基本上它应该以这种格式列出所有 vector 坐标:

(x, y, z)

但目前它确实是这样的 (x, y, z, )

最简单的方法是在 for 循环中使用 if，但我可以从 out 变量中减去一小段字符串吗？

我的代码:

    template <unsigned short m>
    std::ostream& operator<<(std::ostream& out, const Vector<m>& v) {
    out << "(";
    for(int i = 0; i < m; i++) {
        out << v.coords[i] << ", ";
    }
    out << ")";
    return out;
}

最佳答案

这是我的旧代码库。从好的方面来说:它带有单元测试:

Updated for modern times, more generic and self contained Live On Coliru

/*! note: delimiter cannot contain NUL characters
 */
template <typename Range, typename Value = typename Range::value_type>
std::string Join(Range const& elements, const char *const delimiter) {
    std::ostringstream os;
    auto b = begin(elements), e = end(elements);

    if (b != e) {
        std::copy(b, prev(e), std::ostream_iterator<Value>(os, delimiter));
        b = prev(e);
    }
    if (b != e) {
        os << *b;
    }

    return os.str();
}

/*! note: imput is assumed to not contain NUL characters
 */
template <typename Input, typename Output, typename Value = typename Output::value_type>
void Split(char delimiter, Output &output, Input const& input) {
    using namespace std;
    for (auto cur = begin(input), beg = cur; ; ++cur) {
        if (cur == end(input) || *cur == delimiter || !*cur) {
            output.insert(output.end(), Value(beg, cur));
            if (cur == end(input) || !*cur)
                break;
            else
                beg = next(cur);
        }
    }
}

以及一些相应的单元测试用例:

void testSplit() {
    std::vector<std::string> res;
    const std::string test = "a test ,string, to,,,be, split,\"up,up\",";
    TextUtils::Split(',', res, test);

    UT_EQUAL(10u, res.size());
    UT_EQUAL("a test ", res[0]);
    UT_EQUAL("string", res[1]);
    UT_EQUAL(" to", res[2]);
    UT_EQUAL("", res[3]);
    UT_EQUAL("", res[4]);
    UT_EQUAL("be", res[5]);
    UT_EQUAL(" split", res[6]);
    UT_EQUAL("\"up", res[7]); // Thus making 'split' unusable for parsing
    UT_EQUAL("up\"", res[8]); //  csv files...
    UT_EQUAL("", res[9]);

    TextUtils::Split('.', res, "dossier_id");
    UT_EQUAL(11u, res.size());

    res.clear();
    UT_EQUAL(0u, res.size());

    TextUtils::Split('.', res, "dossier_id");
    UT_EQUAL(1u, res.size());
    std::string UseName = res[res.size() - 1];
    UT_EQUAL("dossier_id", UseName);
}

void testJoin() {
    std::string elements[] = { "aap", "noot", "mies" };

    typedef std::vector<std::string> strings;

    UT_EQUAL(""               , TextUtils::Join(strings(), ""));
    UT_EQUAL(""               , TextUtils::Join(strings(), "bla"));
    UT_EQUAL("aap"            , TextUtils::Join(strings(elements, elements + 1), ""));
    UT_EQUAL("aap"            , TextUtils::Join(strings(elements, elements + 1), "#"));
    UT_EQUAL("aap"            , TextUtils::Join(strings(elements, elements + 1), "##"));
    UT_EQUAL("aapnoot"        , TextUtils::Join(strings(elements, elements + 2), ""));
    UT_EQUAL("aap#noot"       , TextUtils::Join(strings(elements, elements + 2), "#"));
    UT_EQUAL("aap##noot"      , TextUtils::Join(strings(elements, elements + 2), "##"));
    UT_EQUAL("aapnootmies"    , TextUtils::Join(strings(elements, elements + 3), ""));
    UT_EQUAL("aap#noot#mies"  , TextUtils::Join(strings(elements, elements + 3), "#"));
    UT_EQUAL("aap##noot##mies", TextUtils::Join(strings(elements, elements + 3), "##"));
    UT_EQUAL("aap  noot  mies", TextUtils::Join(strings(elements, elements + 3), "  "));

    UT_EQUAL("aapnootmies"    , TextUtils::Join(strings(elements, elements + 3), "\0"));
    UT_EQUAL("aapnootmies"    , TextUtils::Join(strings(elements, elements + 3), std::string("\0" , 1).c_str()));
    UT_EQUAL("aapnootmies"    , TextUtils::Join(strings(elements, elements + 3), std::string("\0+", 2).c_str()));
    UT_EQUAL("aap+noot+mies"  , TextUtils::Join(strings(elements, elements + 3), std::string("+\0", 2).c_str()));
}

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关于C++ ostream 输出操作，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/5288396/