我有一个简单的类，它在我的程序获得和失去焦点时停止和启动计时器，但它给出了错误，即 QObject 在每个信号槽连接上都是 MyApp 的模糊基础。 相关代码如下:

class MyApp : public QApplication, public QObject
{
    Q_OBJECT
    ...
}

这是我的(凌乱的)Main.cpp:

    #include <QtGui/QApplication>
    #include "qmlapplicationviewer.h"
    #include <QObject>
    #include <QGraphicsObject>
    #include <QTimer>
    #include <QVariant>
    #include "timecontrol.h"
    #include "scorecontrol.h"
    #include "Retry.h"
    #include <QEvent>
    #include "myapp.h"

    int main(int argc, char *argv[])
    {
        MyApp app(argc, argv);

        QmlApplicationViewer viewer;
        viewer.setOrientation(QmlApplicationViewer::ScreenOrientationLockLandscape);
        viewer.setMainQmlFile(QLatin1String("qml/Raker/main.qml"));
        viewer.showExpanded();

        QObject *rootObject = viewer.rootObject();

        QTimer *timmer = new QTimer;
        timmer->setInterval(1000);

        TimeControl *timcon = new TimeControl;

        scorecontrol *scorer = new scorecontrol;

        Retry *probeer = new Retry;

        QObject::connect(timmer, SIGNAL(timeout()), timcon, SLOT(updateTime()));
        QObject::connect(timcon, SIGNAL(setTime(QVariant)), rootObject, SLOT(setTime(QVariant)));
        QObject::connect(rootObject, SIGNAL(blockClicked(int, int)), scorer, SLOT(checkRight(int, int)));
        QObject::connect(scorer, SIGNAL(setScore(QVariant)), rootObject, SLOT(setScore(QVariant)));
        QObject::connect(scorer, SIGNAL(setState(QVariant)), rootObject, SLOT(setState(QVariant)));

        QObject::connect(rootObject, SIGNAL(start()), probeer, SLOT(Reetry()));
        QObject::connect(probeer, SIGNAL(start()), timmer, SLOT(start()));
        QObject::connect(probeer, SIGNAL(stop()), timmer, SLOT(stop()));
        QObject::connect(probeer, SIGNAL(start(int)), scorer, SLOT(randomNum(int)));
        QObject::connect(probeer, SIGNAL(sReset()), timcon, SLOT(reset()));
        QObject::connect(probeer, SIGNAL(tReset()), scorer, SLOT(reset()));
        QObject::connect(timcon, SIGNAL(timeOut()), scorer, SLOT(reset()));

        QObject::connect(timcon, SIGNAL(setState(QVariant)), rootObject, SLOT(setState(QVariant)));
        QObject::connect(timcon, SIGNAL(changeFinal()), scorer, SLOT(changeFinal()));
        QObject::connect(scorer, SIGNAL(setFinal(QVariant)), rootObject, SLOT(setFinal(QVariant)));

        QObject::connect(&app, SIGNAL(focusL()), probeer, SLOT(focusL()));
        QObject::connect(&app, SIGNAL(focusG()), probeer, SLOT(focusG()));

        return app.exec();
    }

MyApp.cpp:

    #include "myapp.h"
    #include <QDebug>
    #include <QObject>

    MyApp::MyApp(int argc, char **argv): QApplication(argc, argv)
    {
        installEventFilter(this);
    }

    bool MyApp::eventFilter(QObject *object, QEvent *event)
    {
        if (event->type() == QEvent::ApplicationDeactivate)
        {
            qDebug() << "Focus lost";
            focusL();
        }
        if (event->type() == QEvent::ApplicationActivate)
        {
            qDebug() << "Focus gained";
            focusG();
        }

        return false;
    }

最佳答案

在您当前的示例中，您已经创建了一个拆分继承方案，其中您的对象以 QObject 的双重实例结束......有一个基础 QObject用于QApplication，另一个用于实际的MyApp 类。这会产生歧义，因为访问继承的 QObject 方法或数据成员将不知道要访问哪个继承的基础对象。

现在，您的继承关系图如下所示(注意 MyApp 对象继承的两个 QObject 实例):

 | QObject |         | QObject |
       \                 /
        \         | QApplication |
         \             /
          \           /
         |    MyApp    |

您应该使继承图保持线性，而不是采用拆分继承方案，这意味着派生类只包含基类的一个实例。所以你想要这样的东西:

    QObject
       |
       |
  QApplication
       |
       |
     MyApp

关于c++ - QObject 继承 Ambiguous Base，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7903342/