我正在使用 JAXB 来编码一些常规对象。我得到这样的输出:

<desiredskillslist>
 <employeeDesiredSkills xsi:type="employeeDesiredSkill" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
     <name>C Development</name>
 </employeeDesiredSkills>
 <employeeDesiredSkills xsi:type="employeeDesiredSkill" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
     <name>Perl Development</name>
 </employeeDesiredSkills>
 <employeeDesiredSkills xsi:type="employeeDesiredSkill" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
     <name>Java Development</name>
 </employeeDesiredSkills>
 <employeeDesiredSkills xsi:type="employeeDesiredSkill" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
     <name>Database Design</name>
 </employeeDesiredSkills>
 <employeeDesiredSkills xsi:type="employeeDesiredSkill" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
     <name>Grails Development</name>
 </employeeDesiredSkills>

我真的不想要 xsi:type=和 xmlns:xsi=出现在我的最终文档中，因为它不需要它。这可能吗？

另外 - 我设置了一个 @XmlElementWrapper(name="desiredskillslist")将标签放在 employeeDesiredSkills 周围, 但如果可能的话，我宁愿没有 <employeeDesiredSkillsT>根本没有标签-如果它只是名称列表，那就太好了。为什么我注释了ArrayList会这样出来？

最佳答案

I really dont want the xsi:type= and xmlns:xsi= to show up in my final document, since it wont need it. Is this possible?

我不确定为什么 xsi:type 会出现在您面前。正如您在下面的示例中看到的，它通常不会出现。您的模型与以下示例有哪些不同之处？

I'd ratherjust not have the tags at all - if itw as just the list of names, that'd be great.

我相信您所寻找的可以通过@XmlValue 注释来实现。请参阅下面 DesiredSkill 类的名称属性:

import java.util.*;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Root {

    private List<DesiredSkill> employeeDesiredSkills = new ArrayList<DesiredSkill>();

    public List<DesiredSkill> getEmployeeDesiredSkills() {
        return employeeDesiredSkills;
    }

    public void setEmployeeDesiredSkills(List<DesiredSkill> employeeDesiredSkills) {
        this.employeeDesiredSkills = employeeDesiredSkills;
    }

}

和:

import javax.xml.bind.annotation.XmlValue;

public class DesiredSkill {

    private String name;

    @XmlValue
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

}

然后是下面的代码:

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

public class Demo {

    public static void main(String[] args) throws Exception {
        Root root = new Root();

        DesiredSkill cDev = new DesiredSkill();
        cDev.setName("C Development");
        root.getEmployeeDesiredSkills().add(cDev);

        DesiredSkill perlDev = new DesiredSkill();
        perlDev.setName("Perl Development");
        root.getEmployeeDesiredSkills().add(perlDev);

        JAXBContext jc = JAXBContext.newInstance(Root.class);
        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(root, System.out);
    }
}

将产生:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root>
    <employeeDesiredSkills>C Development</employeeDesiredSkills>
    <employeeDesiredSkills>Perl Development</employeeDesiredSkills>
</root>

关于java - JAXB 抑制 XSI 和 xmlns，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/3773156/