我收到此错误:
android.database.sqlite.SQLiteException: no such table: setting (code 1): , while compiling: SELECT * FROM setting
但我已经在我的 DatabaseHandler 文件中创建了表:
public class DatabaseHandler extends SQLiteOpenHelper {
// Database Version
private static final int DATABASE_VERSION = 1;
// Database Name
private static final String DATABASE_NAME = "database.db";
//table name
private static final String TABLE_DETAILS = "details";
private static final String TABLE_FOOD = "food";
private static final String TABLE_OLDDETAILS = "oldDetails";
private static final String TABLE_SETTING = "setting";
//Table Columns names
private static final String KEY_ID = "id";
private static final String KEY_NAME = "name";
private static final String KEY_HEIGHT = "height";
private static final String KEY_WEIGHT = "weight";
private static final String KEY_CALORIES = "calories";
private static final String KEY_DATE = "date";
private static final String KEY_LEVEL = "level";
private static final String KEY_DURATION = "duration";
private static final String KEY_DAYS = "days";
public DatabaseHandler(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
// Creating Tables
@Override
public void onCreate(SQLiteDatabase db) {
String CREATE_DETAILS_TABLE = "CREATE TABLE IF NOT EXISTS " + TABLE_DETAILS + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_HEIGHT + " REAL," + KEY_WEIGHT + " REAL " + ")";
String CREATE_FOOD_TABLE = "CREATE TABLE IF NOT EXISTS " + TABLE_FOOD + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT," + KEY_CALORIES + " INTEGER " + ")";
String CREATE_OLDDETAILS_TABLE = "CREATE TABLE IF NOT EXISTS " + TABLE_OLDDETAILS + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_DATE + " TEXT," + KEY_HEIGHT + " REAL," + KEY_WEIGHT + " REAL " + ")";
String CREATE_SETTING_TABLE = "CREATE TABLE IF NOT EXISTS " + TABLE_SETTING + "("
+ KEY_ID + " INTEGER PRIMARY KEY," + KEY_LEVEL + " INTEGER," + KEY_DURATION + " INTEGER," + KEY_DAYS + " INTEGER " + ")";
db.execSQL(CREATE_OLDDETAILS_TABLE);
db.execSQL(CREATE_DETAILS_TABLE);
db.execSQL(CREATE_FOOD_TABLE);
db.execSQL(CREATE_SETTING_TABLE);
}
// Upgrading database
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// Drop older table if existed
db.execSQL("DROP TABLE IF EXISTS " + TABLE_DETAILS);
db.execSQL("DROP TABLE IF EXISTS " + TABLE_OLDDETAILS);
db.execSQL("DROP TABLE IF EXISTS " + TABLE_FOOD);
db.execSQL("DROP TABLE IF EXISTS " + TABLE_SETTING);
// Create tables again
onCreate(db);
}
public boolean addSetting(int level, int duration, int days) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_ID, 1);
values.put(KEY_LEVEL, level);
values.put(KEY_DURATION, duration);
values.put(KEY_DAYS, days);
// Inserting Row
long result = db.insert(TABLE_SETTING, null, values);
if(result == -1){
return false;
}
else{
return true;
}
}
public boolean checkSetting(){
SQLiteDatabase db = this.getWritableDatabase();
String selectQuery = "SELECT * FROM " + TABLE_SETTING;
Cursor cursor = db.rawQuery(selectQuery, null);
Boolean rowExists;
if (cursor.moveToFirst())
{
// DO SOMETHING WITH CURSOR
rowExists = true;
} else
{
// I AM EMPTY
rowExists = false;
}
return rowExists;
}
public setting getSetting() {
String selectQuery = "SELECT * FROM " + TABLE_SETTING;
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);
if (cursor != null)
cursor.moveToFirst();
setting set = new setting(cursor.getInt(1), cursor.getInt(2), cursor.getInt(3));
return set;
}
public int updateSetting(setting set) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_LEVEL, set.getLevel());
values.put(KEY_DURATION, set.getDuration());
values.put(KEY_DAYS, set.getDays());
Log.d("UPDATE: ", "updated all");
// updating row
return db.update(TABLE_SETTING, values, KEY_ID + " = ?", new String[] { String.valueOf(1) });
}
如您所见,有“CREATE IF NOT EXISTS”方法,我正在尝试创建它,尽管错误不断重复。
我试图在一个 fragment 中执行这个数据库代码,你可以看到 here到目前为止,这似乎不是问题所在,我认为主要是 DatabaseHandler。
如何正确创建表 SETTING 以便我可以从中进行选择?
