让我想知道它们是否与此问题有关。

我还能检查/尝试什么?切换到不同的 JRE 版本?

最佳答案

您仍然可以通过实现自己的信任管理器来检查证书。我遇到了类似的问题 here .我还尝试将证书添加到 cacerts 但无济于事。

在您的信任管理器中,您需要显式加载证书。基本上我必须做的是这样的:

首先,我创建了一个使用实际证书文件的信任管理器:

public class ValicertX509TrustManager implements X509TrustManager {

    X509TrustManager pkixTrustManager;

    ValicertX509TrustManager() throws Exception {

        String valicertFile = "/certificates/ValicertRSAPublicRootCAv1.cer";
        String commwebDRFile = "/certificates/DR_10570.migs.mastercard.com.au.crt";
        String commwebPRODFile = "/certificates/PROD_10549.migs.mastercard.com.au.new.crt";

        Certificate valicert = CertificateFactory.getInstance("X509").generateCertificate(this.getClass().getResourceAsStream(valicertFile));
        Certificate commwebDR = CertificateFactory.getInstance("X509").generateCertificate(this.getClass().getResourceAsStream(commwebDRFile));
        Certificate commwebPROD = CertificateFactory.getInstance("X509").generateCertificate(this.getClass().getResourceAsStream(commwebPRODFile));

        KeyStore keyStore = KeyStore.getInstance("JKS");
        keyStore.load(null, "".toCharArray());
        keyStore.setCertificateEntry("valicert", valicert);
        keyStore.setCertificateEntry("commwebDR", commwebDR);
        keyStore.setCertificateEntry("commwebPROD", commwebPROD);

        TrustManagerFactory trustManagerFactory = TrustManagerFactory.getInstance("PKIX");
        trustManagerFactory.init(keyStore);

        TrustManager trustManagers[] = trustManagerFactory.getTrustManagers();

        for(TrustManager trustManager : trustManagers) {
            if(trustManager instanceof X509TrustManager) {
                pkixTrustManager = (X509TrustManager) trustManager;
                return;
            }
        }

        throw new Exception("Couldn't initialize");
    }

    public void checkClientTrusted(X509Certificate[] chain, String authType) throws CertificateException {
        pkixTrustManager.checkServerTrusted(chain, authType);
    }

    public void checkServerTrusted(X509Certificate[] chain, String authType) throws CertificateException {
        pkixTrustManager.checkServerTrusted(chain, authType);
    }

    public X509Certificate[] getAcceptedIssuers() {
        return pkixTrustManager.getAcceptedIssuers();
    }
}

现在,使用这个信任管理器,我必须创建一个套接字工厂:

public class ValicertSSLProtocolSocketFactory implements ProtocolSocketFactory {

    private SSLContext sslContext = null;

    public ValicertSSLProtocolSocketFactory() {
        super();
    }

    private static SSLContext createValicertSSLContext() {
        try {
            ValicertX509TrustManager valicertX509TrustManager = new ValicertX509TrustManager();
            SSLContext context = SSLContext.getInstance("TLS");
            context.init(null, new ValicertX509TrustManager[] { valicertX509TrustManager}, null);
            return context;
        }

        catch(Exception e) {
            Log.error(Log.Context.Net, e);
            return null;
        }
    }

    private SSLContext getSSLContext() {
        if(this.sslContext == null) {
            this.sslContext = createValicertSSLContext();
        }

        return this.sslContext;
    }

    public Socket createSocket(String host, int port, InetAddress clientHost, int clientPort) throws IOException {
        return getSSLContext().getSocketFactory().createSocket(host, port, clientHost, clientPort);
    }

    public Socket createSocket(final String host, final int port, final InetAddress localAddress, final int localPort, final HttpConnectionParams params) throws IOException {
        if(params == null) {
            throw new IllegalArgumentException("Parameters may not be null");
        }

        int timeout = params.getConnectionTimeout();
        SocketFactory socketFactory = getSSLContext().getSocketFactory();

        if(timeout == 0) {
            return socketFactory.createSocket(host, port, localAddress, localPort);
        }

