编辑:现在已解决 - 在此发布解决方案以防将来有人需要它或任何人都可以提出更好的方法。我从我的 list 中删除了 Intent 内容，并在我的 SmsReceiver 类中设置了 BroadcastReceiver。这现在有效。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

using Android.App;
using Android.Content;
using Android.OS;
using Android.Runtime;
using Android.Views;
using Android.Widget;
using Android.Util;
using Android.Telephony;

namespace dummyAndroid
{
    [BroadcastReceiver(Enabled = true, Label = "SMS Receiver")]
    [IntentFilter(new string[] { "android.provider.Telephony.SMS_RECEIVED" })] 
    public class SmsReceiver : Android.Content.BroadcastReceiver 
    {
        public static readonly string INTENT_ACTION = "android.provider.Telephony.SMS_RECEIVED"; 

        public override void OnReceive(Context context, Intent intent)
        {
            if (intent.Action == INTENT_ACTION)
            {
                StringBuilder buffer = new StringBuilder();
                Bundle bundle = intent.Extras;

                if (bundle != null)
                {
                    Java.Lang.Object[] pdus = (Java.Lang.Object[])bundle.Get("pdus");

                    SmsMessage[] msgs;
                    msgs = new SmsMessage[pdus.Length];

                    for (int i = 0; i < msgs.Length; i++)
                    {
                        msgs[i] = SmsMessage.CreateFromPdu((byte[])pdus[i]);

                        Log.Info("SmsReceiver", "SMS Received from: " + msgs[i].OriginatingAddress);
                        Log.Info("SmsReceiver", "SMS Data: " + msgs[i].MessageBody.ToString());
                    }

                    Log.Info("SmsReceiver", "SMS Received");
                }
            } 
        }
    }
}

我正在编写一个发送/接收 SMS 消息的应用程序，并且已经通过 SMS Mananger 进行发送。

我现在正尝试在 Android 的 Mono 中接收短信，我是 Android 开发的新手，所以我可能做错了什么!

我已将以下内容添加到我的 list 中

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android" android:installLocation="auto" package="com.me.dummyAndroid" android:versionCode="1" android:versionName="1">
  <uses-sdk android:targetSdkVersion="8" />
  <application 
        android:label="meAndroidSMS"
        android:theme="@android:style/Theme.NoTitleBar.Fullscreen">
    <receiver android:name=".SmsReceiver">
      <intent-filter>
        <action android:name=
                    "android.provider.Telephony.SMS_RECEIVED" />
      </intent-filter>
    </receiver>
  </application>
  <uses-permission android:name="android.permission.SEND_SMS" />
  <uses-permission android:name="android.permission.RECEIVE_SMS" />
  <uses-permission android:name="android.permission.READ_SMS" />
</manifest>

然后我创建了一个名为 SmsReceiver.cs 的新类，我已将函数 onReceive 添加到其中，但在 intent 中似乎没有 getExtras 函数，根据我阅读的在线教程，我需要它(http://www.techques.com/question/1-3542320/IPhone-Android-SMS-intercept-and-redirection-to-an-application .).

namespace dummyAndroid
{
    class SmsReceiver
    {
        public void onReceive(Context context, Intent intent)
        {
            Bundle bundle = intent.getExtras();



        }
    }
}

我很感激我在 Android 和 MonoDroid 上确实有点不知所措，但也许有人能给我指明正确的方向!

最佳答案

我这里有一些工作代码(我不记得来源，但我认为是与 Xamarin 相关的人编写了这个示例)，它在收到 SMS 时显示 Toast。

using System.Text;

using Android.App;
using Android.Content;
using Android.Runtime;
using Android.Util;
using Android.Widget;
using Android.Telephony;
using Environment = System.Environment;

namespace MonoDroid.SMSFun
{
    [BroadcastReceiver(Enabled = true, Label = "SMS Receiver")]
    [IntentFilter(new[] { "android.provider.Telephony.SMS_RECEIVED" })] 
    public class SMSBroadcastReceiver : BroadcastReceiver
    {
        private const string Tag = "SMSBroadcastReceiver";
        private const string IntentAction = "android.provider.Telephony.SMS_RECEIVED"; 

        public override void OnReceive(Context context, Intent intent)
        {
            Log.Info(Tag, "Intent received: " + intent.Action);

            if (intent.Action != IntentAction) return;

            var bundle = intent.Extras;

            if (bundle == null) return;

            var pdus = bundle.Get("pdus");
            var castedPdus = JNIEnv.GetArray<Java.Lang.Object>(pdus.Handle);

            var msgs = new SmsMessage[castedPdus.Length];

            var sb = new StringBuilder();

            for (var i = 0; i < msgs.Length; i++)
            {
                var bytes = new byte[JNIEnv.GetArrayLength(castedPdus[i].Handle)];
                JNIEnv.CopyArray(castedPdus[i].Handle, bytes);

                msgs[i] = SmsMessage.CreateFromPdu(bytes);

                sb.Append(string.Format("SMS From: {0}{1}Body: {2}{1}", msgs[i].OriginatingAddress,
                                        Environment.NewLine, msgs[i].MessageBody));
            }

            Toast.MakeText(context, sb.ToString(), ToastLength.Long).Show();
        }
    }
}

AndroidManifest.xml:

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android" android:installLocation="internalOnly" package="monodroid.smsfun" android:versionCode="1" android:versionName="1.0">
  <uses-sdk android:targetSdkVersion="8" />
  <application android:label="SMSFun">
  </application>
  <uses-permission android:name="android.permission.RECEIVE_SMS" />
</manifest>

关于c# - 使用 MonoDroid 接收短信，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14200091/