在 PostgreSQL 中，我有一个名为 surveys 的表。

CREATE TABLE SURVEYS(
  SURVEY_ID UUID PRIMARY KEY NOT NULL DEFAULT uuid_generate_v4(),
  SURVEY_NAME VARCHAR NOT NULL,
  SURVEY_DESCRIPTION TEXT,
  START_PERIOD TIMESTAMP,
  END_PERIOD TIMESTAMP
);

如您所见，只有 SURVEY_ID 和 SURVEY_NAME 列是 NOT NULL。

在 Go 中，我想通过 POST 请求在该表中创建新条目。我像这样发送 JSON 对象:

{
    "survey_name": "NAME",
    "survey_description": "DESCRIPTION",
    "start_period": "2019-01-01 00:00:00",
    "end_period": "2019-02-28 23:59:59"
}

不幸的是，它引发了奇怪的ERROR:

parsing time ""2019-01-01 00:00:00"" as ""2006-01-02T15:04:05Z07:00"": cannot parse " 00:00:00"" as "T"

我在哪里出错以及如何解决我的问题？

models/surveys.go:

import (
    "database/sql"
    "time"
)

type NullTime struct {
    time.Time
    Valid bool
}

type Survey struct {
    ID int `json:"survey_id"`
    Name string `json:"survey_name"`
    Description sql.NullString `json:"survey_description"`
    StartPeriod NullTime `json:"start_period"`
    EndPeriod NullTime `json:"end_period"`
}

controllers/surveys.go:

var CreateSurvey = func(responseWriter http.ResponseWriter, request *http.Request) {
    // Initialize variables.
    survey := models.Survey{}
    var err error

    // The decoder introduces its own buffering and may read data from argument beyond the JSON values requested.
    err = json.NewDecoder(request.Body).Decode(&survey)
    if err != nil {
        log.Println(err)
        utils.ResponseWithError(responseWriter, http.StatusInternalServerError, err.Error())
        return
    }
    defer request.Body.Close()

    // Execute INSERT SQL statement.
    _, err = database.DB.Exec("INSERT INTO surveys (survey_name, survey_description, start_period, end_period) VALUES ($1, $2, $3, $4);", survey.Name, survey.Description, survey.StartPeriod, survey.EndPeriod)

    // Shape the response depending on the result of the previous command.
    if err != nil {
        log.Println(err)
        utils.ResponseWithError(responseWriter, http.StatusInternalServerError, err.Error())
        return
    }
    utils.ResponseWithSuccess(responseWriter, http.StatusCreated, "The new entry successfully created.")
}

最佳答案

错误已经说明了问题所在:

parsing time ""2019-01-01 00:00:00"" as ""2006-01-02T15:04:05Z07:00"": cannot parse " 00:00:00"" as "T"

您正在传递 "2019-01-01 00:00:00" 而它需要不同的时间格式，即 RFC3339 (UnmarshalJSON's default)。

要解决这个问题，您要么想要以预期格式传递时间 "2019-01-01T00:00:00Z00:00" 要么定义您自己的类型 CustomTime 像这样:

const timeFormat = "2006-01-02 15:04:05"

type CustomTime time.Time

func (ct *CustomTime) UnmarshalJSON(data []byte) error {
    newTime, err := time.Parse(timeFormat, strings.Trim(string(data), "\""))
    if err != nil {
        return err
    }

    *ct = CustomTime(newTime)
    return nil
}

func (ct *CustomTime) MarshalJSON() ([]byte, error) {
    return []byte(fmt.Sprintf("%q", time.Time(*ct).Format(timeFormat))), nil
}

注意，您可能还需要实现 Valuer 和 Scanner 接口(interface)，以便在数据库内外解析时间，如下所示:

func (ct CustomTime) Value() (driver.Value, error) {
    return time.Time(ct), nil
}

func (ct *CustomTime) Scan(src interface{}) error {
    if val, ok := src.(time.Time); ok {
        *ct = CustomTime(val)
    } else {
        return errors.New("time Scanner passed a non-time object")
    }

    return nil
}

Go Playground示例。

关于go - 解析 PostgreSQL TIMESTAMP 类型值的问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54921636/