我正在执行查询以使用 chartjs 绘制多折线图。我有一组日期

["2016-10-16","2016-10-17","2016-10-18","2016-10-19","2016-10-20","2016-10-21","2016-10-22","2016-10-23","2016-10-24","2016-10-25","2016-10-26","2016-10-27","2016-10-28","2016-10-29","2016-10-30","2016-10-31","2016-11-01","2016-11-02","2016-11-03","2016-11-04","2016-11-05","2016-11-06","2016-11-07","2016-11-08","2016-11-09","2016-11-10","2016-11-11","2016-11-12","2016-11-13","2016-11-14","2016-11-15","2016-11-16"]

此数组的日期介于“2016-11-16”和“2016-10-16”之间。

我创建了一个模型 Tickets，我编写了一个查询来获取按 tickets.status 分组的票数。

$join = $this->tickets();
$tickets = $join
         ->when($category, function($query) use ($category) {
             $ranges = $this->dateRange($category);
             return $query->whereBetween('tickets.created_at', $ranges);
         })
         ->select(DB::raw('COUNT(tickets.id) as tickets'), 'ticket_status.name as name', 'tickets.created_at')
         ->groupBy('ticket_status.name', 'tickets.created_at')
         ->get();

执行我得到的这个查询

[
    {
        "tickets":"1",
        "name":"Closed",
        "created_at":"2016-11-08 14:07:32"
    },
    {
        "tickets":"1",
        "name":"Open",
        "created_at":"2016-11-08 14:07:32"
    },
    {
        "tickets":"1",
        "name":"Open",
        "created_at":"2016-11-11 12:24:39"
    },
    {
        "tickets":"1",
        "name":"Open",
        "created_at":"2016-11-11 12:26:38"
    },
    {
        "tickets":"1",
        "name":"Open",
        "created_at":"2016-11-11 12:27:04"
    },
    {
        "tickets":"1",
        "name":"Open",
        "created_at":"2016-11-11 12:27:49"
    },
    {
        "tickets":"1",
        "name":"Open",
        "created_at":"2016-11-11 12:28:47"
    },
    {
        "tickets":"1",
        "name":"Resolved",
        "created_at":"2016-11-08 14:07:32"
    }
]

如果 $label[0] != $tickets.created，票和名字将为空，但应该有日期

请帮我得到类似的输出

[
    [
        'tickets'=>0,
        'name'=>null,//tickets don't have this date
        'created_at'=>'2016-10-16'
    ],
    [
        'tickets'=>0,
        'name'=>null,//tickets don't have this date
        'created_at'=>'2016-10-15'
    ],
    [
        'tickets'=>1,
        'name'=>'closed',//on this date 1 closed ticket
        'created_at'=>'2016-10-14'
    ],
    [
        'tickets'=>3,
        'name'=>'open',//on this date 3 open ticket
        'created_at'=>'2016-10-14'
    ],
    [
        'tickets'=>2,
        'name'=>'resolved',//on this date 2 resolved ticket
        'created_at'=>'2016-10-14'// on 2016-10-14 has three different tickets
    ],
    ...........
]

请帮我找到解决办法。提前致谢。

最佳答案

请关注Laravel:Collection:GroupBy

所以你可能需要这样的代码

$join = $this->tickets();
$tickets = $join
         ->when($category, function($query) use ($category) {
             $ranges = $this->dateRange($category);
             return $query->whereBetween('tickets.created_at', $ranges);
         })
         ->select(DB::raw('COUNT(tickets.id) as tickets'), 'ticket_status.name as name', 'tickets.created_at')
         ->get()->groupBy(/** YOUR LOGIC HERE  **/);

关于php - 带条件的 laravel 查询生成器，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40633483/