        else {
            Socket socket = socketFactory.createSocket();
            SocketAddress localAddr = new InetSocketAddress(localAddress, localPort);
            SocketAddress remoteAddr = new InetSocketAddress(host, port);
            socket.bind(localAddr);
            socket.connect(remoteAddr, timeout);
            return socket;
        }
    }

    public Socket createSocket(String host, int port) throws IOException {
        return getSSLContext().getSocketFactory().createSocket(host, port);
    }

    public Socket createSocket(Socket socket, String host, int port, boolean autoClose) throws IOException {
        return getSSLContext().getSocketFactory().createSocket(socket, host, port, autoClose);
    }

    public boolean equals(Object obj) {
        return ((obj != null) && obj.getClass().equals(ValicertSSLProtocolSocketFactory.class));
    }

    public int hashCode() {
        return ValicertSSLProtocolSocketFactory.class.hashCode();
    }
}

然后我就注册了一个新的协议(protocol):

Protocol.registerProtocol("vhttps", new Protocol("vhttps", new ValicertSSLProtocolSocketFactory(), 443));
PostMethod postMethod = new PostMethod(url);
for (Map.Entry<String, String> entry : params.entrySet()) {
    postMethod.addParameter(entry.getKey(), StringUtils.Nz(entry.getValue()));
}

HttpClient client = new HttpClient();
int status = client.executeMethod(postMethod);
if (status == 200) {
    StringBuilder resultBuffer = new StringBuilder();
    resultBuffer.append(postMethod.getResponseBodyAsString());
    return new HttpResponse(resultBuffer.toString(), "");
} else {
    throw new IOException("Invalid response code: " + status);
}

唯一的缺点是我必须为这个特定的证书创建一个特定的协议(protocol) (vhttps)。

关于ssl - Java SSL - InstallCert 识别证书,但仍然出现 "unable to find valid certification path"错误?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11087121/

有关ssl - Java SSL - InstallCert 识别证书,但仍然出现 "unable to find valid certification path"错误?的更多相关文章

  1. ruby-on-rails - rails : "missing partial" when calling 'render' in RSpec test - 2

    我正在尝试测试是否存在表单。我是Rails新手。我的new.html.erb_spec.rb文件的内容是:require'spec_helper'describe"messages/new.html.erb"doit"shouldrendertheform"dorender'/messages/new.html.erb'reponse.shouldhave_form_putting_to(@message)with_submit_buttonendendView本身,new.html.erb,有代码:当我运行rspec时,它失败了:1)messages/new.html.erbshou

  2. ruby-on-rails - 由于 "wkhtmltopdf",PDFKIT 显然无法正常工作 - 2

    我在从html页面生成PDF时遇到问题。我正在使用PDFkit。在安装它的过程中,我注意到我需要wkhtmltopdf。所以我也安装了它。我做了PDFkit的文档所说的一切......现在我在尝试加载PDF时遇到了这个错误。这里是错误:commandfailed:"/usr/local/bin/wkhtmltopdf""--margin-right""0.75in""--page-size""Letter""--margin-top""0.75in""--margin-bottom""0.75in""--encoding""UTF-8""--margin-left""0.75in""-

  3. ruby - 检查 "command"的输出应该包含 NilClass 的意外崩溃 - 2

    为了将Cucumber用于命令行脚本,我按照提供的说明安装了arubagem。它在我的Gemfile中,我可以验证是否安装了正确的版本并且我已经包含了require'aruba/cucumber'在'features/env.rb'中为了确保它能正常工作,我写了以下场景:@announceScenario:Testingcucumber/arubaGivenablankslateThentheoutputfrom"ls-la"shouldcontain"drw"假设事情应该失败。它确实失败了,但失败的原因是错误的:@announceScenario:Testingcucumber/ar

  4. ruby-on-rails - 迷你测试错误 : "NameError: uninitialized constant" - 2

    我遵循MichaelHartl的“RubyonRails教程:学习Web开发”,并创建了检查用户名和电子邮件长度有效性的测试(名称最多50个字符,电子邮件最多255个字符)。test/helpers/application_helper_test.rb的内容是:require'test_helper'classApplicationHelperTest在运行bundleexecraketest时,所有测试都通过了,但我看到以下消息在最后被标记为错误:ERROR["test_full_title_helper",ApplicationHelperTest,1.820016791]test

