---

---

🧛‍♂️iecne个人主页：：iecne的学习日志
💡每天关注iecne的作品，一起进步
💪学C++必看iecne
本文专栏：【实战小项目】
🐳希望大家多多支持🥰一起进步呀！

---

✨前言

哈喽大家好，我是iecne，本期为大家带来的是CPP/C++【C++实战小项目】实现基本通讯录模拟详解分析。包教包会，快来看看吧！

任务描述

如何根据据C++基础入门编写一款不可视化通讯录，我们这次就来讲讲并且写一写添加用户

---

文章目录

• ✨前言
• • 任务描述
• 一.分析通讯录
• 二.删除
• • 2.1 Flowchat流程图
  • 2.2 string2_
• 三.查找
• • 3.1 Flowchart流程图
  • 3.2 三千字代码实现
• 四.修改
• • 4.1 Flowchart流程图
  • 4.2 代码实现
• 总结

---

一.分析通讯录

首先制作一款通讯录我们可以将它分为以下部分

增加联系人
删除联系人
查找联系人
修改联系人
打印通讯录
排序通讯录

这一期我们就来实现准备删除查找与修改

---

二.删除

删除是string2_函数，我们就来看看

2.1 Flowchat流程图

2.2 string2_

void string2_()
{
	string name1 = "请输入名字：>\n";
	out06(name1);
	string chaname;
	input_string(chaname);
	chaname = stringaaaa;
	int s = 0;
	int ss = 0;
	cout << " 姓名";
	for (int j = 1; j <= 12; j++)
	{
		cout << " ";
	}
	cout << "性别";
	for (int j = 1; j <= 10; j++)
	{
		cout << " ";
	}
	cout << "年龄";
	for (int j = 1; j <= 20 - 1; j++)
	{
		cout << " ";
	}
	cout << "电话";
	for (int j = 1; j <= 20; j++)
	{
		cout << " ";
	}
	cout << "地址";
	cout << "\n";
	for (int i = 1; i <= z - 1; i++)
	{
		if (namez[i] == chaname)
		{
			s++;
			ss = i;
			cout << " ";
			cout << namez[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << bgz[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << agez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << phonez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << homez[i];
			cout << "\n";
		}
	}
	if (s == 0)
	{
		cout << "没有找到这个人";
	}
	cout << "确认删除该联系人吗";
	cout << endl;
	cout << "1.yes";
	cout << endl << "2.no" << endl;
	int yesno1;
	cin >> yesno1;
	if (yesno1 == 1)
	{
		over(ss);
	}
	else
	{
		system("pause");
		playfirst();
	}
}

基本如图所示

---

三.查找

删除是string3_函数，我们来看看

3.1 Flowchart流程图

---

3.2 三千字代码实现

然后我们再看看code

void string3_()
{
	string string0 = "=====================================\n";
	string string1 = "============1.通过名字查=============\n";
	string string2 = "============2.通过性别查=============\n";
	string string3 = "============3.通过年龄查=============\n";
	string string4 = "============4.通过地址查=============\n";
	out06(string0);
	out06(string1);
	out06(string2);
	out06(string3);
	out06(string4);
	out06(string0);
	int string7 = 0;
	string7 = input(string7);
	switch (string7)
	{
	case 1:
		cha1_();
	case 2:
		cha2_();
	case 3:
		cha3_();
	case 4:
		cha4_();
	}
}

---

通过switch来分别到cha1_ ~ cha4_

void cha1_()
{
	string name1 = "请输入名字：>\n";
	out06(name1);
	string chaname;
	input_string(chaname);
	chaname = stringaaaa;
	int s = 0;
	cout << " 姓名";
	for (int j = 1; j <= 12; j++)
	{
		cout << " ";
	}
	cout << "性别";
	for (int j = 1; j <= 10; j++)
	{
		cout << " ";
	}
	cout << "年龄";
	for (int j = 1; j <= 20 - 1; j++)
	{
		cout << " ";
	}
	cout << "电话";
	for (int j = 1; j <= 20; j++)
	{
		cout << " ";
	}
	cout << "地址";
	cout << "\n";
	for (int i = 1; i <= z - 1; i++)
	{
		if (namez[i] == chaname)
		{
			s++;
			
			cout << " ";
			cout << namez[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << bgz[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << agez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << phonez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << homez[i];
			cout << "\n";
		}
	}
	if (s == 0)
	{
		cout << "没有找到这个人";
	}
	system("pause");
	playfirst();
}

void cha2_()
{
	string name1 = "请输入性别：>\n";
	out06(name1);
	string chaname;
	input_string(chaname);
	chaname = stringaaaa;
	if (chaname == "男")chaname = "男";
	else if (chaname == "女") chaname = "女";
	else chaname = "不男不女";
	cout << " 姓名";
	for (int j = 1; j <= 12; j++)
	{
		cout << " ";
	}
	cout << "性别";
	for (int j = 1; j <= 10; j++)
	{
		cout << " ";
	}
	cout << "年龄";
	for (int j = 1; j <= 20 - 1; j++)
	{
		cout << " ";
	}
	cout << "电话";
	for (int j = 1; j <= 20; j++)
	{
		cout << " ";
	}
	cout << "地址";
	cout << "\n";
	int s = 0;
	for (int i = 1; i <= z - 1; i++)
	{
		if (bgz[i] == chaname)
		{
			s++;
			cout << " ";
			cout << namez[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << bgz[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << agez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << phonez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << homez[i];
			cout << "\n";
		}
	}
	if (s == 0)
	{
		cout << "没有找到这个人";
	}
	system("pause");
	playfirst();
}

