我有一些基本代码可以循环访问从 Adob​​e RoboHelp(用于我们的帮助文档)生成的一些 XML。这工作正常，但由于一个主题可以嵌套任意多次，我需要一种更好的方法来循环遍历这个 XML，而不是仅仅嵌套 .each()。循环。

这是 XML 的样子

<?xml version="1.0" encoding="utf-8"?>
<!--RoboML: Table of Content-->
<roboml_toc>
  <page title="Welcome" url="Welcome.htm"/>
 <book title="Getting Started" url="Getting_Started/Initial_Setup.htm">
   <page title="Initial Setup" url="Getting_Started/Initial_Setup.htm"/>
   <page title="Customize Settings" url="Getting_Started/Settings.htm"/>
 </book>
 <book title="Administrator Services" url="Administrator_Services/General_Administrator.htm">
  <book title="Portal Workspace" url="Administrator_Services/Portal_Workspace/AdminHome.htm">
    <page title="Home" url="Administrator_Services/Portal_Workspace/AdminHome.htm"/>
    <page title="Portal Accounts" url="Administrator_Services/Portal_Workspace/Portal_Accounts.htm"/>

  </book>
  <book title="SpamLab" url="Administrator_Services/SpamLab/SpamLab_Admin_General.htm">
    <page title="Alerts" url="Administrator_Services/SpamLab/Alerts.htm"/>
    <page title="Spam Quarantine" url="Administrator_Services/SpamLab/Admin_Spam_Quarantine_.htm"/>

  </book>

 </book>
 <book title="User Services" url="User_Services/General_User.htm">
  <book title="Portal Workspace" url="User_Services/Portal_Workspace/Home.htm">
    <page title="Home" url="User_Services/Portal_Workspace/Home.htm"/>
    <page title="Self Help" url="User_Services/Portal_Workspace/Self_Help.htm"/>
  </book>
  <book title="SpamLab" url="User_Services/SpamLab/SpamLab_General.htm">
    <page title="Spam Quarantine" url="User_Services/SpamLab/Spam_Quarantine.htm"/>
    <page title="Virus Quarantine" url="User_Services/SpamLab/Virus_Quarantine.htm"/>
  </book>

  <book title="Encryption" url="User_Services/Encryption/Encryption_General.htm">
    <page title="Outlook Plug-in" url="User_Services/Encryption/Encryption_Outlook_Plug_in.htm"/>
  </book>
 </book>
</roboml_toc>

A <page>是一篇文章，一个<book>是一个文件夹。

她是我的 jQuery 代码，只能查看一层深的标签

   //Get the TOC
$tocOutput="";
$.get(tocURL,function(toc){
    $(toc).children().each(function(){
        $tocOutput+="<li><a href='"+$(this).attr("url")+"'>"+$(this).attr("title")+"</a>";
        if(this.tagName=="BOOK"){
            $tocOutput+="<ul>";
            $(this).find("page").each(function(){
                $tocOutput+="<li><a href='"+$(this).attr("url")+"'>"+$(this).attr("title")+"</a></li>";
            });
            $tocOutput+="</ul>";
        }
        $tocOutput+="</li>";
    });
    $("#list").html($tocOutput);

我知道有一个更好的方法来遍历所有元素，然后确定该元素是否有子元素等。但我就是想不出该怎么做。

非常感谢任何帮助!

最佳答案

递归函数对此很有效。当您创建一个创建并使用内部递归闭包的函数时，您可以将其全部包装在一个整洁的小包中:

    $.get(tocURL, function(toc) {
    function makeToc($xml) {
        // variable to accumulate markup
        var markup = "";
        // worker function local to makeToc
        function processXml() {
            markup += "<li><a href='" + $(this).attr("url") + "'>" + $(this).attr("title") + "</a>";
            if (this.nodeName == "BOOK") {
                markup += "<ul>";
                // recurse on book children
                $(this).find("page").each(processXml);
                markup += "</ul>";
            }
            markup += "</li>";
        }
        // call worker function on all children
        $xml.children().each(processXml);
        return markup;
    }
    var tocOutput = makeToc($(toc));
    $("#list").html(tocOutput);
});

关于jquery - 使用 jQuery 遍历 XML，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1574113/