最佳答案
您在应用程序已安装时更改了数据库结构,但 onCreate 只会执行一次,因此您有两个选项可以让您的更改反射(reflect)到数据库中
1.) 将数据库版本递增 1 以执行 onUpgrade 将更改应用到现有数据库
2.) 从手机上手动卸载应用程序以执行onCreate
关于java - 根据 android studio 编译器,数据库表不存在,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44218431/
我主要使用Ruby来执行此操作,但到目前为止我的攻击计划如下:使用gemsrdf、rdf-rdfa和rdf-microdata或mida来解析给定任何URI的数据。我认为最好映射到像schema.org这样的统一模式,例如使用这个yaml文件,它试图描述数据词汇表和opengraph到schema.org之间的转换:#SchemaXtoschema.orgconversion#data-vocabularyDV:name:namestreet-address:streetAddressregion:addressRegionlocality:addressLocalityphoto:i
我真的很习惯使用Ruby编写以下代码:my_hash={}my_hash['test']=1Java中对应的数据结构是什么? 最佳答案 HashMapmap=newHashMap();map.put("test",1);我假设? 关于java-等价于Java中的RubyHash,我们在StackOverflow上找到一个类似的问题: https://stackoverflow.com/questions/22737685/
我有一个用户工厂。我希望默认情况下确认用户。但是鉴于unconfirmed特征,我不希望它们被确认。虽然我有一个基于实现细节而不是抽象的工作实现,但我想知道如何正确地做到这一点。factory:userdoafter(:create)do|user,evaluator|#unwantedimplementationdetailshereunlessFactoryGirl.factories[:user].defined_traits.map(&:name).include?(:unconfirmed)user.confirm!endendtrait:unconfirmeddoenden
有时我需要处理键/值数据。我不喜欢使用数组,因为它们在大小上没有限制(很容易不小心添加超过2个项目,而且您最终需要稍后验证大小)。此外,0和1的索引变成了魔数(MagicNumber),并且在传达含义方面做得很差(“当我说0时,我的意思是head...”)。散列也不合适,因为可能会不小心添加额外的条目。我写了下面的类来解决这个问题:classPairattr_accessor:head,:taildefinitialize(h,t)@head,@tail=h,tendend它工作得很好并且解决了问题,但我很想知道:Ruby标准库是否已经带有这样一个类? 最佳
我正在尝试使用boilerpipe来自JRuby。我看过guide从JRuby调用Java,并成功地将它与另一个Java包一起使用,但无法弄清楚为什么同样的东西不能用于boilerpipe。我正在尝试基本上从JRuby中执行与此Java等效的操作:URLurl=newURL("http://www.example.com/some-location/index.html");Stringtext=ArticleExtractor.INSTANCE.getText(url);在JRuby中试过这个:require'java'url=java.net.URL.new("http://www
我只想对我一直在思考的这个问题有其他意见,例如我有classuser_controller和classuserclassUserattr_accessor:name,:usernameendclassUserController//dosomethingaboutanythingaboutusersend问题是我的User类中是否应该有逻辑user=User.newuser.do_something(user1)oritshouldbeuser_controller=UserController.newuser_controller.do_something(user1,user2)我
我的模型有defself.empty_building//stuffend我怎样才能对这个现有的进行rspec?,已经尝试过:describe"empty_building"dosubject{Building.new}it{shouldrespond_to:empty_building}endbutgetting:Failure/Error:it{shouldrespond_to:empty_building}expected#torespondto:empty_building 最佳答案 你有一个类方法self.empty_bu
什么是ruby的rack或python的Java的wsgi?还有一个路由库。 最佳答案 来自Python标准PEP333:Bycontrast,althoughJavahasjustasmanywebapplicationframeworksavailable,Java's"servlet"APImakesitpossibleforapplicationswrittenwithanyJavawebapplicationframeworktoruninanywebserverthatsupportstheservletAPI.ht
我正在尝试使用Curbgem执行以下POST以解析云curl-XPOST\-H"X-Parse-Application-Id:PARSE_APP_ID"\-H"X-Parse-REST-API-Key:PARSE_API_KEY"\-H"Content-Type:image/jpeg"\--data-binary'@myPicture.jpg'\https://api.parse.com/1/files/pic.jpg用这个:curl=Curl::Easy.new("https://api.parse.com/1/files/lion.jpg")curl.multipart_form_
无论您是想搭建桌面端、WEB端或者移动端APP应用,HOOPSPlatform组件都可以为您提供弹性的3D集成架构,同时,由工业领域3D技术专家组成的HOOPS技术团队也能为您提供技术支持服务。如果您的客户期望有一种在多个平台(桌面/WEB/APP,而且某些客户端是“瘦”客户端)快速、方便地将数据接入到3D应用系统的解决方案,并且当访问数据时,在各个平台上的性能和用户体验保持一致,HOOPSPlatform将帮助您完成。利用HOOPSPlatform,您可以开发在任何环境下的3D基础应用架构。HOOPSPlatform可以帮您打造3D创新型产品,HOOPSSDK包含的技术有:快速且准确的CAD