void cha3_()
{
	string name1 = "请输入年龄：>\n";
	out06(name1);
	int chaage;
	int s = 0;
	cin >> chaage;
	cout << " 姓名";
	for (int j = 1; j <= 12; j++)
	{
		cout << " ";
	}
	cout << "性别";
	for (int j = 1; j <= 10; j++)
	{
		cout << " ";
	}
	cout << "年龄";
	for (int j = 1; j <= 20 - 1; j++)
	{
		cout << " ";
	}
	cout << "电话";
	for (int j = 1; j <= 20; j++)
	{
		cout << " ";
	}
	cout << "地址";
	cout << "\n";
	cout << " ";
	for (int i = 1; i <= z - 1; i++)
	{
		if (agez[i] == chaage)
		{
			s++;
			cout << " 姓名";
			for (int j = 1; j <= 12; j++)
			{
				cout << " ";
			}
			cout << "性别";
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << "年龄";
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << "电话";
			for (int j = 1; j <= 20; j++)
			{
				cout << " ";
			}
			cout << "地址";
			cout << "\n";
			cout << " ";
			cout << namez[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << bgz[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << agez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << phonez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << homez[i];
			cout << "\n";
		}
	}
	if (s == 0)
	{
		cout << "没有找到这个人";
	}
	system("pause");
	playfirst();
}

void cha4_()
{
	string name1 = "请输入地址：>\n";
	out06(name1);
	string chaname;
	input_string(chaname);
	chaname = stringaaaa;
	int s = 0;
	cout << " 姓名";
	for (int j = 1; j <= 12; j++)
	{
		cout << " ";
	}
	cout << "性别";
	for (int j = 1; j <= 10; j++)
	{
		cout << " ";
	}
	cout << "年龄";
	for (int j = 1; j <= 20 - 1; j++)
	{
		cout << " ";
	}
	cout << "电话";
	for (int j = 1; j <= 20; j++)
	{
		cout << " ";
	}
	cout << "地址";
	cout << "\n";
	cout << " ";
	for (int i = 1; i <= z - 1; i++)
	{
		if (homez[i] == chaname)
		{
			s++;
			
			cout << namez[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << bgz[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << agez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << phonez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << homez[i];
			cout << "\n";
		}
	}
	if (s == 0)
	{
		cout << "没有找到这个人";
	}
	system("pause");
	playfirst();
}

---

四.修改

4.1 Flowchart流程图

---

4.2 代码实现

void string4_()
{
	printf("请输入需要修改信息用户的名字:>\n");
	string chaname;
	input_string(chaname);
	chaname = stringaaaa;
	int s = 0;
	cout << " 姓名";
	for (int j = 1; j <= 12; j++)
	{
		cout << " ";
	}
	cout << "性别";
	for (int j = 1; j <= 10; j++)
	{
		cout << " ";
	}
	cout << "年龄";
	for (int j = 1; j <= 20 - 1; j++)
	{
		cout << " ";
	}
	cout << "电话";
	for (int j = 1; j <= 20; j++)
	{
		cout << " ";
	}
	cout << "地址";
	cout << "\n";
	cout << " ";
	int ss = 0;
	for (int i = 1; i <= z - 1; i++)
	{
		if (namez[i] == chaname)
		{
			s++;
			ss = i;
			cout << namez[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << bgz[i];
			for (int j = 1; j <= 10; j++)
			{
				cout << " ";
			}
			cout << agez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << phonez[i];
			for (int j = 1; j <= 20 - 1; j++)
			{
				cout << " ";
			}
			cout << homez[i];
			cout << "\n";
		}
	}
	if (s == 0)
	{
		cout << "没有找到这个人";
		system("pause");
		playfirst();
	}
	printf(" \n0.退出 1.姓名 2.性别 3.年龄 4.电话 5.地址:>\n");
	int num;
	cin >> num;
	switch (num)
	{
	case 1:
		printf("请输入你想修改的姓名:>\n");
		cin >> namez[ss];
		break;
	case 2:
		printf("请输入你想修改的性别:>\n");
		cin >> bgz[ss];
		break;
	case 3:
		printf("请输入你想修改的年龄:>\n");
		cin >> agez[ss];
		break;
	case 4:
		printf("请输入你想修改的电话:>\n");
		cin >> phonez[ss];
		break;
	case 5:
		printf("请输入你想修改的地址:>\n");
		cin >> homez[ss];
		break;
	case 0:
		printf("不修改退回界面\n");
		break;
	default:printf("无效操作数！\n");
	}
	system("pause");
	playfirst();
}

---

总结

今天我们实现了通讯录的教程，至此该课示例的思想博主已经真真切切彻彻底底分享完了，相信大家对这个逻辑有了一定的理解，大家可以自己动手敲敲代码，感受一下，包教包会。若有任何侵权和不妥之处，请私信于我，定积极配合处理，看到必回！！！

帅的人已然点赞收藏关注，而丑的人还在犹豫，被犹豫了，快三连吧！
原创不易，还希望各位大佬支持一下
点赞，你的认可是我创作的动力！
收藏，你的青睐是我努力的方向！
评论，你的意见是我进步的财富！

---

感谢每一个观看本篇文章的朋友，更多精彩敬请期待～(￣▽￣～)~：
iecne的博客
若有任何侵权和不妥之处，请私信于我，定积极配合处理，看到必回！！！