我发现 C++ 提供了默认的 operator<< enum 的函数类型:
#include <iostream>
using namespace std;
enum OpType {
Select,
Insert
};
int main() {
OpType t = Select;
cout << t;
return 0;
}
运行结果为:
0
虽然不提供默认 operator>>功能:
#include <iostream>
using namespace std;
enum OpType {
Select,
Insert
};
int main() {
OpType t = Select;
cin >> t;
return 0;
}
构建它会产生以下编译错误:
prog.cpp: In function ‘int main()’:
prog.cpp:11:6: error: no match for ‘operator>>’ (operand types are ‘std::istream {aka std::basic_istream<char>}’ and ‘OpType’)
cin >> t;
~~~~^~~~
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:168:7: note: candidate: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(bool&) [with _CharT = char; _Traits = std::char_traits<char>; std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
operator>>(bool& __n)
^~~~~~~~
/usr/include/c++/6/istream:168:7: note: conversion of argument 1 would be ill-formed:
prog.cpp:11:9: error: invalid initialization of non-const reference of type ‘bool&’ from an rvalue of type ‘bool’
cin >> t;
^
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:172:7: note: candidate: std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(short int&) [with _CharT = char; _Traits = std::char_traits<char>] <near match>
operator>>(short& __n);
^~~~~~~~
/usr/include/c++/6/istream:172:7: note: conversion of argument 1 would be ill-formed:
prog.cpp:11:9: error: invalid initialization of non-const reference of type ‘short int&’ from an rvalue of type ‘short int’
cin >> t;
^
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:175:7: note: candidate: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(short unsigned int&) [with _CharT = char; _Traits = std::char_traits<char>; std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
operator>>(unsigned short& __n)
^~~~~~~~
/usr/include/c++/6/istream:175:7: note: conversion of argument 1 would be ill-formed:
prog.cpp:11:9: error: invalid initialization of non-const reference of type ‘short unsigned int&’ from an rvalue of type ‘short unsigned int’
cin >> t;
^
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:179:7: note: candidate: std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(int&) [with _CharT = char; _Traits = std::char_traits<char>] <near match>
operator>>(int& __n);
^~~~~~~~
/usr/include/c++/6/istream:179:7: note: conversion of argument 1 would be ill-formed:
prog.cpp:11:9: error: invalid initialization of non-const reference of type ‘int&’ from an rvalue of type ‘int’
cin >> t;
^
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:182:7: note: candidate: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(unsigned int&) [with _CharT = char; _Traits = std::char_traits<char>; std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
operator>>(unsigned int& __n)
^~~~~~~~
/usr/include/c++/6/istream:182:7: note: conversion of argument 1 would be ill-formed:
prog.cpp:11:9: error: invalid initialization of non-const reference of type ‘unsigned int&’ from an rvalue of type ‘unsigned int’
cin >> t;
^
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:186:7: note: candidate: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(long int&) [with _CharT = char; _Traits = std::char_traits<char>; std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
operator>>(long& __n)
^~~~~~~~
/usr/include/c++/6/istream:186:7: note: conversion of argument 1 would be ill-formed:
prog.cpp:11:9: error: invalid initialization of non-const reference of type ‘long int&’ from an rvalue of type ‘long int’
cin >> t;
^
In file included from /usr/include/c++/6/iostream:40:0,
from prog.cpp:1:
/usr/include/c++/6/istream:190:7: note: candidate: std::basic_istream<_CharT, _Traits>::__istream_type& std::basic_istream<_CharT, _Traits>::operator>>(long unsigned int&) [with _CharT = char; _Traits = std::char_traits<char>; std::basic_istream<_CharT, _Traits>::__istream_type = std::basic_istream<char>] <near match>
......
为什么C++不提供默认operator>>枚举类型的函数?
最佳答案
即使不考虑没有 << 的事实运算符 - 枚举首先隐式转换为整数 - 如何标准化它并不明显。
读取不存在的枚举值的结果是错误、未指定、实现定义还是未定义?
不同的应用程序需要不同的行为,甚至在同一个应用程序中也是如此。
这让每个人都回到原点,编写与我们现在相同的代码。
还有一个问题是,流运算符不是语言本身的一部分,流概念也不是,因此您无法真正让编译器为您生成它们。
关于c++ - 为什么 C++ 不为枚举类型提供默认的 "operator>>"函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45230348/
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