我想返回我的应用程序的所有登录用户并将其呈现在我的仪表板中。 user_id 和 user_name 应该从 session 中检索(我正在使用外部 LDAP 库进行身份验证)

我在数据库中创建了一个名为 lastActivity 的字段，它将包含上次登录时间，然后我可以在数据库中查询 lastActivity 显示上次登录的用户2分钟。

ActivityListener.php

     <?php

namespace Bnpp\SecurityBundle\EventListener;

use Doctrine\ORM\EntityManager;
//use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\HttpKernel\HttpKernel;
use Acme\SecurityBundle\Entity\User;
use Doctrine\Bundle\DoctrineBundle\Registry;


/**
 * Listener that updates the last activity of the authenticated user
 */

class ActivityListener

    {
    protected $securityContext;
    protected $entityManager;

    public function __construct(SecurityContext $securityContext, EntityManager $entityManager)
    {
        $this->securityContext = $securityContext;
        $this->entityManager = $entityManager;
    }



    /**
     * Update the user "lastActivity" on each request
     * @param FilterControllerEvent $event
     */


    public function onCoreController(FilterControllerEvent $event)
    {

        // Check that the current request is a "MASTER_REQUEST"
        // Ignore any sub-request
        if ($event->getRequestType() !== HttpKernel::MASTER_REQUEST) {
            return;
        }

        // Check token authentication availability
        if ($this->securityContext->getToken()) {
            $user = $this->securityContext->getToken()->getUser();


            if ( ($user instanceof User) && !($user->isActiveNow()) ) {
                $user->setLastActivity(new \DateTime('now'));
                $this->entityManager->flush($user);
            }
        }

    }

}

服务.yml

services:
    activity_listener:
        class: Bnpp\SecurityBundle\EventListener\ActivityListener
        arguments: [@security.context, @doctrine.orm.entity_manager]
        tags:
         - { name: kernel.event_listener, event: kernel.controller, method: onCoreController }

用户实体

<?php

namespace Acme\SecurityBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;

/**
 * User
 *
 * @ORM\Table(name="users")
 * @ORM\Entity(repositoryClass="Acme\SecurityBundle\Entity\UserRepository")
 */
class User implements UserInterface
{

/**
     * @var \DateTime
     * @ORM\Column(name="LASTACTIVITY", type="datetime")
     */
    private $lastActivity;


    /**
     * @return bool whether the user is active or not
     */

    public function isActiveNow()
     {

    $delay = new\DateTime('2 minutes ago');

    return($this->getlastActivity()>$delay);

       }

/**
     * Set lastActivity
     *
     * @param\Datetime $lastActivity
     * @return User
     */


    public function setlastActivity($lastActivity)
    {
        $this->lastActivity = $lastActivity;

        return $this;
    }


    /**
     * Get lastActivity
     *
     * @return \DateTime
     */
    public function getlastActivity()
    {
        return $this->lastActivity;
    }




}

最佳答案

这里有一篇很棒的帖子:List online users .

您可以创建一个监听 kernel.controller 的监听器事件并在每次用户处于事件状态时更新用户字段 lastActivity。你可以查看lastActivity < now()- 2 minutes并更新 lastActivity 时间戳。

还有:Implementing user activity in symfony 2

方法如下

注意:如果您没有使用 FOSUserBundle，请参阅下面的编辑。

1 将此添加到您的用户实体

/**
 * Date/Time of the last activity
 *
 * @var \Datetime
 * @ORM\Column(name="last_activity_at", type="datetime")
 */
protected $lastActivityAt;

/**
 * @param \Datetime $lastActivityAt
 */
public function setLastActivityAt($lastActivityAt)
{
    $this->lastActivityAt = $lastActivityAt;
}

/**
 * @return \Datetime
 */
public function getLastActivityAt()
{
    return $this->lastActivityAt;
}

/**
 * @return Bool Whether the user is active or not
 */
public function isActiveNow()
{
    // Delay during wich the user will be considered as still active
    $delay = new \DateTime('2 minutes ago');

    return ( $this->getLastActivityAt() > $delay );
}

2 创建事件监听器

<?php
namespace Acme\UserBundle\EventListener;

use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\HttpKernel\HttpKernel;
use FOS\UserBundle\Model\UserManagerInterface;
use FOS\UserBundle\Model\UserInterface;

/**
 * Listener that updates the last activity of the authenticated user
 */
class ActivityListener
{
    protected $securityContext;
    protected $userManager;

    public function __construct(SecurityContext $securityContext, UserManagerInterface $userManager)
    {
        $this->securityContext = $securityContext;
        $this->userManager = $userManager;
    }

    /**
    * Update the user "lastActivity" on each request
    * @param FilterControllerEvent $event
    */
    public function onCoreController(FilterControllerEvent $event)
    {
        // Check that the current request is a "MASTER_REQUEST"
        // Ignore any sub-request
        if ($event->getRequestType() !== HttpKernel::MASTER_REQUEST) {
            return;
        }

        // Check token authentication availability
        if ($this->securityContext->getToken()) {
            $user = $this->securityContext->getToken()->getUser();

            if ( ($user instanceof UserInterface) && !($user->isActiveNow()) ) {
                $user->setLastActivityAt(new \DateTime());
                $this->userManager->updateUser($user);
            }
        }
    }
}

3 将事件监听器声明为服务

parameters:
    acme_user.activity_listener.class: Acme\UserBundle\EventListener\ActivityListener

services:
    acme_user.activity_listener:
        class: %acme_user.activity_listener.class%
        arguments: [@security.context, @fos_user.user_manager]
        tags:
            - { name: kernel.event_listener, event: kernel.controller, method: onCoreController }

一切顺利!

编辑(没有 FOSUserBundle)

1 将此添加到您的用户实体

Same as Step 1 Above

2 创建事件监听器

<?php
namespace Acme\UserBundle\EventListener;

use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\HttpKernel\HttpKernel;
use Doctrine\ORM\EntityManager;
use Acme\UserBundle\Entity\User;

/**
 * Listener that updates the last activity of the authenticated user
 */
class ActivityListener
{
    protected $securityContext;
    protected $entityManager;

    public function __construct(SecurityContext $securityContext, EntityManager $entityManager)
    {
        $this->securityContext = $securityContext;
        $this->entityManager = $entityManager;
    }

    /**
    * Update the user "lastActivity" on each request
    * @param FilterControllerEvent $event
    */
    public function onCoreController(FilterControllerEvent $event)
    {
        // Check that the current request is a "MASTER_REQUEST"
        // Ignore any sub-request
        if ($event->getRequestType() !== HttpKernel::MASTER_REQUEST) {
            return;
        }

        // Check token authentication availability
        if ($this->securityContext->getToken()) {
            $user = $this->securityContext->getToken()->getUser();

            if ( ($user instanceof User) && !($user->isActiveNow()) ) {
                $user->setLastActivityAt(new \DateTime());
                $this->entityManager->flush($user);
            }
        }
    }
}

3 将事件监听器声明为服务

parameters:
    acme_user.activity_listener.class: Acme\UserBundle\EventListener\ActivityListener

services:
    acme_user.activity_listener:
        class: %acme_user.activity_listener.class%
        arguments: [@security.context, @doctrine.orm.entity_manager]
        tags:
            - { name: kernel.event_listener, event: kernel.controller, method: onCoreController }

一切顺利!

关于php - Symfony 如何返回所有登录的事件用户，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21096689/