我在 Visual C++ 中创建了一个基本的字符串表资源。我正在尝试访问该资源。但是，我的程序似乎找不到资源。这里:

int main(int argc, char* argv[])
{
    HRSRC hRsrc;
    hRsrc = FindResource(NULL, MAKEINTRESOURCE(IDS_STRING102), RT_STRING);
    if (hRsrc == NULL) {
        printf("Not found\n");
    } else {
        printf("Found\n");
    }
}

这个程序找不到资源，总是返回null。

我创建了一个简单的位图资源，这个新程序可以很好地识别它。这里:

int main(int argc, char* argv[])
{
    HRSRC hRsrc;
    hRsrc = FindResource(NULL, MAKEINTRESOURCE(IDB_BITMAP1), RT_BITMAP);
    if (hRsrc == NULL) {
        printf("Not found\n");
    } else {
        printf("Found\n");
    }
}

这找到了位图。

字符串表资源的处理方式是否有所不同？

最佳答案

假设您不想使用 LoadString() 这应该有助于...

在使用 FindResource() 和 FindResourceEx() 时，字符串和字符串表确实被区别对待。来自 this KB文章:

String resources are stored as blocks of strings. Each block can have up to sixteen strings and represents the smallest granularity of string resource that can be loaded/updated. Each block is identified by an identifier (ID), starting with one (1). We use this ID when calling the FindResource, LoadResource and UpdateResource functions.

A string with ID, nStringID, is located in the block with ID, nBlockID, given by the following formula:

nBlockID = (nStringID / 16) + 1; // Note integer division.

nStringID 的低 4 位指示 block 中的哪个条目包含实际字符串。一旦计算出要传递给 FindResource() 的 block ID 和字符串所在 block 中的索引，您必须扫描它的内容以找到您要查找的字符串。

以下代码应该可以帮助您入门。

const WCHAR *stringPtr;
WCHAR stringLen;

//  Get the id of the string table block containing the target string
const DWORD blockID = (nID >> 4) + 1;

//  Get the offset of teh target string in the block
const DWORD itemID = nID % 0x10;

//  Find the resource
HRSRC hRes = FindResourceEx(
    hInst,
    RT_STRING,
    MAKEINTRESOURCE(blockID),
    wLanguage);
if (hRes)
{
    HGLOBAL hBlock = LoadResource(hInst, hRes);
    const WCHAR *tableDataBlock = reinterpret_cast<LPCWSTR>(LockResource(hBlock));
    const DWORD tableBlockSize = SizeofResource(hInst, hRes);
    DWORD searchOffset = 0;
    DWORD stringIndex = 0;

    //  Search through the section for the appropriate entry.
    //  The first two bytes of each entry is the length of the string
    //  followed by the Unicode string itself. All strings entries 
    //  are stored one after another with no padding.
    while(searchOffset < tableBlockSize)
    {
        if (stringIndex == itemID)
        {
            //  If the string has size. use it!
            if (tableDataBlock[searchOffset] != 0x0000)
            {
                stringPtr = &tableDataBlock[searchOffset + 1];
                stringLen = tableDataBlock[searchOffset];
            }
            //  Nothing there -
            else
            {
                stringPtr = NULL;
                stringLen = 0;
            }

            //  Done
            break;
        }

        //  Go to the next string in the table
        searchOffset += tableDataBlock[searchOffset] + 1;

        //  Bump the index
        stringIndex++;
    }
}

关于c++ - 如何在 Visual C++ 2010 中打开资源字符串？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6720259/