我是 SOAP API 的新手

我有一个来自 API 的 soap 响应

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<LoginResponse xmlns="http://test.org/ADMail_Service">
<LoginResult>
<ErrorMessage>Successful login</ErrorMessage>
<Status>true</Status>
</LoginResult>
</LoginResponse>
</soapenv:Body>
</soapenv:Envelope>

我正在尝试将其转换为一个对象。

通过在线阅读文章，我尝试使用 JAXB 来执行此操作，但我的对象是空的。

这是读取响应的代码。为了测试目的，我将响应写入了一个 xml 文件:

try {
    XMLInputFactory xif = XMLInputFactory.newFactory();
    XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
    xsr.nextTag(); // Advance to Envelope tag

    xsr.nextTag(); // Advance to Body tag
    xsr.nextTag();
    xsr.nextTag();


    JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
    Unmarshaller unmarshaller = jc.createUnmarshaller();
    JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

    System.out.println(je.getName());
    System.out.println(je.getValue());
} catch (XMLStreamException e) {
    e.printStackTrace();
} catch (JAXBException e) {
    e.printStackTrace();
} catch (FileNotFoundException e) {
    e.printStackTrace();
}

LoginResult 类:

public class LoginResult {
    private String errorMessage;
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}

提前致谢!

最佳答案

您可以使用此代码检索 POJO，并将 @XmlRootElement 作为 header 添加到您的 POJO。

(我没有测试下面的代码)

XMLInputFactory xif = XMLInputFactory.newFactory();
        XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
        xsr.nextTag(); // Advance to Envelope tag

        xsr.nextTag(); // Advance to Body tag
        xsr.nextTag();
        xsr.nextTag();

        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        StringWriter stringWriter = new StringWriter();
        transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
        StringReader sr = new StringReader(stringWriter.toString());
        JAXBContext jaxbContext = JAXBContext.newInstance(LoginResult.class);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        LoginResult loginResult = (LoginResult) unmarshaller.unmarshal(sr);

编辑:

我为您找到了解决方案:

    @XmlRootElement(name = "LoginResult", namespace = "http://test.org/ADMail_Service")
@XmlAccessorType(XmlAccessType.FIELD)
public class LoginResult {
    @XmlElement(name = "ErrorMessage", namespace = "http://test.org/ADMail_Service")
    private String errorMessage;
    @XmlElement(name = "Status", namespace = "http://test.org/ADMail_Service")
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}


public static void main(String[] args) {
        try {
            XMLInputFactory xif = XMLInputFactory.newFactory();
            XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
            xsr.nextTag(); // Advance to Envelope tag

            xsr.nextTag(); // Advance to Body tag
            xsr.nextTag();
            xsr.nextTag();


            JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
            Unmarshaller unmarshaller = jc.createUnmarshaller();
            JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

            System.out.println(je.getName());
            System.out.println(je.getValue());
            System.out.println(je.getValue().getErrorMessage());
        } catch (XMLStreamException e) {
            e.printStackTrace();
        } catch (JAXBException e) {
            e.printStackTrace();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }

    }

关于java - 将 Soap XML 响应转换为对象，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47333185/