  5. ruby-on-rails - 相关表上的范围为 "WHERE ... LIKE" - 2

    我正在尝试从Postgresql表(table1)中获取数据,该表由另一个相关表(property)的字段(table2)过滤。在纯SQL中,我会这样编写查询:SELECT*FROMtable1JOINtable2USING(table2_id)WHEREtable2.propertyLIKE'query%'这工作正常:scope:my_scope,->(query){includes(:table2).where("table2.property":query)}但我真正需要的是使用LIKE运算符进行过滤,而不是严格相等。然而,这是行不通的:scope:my_scope,->(que

  6. 使用 ACL 调用 upload_file 时出现 Ruby S3 "Access Denied"错误 - 2

    我正在尝试编写一个将文件上传到AWS并公开该文件的Ruby脚本。我做了以下事情:s3=Aws::S3::Resource.new(credentials:Aws::Credentials.new(KEY,SECRET),region:'us-west-2')obj=s3.bucket('stg-db').object('key')obj.upload_file(filename)这似乎工作正常,除了该文件不是公开可用的,而且我无法获得它的公共(public)URL。但是当我登录到S3时,我可以正常查看我的文件。为了使其公开可用,我将最后一行更改为obj.upload_file(file

  7. ruby - 安装 Ruby 时遇到问题(无法下载资源 "readline--patch") - 2

    当我尝试安装Ruby时遇到此错误。我试过查看this和this但无济于事➜~brewinstallrubyWarning:YouareusingOSX10.12.Wedonotprovidesupportforthispre-releaseversion.Youmayencounterbuildfailuresorotherbreakages.Pleasecreatepull-requestsinsteadoffilingissues.==>Installingdependenciesforruby:readline,libyaml,makedepend==>Installingrub

  8. ruby - RVM "ERROR: Unable to checkout branch ."单用户 - 2

    我在新的Debian6VirtualBoxVM上安装RVM时遇到问题。我已经安装了所有需要的包并使用下载了安装脚本(curl-shttps://rvm.beginrescueend.com/install/rvm)>rvm,但以单个用户身份运行时bashrvm我收到以下错误消息:ERROR:Unabletocheckoutbranch.安装在这里停止,并且(据我所知)没有安装RVM的任何文件。如果我以root身份运行脚本(对于多用户安装),我会收到另一条消息:Successfullycheckedoutbranch''安装程序继续并指示成功,但未添加.rvm目录,甚至在修改我的.bas

  9. ruby - 如何关闭 ruby​​ gem "Spreadsheet?"中的文件 - 2

    下面的代码在我第一次运行它时就可以正常工作:require'rubygems'require'spreadsheet'book=Spreadsheet.open'/Users/me/myruby/Mywks.xls'sheet=book.worksheet0row=sheet.row(1)putsrow[1]book.write'/Users/me/myruby/Mywks.xls'当我再次运行它时,我会收到更多消息,例如:/Library/Ruby/Gems/1.8/gems/spreadsheet-0.6.5.9/lib/spreadsheet/excel/reader.rb:11

  10. ruby - Ruby 语法糖有 "rules"吗? - 2

    我正在学习Ruby的基础知识(刚刚开始),我遇到了Hash.[]method.它被引入a=["foo",1,"bar",2]=>["foo",1,"bar",2]Hash[*a]=>{"foo"=>1,"bar"=>2}稍加思索,我发现Hash[*a]等同于Hash.[](*a)或Hash.[]*一个。我的问题是为什么会这样。是什么让您将*a放在方括号内,是否有某种规则可以在何时何地使用“it”?编辑:我的措辞似乎造成了一些困惑。我不是在问数组扩展。我明白了。我的问题基本上是:如果[]是方法名称,为什么可以将参数放在括号内?这看起来几乎——但不完全是——就像说如果你有一个方法Foo.d

随机推荐