我想要一个 Foo 类来存储它在构造时获得的函数指针，并在某个时候调用这个函数。我查看了这两个问题以寻求帮助:

• Pass tuple's content as variadic function arguments
• How do I expand a tuple into variadic template function's arguments?

然后，根据答案，想出了这段代码:

#include <functional>

template < int N, typename... ARGS >
struct apply_func {
   static void applyTuple( std::function<void(ARGS...)>& f,
                          const std::tuple<ARGS...>& t,
                          ARGS... args ) {
    apply_func<N-1>::applyTuple( f, t, std::get<N-1>( t ), args... );
  }
};

template <typename... ARGS>
struct apply_func<0,ARGS...>
{
  static void applyTuple( std::function<void(ARGS...)>& f,
                          const std::tuple<ARGS...>& /* t */,
                          ARGS... args ) {
    f( args... );
  }
};

template < typename... ARGS >
void applyTuple( std::function<void(ARGS...)>& f,
                 std::tuple<ARGS...> const& t ) {
   apply_func<sizeof...(ARGS), ARGS...>::applyTuple( f, t );
}

template<typename... ARGS>
class Foo
{
    std::function<void(ARGS...)> m_f;
    std::tuple<ARGS...> *argument_pack;

    public:
    Foo(std::function<void(ARGS...)> f):m_f(f){}
    void operator()(ARGS... args);
    void run();

};

template<typename... ARGS>
void Foo<ARGS...>::operator()(ARGS... args)
{
    m_f(args...); // this works
}

template<typename... ARGS>
void Foo<ARGS...>::run()
{
    applyTuple<ARGS...>(m_f, *argument_pack); // this doesn't compile
}

void bar(int i, double d){}

int main(void)
{
    Foo<int,double> foo(bar);
    foo(1,1.0); // this works
    foo.run(); // this doesn't compile
}

如果您使用“g++ -std=c++0x”编译，倒数第二行将出现此错误:

    test.cc: In function ‘void applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&) [with ARGS = {int, double}]’:
test.cc:52:9:   instantiated from ‘void Foo<ARGS>::run() [with ARGS = {int, double}]’
test.cc:61:17:   instantiated from here
test.cc:27:8: error: no matching function for call to ‘apply_func<2, int, double>::applyTuple(std::function<void(int, double)>&, const std::tuple<int, double>&)’
test.cc:27:8: note: candidate is:
test.cc:6:19: note: static void apply_func<N, ARGS>::applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&, ARGS ...) [with int N = 2, ARGS = {int, double}]
test.cc:6:19: note:   candidate expects 4 arguments, 2 provided
test.cc: In static member function ‘static void apply_func<N, ARGS>::applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&, ARGS ...) [with int N = 2, ARGS = {int, double}]’:
test.cc:27:8:   instantiated from ‘void applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&) [with ARGS = {int, double}]’
test.cc:52:9:   instantiated from ‘void Foo<ARGS>::run() [with ARGS = {int, double}]’
test.cc:61:17:   instantiated from here
test.cc:9:9: error: no matching function for call to ‘apply_func<1>::applyTuple(std::function<void(int, double)>&, const std::tuple<int, double>&, const double&, int&, double&)’
test.cc:9:9: note: candidate is:
test.cc:6:19: note: static void apply_func<N, ARGS>::applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&, ARGS ...) [with int N = 1, ARGS = {}]
test.cc:6:19: note:   candidate expects 2 arguments, 5 provided
test.cc: In static member function ‘static void apply_func<N, ARGS>::applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&, ARGS ...) [with int N = 1, ARGS = {}]’:
test.cc:9:9:   instantiated from ‘static void apply_func<N, ARGS>::applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&, ARGS ...) [with int N = 2, ARGS = {int, double}]’
test.cc:27:8:   instantiated from ‘void applyTuple(std::function<void(ARGS ...)>&, const std::tuple<_Elements ...>&) [with ARGS = {int, double}]’
test.cc:52:9:   instantiated from ‘void Foo<ARGS>::run() [with ARGS = {int, double}]’
test.cc:61:17:   instantiated from here
test.cc:9:9: error: no matching function for call to ‘get(const std::tuple<>&)’
test.cc:9:9: note: candidates are:
/usr/include/c++/4.6/utility:133:5: note: template<long unsigned int _Int, class _Tp1, class _Tp2> typename std::tuple_element<_Int, std::pair<_Tp1, _Tp2> >::type& std::get(std::pair<_Tp1, _Tp2>&)
/usr/include/c++/4.6/utility:138:5: note: template<long unsigned int _Int, class _Tp1, class _Tp2> const typename std::tuple_element<_Int, std::pair<_Tp1, _Tp2> >::type& std::get(const std::pair<_Tp1, _Tp2>&)
/usr/include/c++/4.6/tuple:531:5: note: template<long unsigned int __i, class ... _Elements> typename std::__add_ref<typename std::tuple_element<__i, std::tuple<_Elements ...> >::type>::type std::get(std::tuple<_Elements ...>&)
/usr/include/c++/4.6/tuple:538:5: note: template<long unsigned int __i, class ... _Elements> typename std::__add_c_ref<typename std::tuple_element<__i, std::tuple<_Elements ...> >::type>::type std::get(const std::tuple<_Elements ...>&)

我错过了什么？谢谢!

最佳答案

我认为问题在于 applyTuple 将对元组的引用作为其第二个参数:

template < typename... ARGS >
void applyTuple( std::function<void(ARGS...)>& f,
                 std::tuple<ARGS...> const& t ) {
   apply_func<sizeof...(ARGS), ARGS...>::applyTuple( f, t );
}

但是，在 run 中，您传递了一个指向元组的指针，因为 argument_pack 是一个指向元组的指针:

std::tuple<ARGS...> *argument_pack;

如果将 run 的主体更改为

applyTuple<ARGS...>(m_f, *argument_pack);

那么我认为你的问题应该消失了。

希望这对您有所帮助!

关于c++ - 调用函数并传递存储在元组中的参数？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9189224/