我有两个表,表 1 有 2 个字段(question_pk、question_name),表 2 有 4 个字段(ans_pk、options、question_fk 和 right_answer)。 我想创建如下结构的json
{
"type": "quiz",
"name": "Brand Colors",
"description": "Can you identify these brands by the background color?",
"questions": [
{
"name": "Can you identify this color?",
"description": "#ea4c89",
"answers": [
{
"name": "Dribbble",
"description": "dribbble.png",
"weight": 1
},
{
"name": "Amazon",
"description": "amazon.png",
"weight": 0
},
{
"name": "Apple",
"description": "apple.png",
"weight": 0
}
]
},
{
"name": "Can you identify this color?",
"description": "#3d9ae8",
"answers": [
{
"name": "Youtube",
"description": "youtube.png",
"weight": 0
},
{
"name": "Dropbox",
"description": "dropbox.png",
"weight": 1
},
{
"name": "Wordpress",
"description": "wordpress.png",
"weight": 0
}
]
},
{
"name": "Can you identify this color?",
"description": "#c4302b",
"answers": [
{
"name": "Youtube",
"description": "youtube.png",
"weight": 1
},
{
"name": "Twitter",
"description": "twitter.png",
"weight": 0
},
{
"name": "Vimeo",
"description": "vimeo.png",
"weight": 0
}
]
}
]
}
我的 PHP 代码
<?php
include '../config/config.php';
if(isset($_GET['sub_cat_id']))
{
$sub_cat_id = $_GET['sub_cat_id'];
$result = mysql_query("select * from $questions where sub_cat='$sub_cat_id' order by level_fk asc");
$json_response = array(); //Create an array
$i=1;
while ($row = mysql_fetch_array($result))
{
$row_array['qus_pk'] = $row['qus_pk'];
$row_array['question'] = $row['question'];
$qus_pk = $row['qus_pk'];
$option_qry = mysql_query("select * from $qus_ans where qus_pk=$qus_pk");
while ($opt_fet = mysql_fetch_array($option_qry))
{
$row_array['options'] = $opt_fet['options'];
$row_array['right_ans'] = $opt_fet['right_ans'];
array_push($json_response,$row_array); //push the values in the array
}
$i++;
}
echo json_encode($json_response);
}
?>
我的结果是我得到如下所示的 json 响应
[
{
"qus_pk": "1",
"question": "Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?",
"options": "45",
"right_ans": "0"
},
{
"qus_pk": "1",
"question": "Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?",
"options": "40",
"right_ans": "0"
},
{
"qus_pk": "1",
"question": "Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?",
"options": "35",
"right_ans": "1"
},
{
"qus_pk": "1",
"question": "Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?",
"options": "50",
"right_ans": "0"
},
{
"qus_pk": "2",
"question": "Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?",
"options": "4 times",
"right_ans": "0"
},
{
"qus_pk": "2",
"question": "Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?",
"options": "1 times",
"right_ans": "0"
},
{
"qus_pk": "2",
"question": "Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?",
"options": "3 times",
"right_ans": "1"
},
{
"qus_pk": "2",
"question": "Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?",
"options": "5 times",
"right_ans": "0"
}
]
在我的回复中,每次重复问题时,如何避免以及如果我想获得第一个 json 结构,在我的 PHP 代码中我需要更改什么以及在哪里?有知道的帮帮我吧。
最佳答案
嗨,试试这个,
<?php
include '../config/config.php';
if(isset($_GET['sub_cat_id']))
{
$sub_cat_id = $_GET['sub_cat_id'];
$result = mysql_query("SELECT * FROM $questions WHERE sub_cat='$sub_cat_id' ORDER BY level_fk ASC");
$json_response = array(); //Create an array
while ($row = mysql_fetch_array($result))
{
$row_array = array();
$row_array['qus_pk'] = $row['qus_pk'];
$row_array['question'] = $row['question'];
$row_array['answers'] = array();
$qus_pk = $row['qus_pk'];
$option_qry = mysql_query("SELECT * FROM $qus_ans WHERE qus_pk=$qus_pk");
while ($opt_fet = mysql_fetch_array($option_qry))
{
$row_array['answers'][] = array(
'options' => $opt_fet['options'],
'right_ans' => $opt_fet['right_ans'],
);
}
array_push($json_response, $row_array); //push the values in the array
}
echo json_encode($json_response);
}
?>
关于php - 使用 php mysql 创建嵌套的 json 对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30155231/
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