我没有收到错误，请你帮我解决一下，这是 .l 和 .y 文件。谢谢。

%{
#include "ifanw.tab.h"
extern int yylval;
%}
%%
"="      { return EQ; }
"!="     { return NE; }
"<"      { return LT; }
"<="     { return LE; }
">"      { return GT; }
">="     { return GE; }
"+"      { return PLUS; }
"-"      { return MINUS; }
"*"      { return MULT; }
"/"      { return DIVIDE; }
")"      { return RPAREN; }
"("      { return LPAREN; }
":="     { return ASSIGN; }
";"      { return SEMICOLON; }
"IF"     { return IF; }
"THEN"   { return THEN; }
"ELSE"   { return ELSE; }
"FI"     { return FI; }
"WHILE"  { return WHILE; }
"DO"     { return DO; }
"OD"     { return OD; }
"PRINT"  { return PRINT; }
[0-9]+   { yylval = atoi(yytext); return NUMBER; }
[a-z]    { yylval = yytext[0] - 'a'; return NAME; }   
\        { ; }
\n       { nextline(); }
\t       { ; }
"//".*\n { nextline(); }
.        { yyerror("illegal token"); }
%%

Yacc 文件

%start ROOT

%token EQ
%token NE
%token LT
%token LE
%token GT
%token GE
%token PLUS
%token MINUS
%token MULT
%token DIVIDE
%token RPAREN
%token LPAREN
%token ASSIGN
%token SEMICOLON
%token IF
%token THEN
%token ELSE
%token FI
%token WHILE
%token DO
%token OD
%token PRINT
%token NUMBER
%token NAME

%%

ROOT:
   stmtseq { execute($1); } 
   ;

statement:
     designator ASSIGN expression { $$ = assignment($1, $3); } 
   | PRINT expression { $$ = print($2); } 
   | IF expression THEN stmtseq ELSE stmtseq FI
    { $$ = ifstmt($2, $4, $6); }
   | IF expression THEN stmtseq FI
    { $$ = ifstmt($2, $4, empty()); }
   | WHILE expression DO stmtseq OD { $$ = whilestmt($2, $4); }   
   ;

stmtseq:
     stmtseq SEMICOLON statement { $$ = seq($1, $3); }
   | statement { $$ = $1; }
   ;

expression:
 expr2 { $$ = $1; } 
   | expr2 EQ expr2 { $$ = eq($1, $3); }
   | expr2 NE expr2 { $$ = ne($1, $3); }
   | expr2 LT expr2 { $$ = le($1, $3); }
   | expr2 LE expr2 { $$ = le($1, $3); }
   | expr2 GT expr2 { $$ = gt($1, $3); }
   | expr2 GE expr2 { $$ = gt($1, $3); }
   ;

expr2:
     expr3 { $$ == $1; }
   | expr2 PLUS expr3 { $$ = plus($1, $3); }
   | expr2 MINUS expr3 { $$ = minus($1, $3); }
   ;

expr3:
     expr4 { $$ = $1; }
   | expr3 MULT expr4 { $$ = mult($1, $3); }
   | expr3 DIVIDE expr4 { $$ = divide ($1, $3); }
   ;

expr4:
     PLUS expr4 { $$ = $2; }
   | MINUS expr4 { $$ = neg($2); }
   | LPAREN expression RPAREN { $$ = $2; }
   | NUMBER { $$ = number($1); }
   | designator { $$ = $1; }
   ;

designator:
     NAME { $$ = name($1); }
  ;
%%

我还有一个问题， 是否有可能像在汇编程序中那样使用 flex/bison 实现 JMP 指令以转到像我的示例这样的标签，感谢您的帮助。

:L1
IF FLAG AND X"0001"
    EVT 23;
ELSE
    WAIT 500 ms;
    JMP L1;
END IF; 

最佳答案

编辑:我把旧答案放在最后

这是 promise 的更详细的示例:

通常我从所需语言的示例文件开始:

# example.toy
begin # example of the simple toy language
    x = 23;
    while x > 0 do begin
        x = x - 1;
        print(x*x);
    end;
end;

下一步是创建一个词法分析器+解析器组合，其中之前的文件 通过。

词法分析器来了(使用 flex -o lexer.c lexer.l 生成源代码)。另请注意，词法分析器源代码依赖于解析器源代码(因为 TOKEN_* 常量)，因此必须在编译词法分析器源代码之前运行 bison:

%option noyywrap

%{
#include "parser.h"
#include <stdlib.h>
%}

%%

"while" return TOKEN_WHILE;
"begin" return TOKEN_BEGIN;
"end"   return TOKEN_END;
"do"    return TOKEN_DO;
[a-zA-Z_][a-zA-Z0-9_]* {yylval.name = strdup(yytext); return TOKEN_ID;}
[-]?[0-9]+    {yylval.val = atoi(yytext); return TOKEN_NUMBER;}
[()=;]  {return *yytext;}
[*/+-<>] {yylval.op = *yytext; return TOKEN_OPERATOR;}
[ \t\n] {/* suppress the output of the whitespaces from the input file to stdout */}
#.* {/* one-line comment */}

和解析器(用 bison -d -o parser.c parser.y 编译，-d 告诉 bison 用词法分析器需要的东西创建 parser.h 头文件)

%error-verbose /* instruct bison to generate verbose error messages*/
%{
/* enable debugging of the parser: when yydebug is set to 1 before the
 * yyparse call the parser prints a lot of messages about what it does */
#define YYDEBUG 1
%}

%union {
    int val;
    char op;
    char* name;
}

%token TOKEN_BEGIN TOKEN_END TOKEN_WHILE TOKEN_DO TOKEN_ID TOKEN_NUMBER TOKEN_OPERATOR
%start program

%{
/* Forward declarations */
void yyerror(const char* const message);


%}

%%

program: statement';';

block: TOKEN_BEGIN statements TOKEN_END;

statements:
    | statements statement ';'
    | statements block';';

statement: 
      assignment
    | whileStmt
    | block
    | call;

assignment: TOKEN_ID '=' expression;

expression: TOKEN_ID
    | TOKEN_NUMBER
    | expression TOKEN_OPERATOR expression;

whileStmt: TOKEN_WHILE expression TOKEN_DO statement;

call: TOKEN_ID '(' expression ')';

%%

#include <stdlib.h>

void yyerror(const char* const message)
{
    fprintf(stderr, "Parse error:%s\n", message);
    exit(1);
}

int main()
{
    yydebug = 0;
    yyparse();
}

在 gcc parser.c lexer.c -o toylang-noop 之后toylang-noop < example.toy的来电必须运行无任何错误。所以现在解析器本身可以工作并可以解析示例脚本。

下一步是创建所谓的语法抽象语法树。在这一点上，我通过为标记和规则定义不同的类型以及在每个解析步骤中插入规则来增强解析器。

%error-verbose /* instruct bison to generate verbose error messages*/
%{
#include "astgen.h"
#define YYDEBUG 1

/* Since the parser must return the AST, it must get a parameter where
 * the AST can be stored. The type of the parameter will be void*. */
#define YYPARSE_PARAM astDest
%}

%union {
    int val;
    char op;
    char* name;
    struct AstElement* ast; /* this is the new member to store AST elements */
}

%token TOKEN_BEGIN TOKEN_END TOKEN_WHILE TOKEN_DO
%token<name> TOKEN_ID
%token<val> TOKEN_NUMBER
%token<op> TOKEN_OPERATOR
%type<ast> program block statements statement assignment expression whileStmt call
%start program

%{
/* Forward declarations */
void yyerror(const char* const message);


%}

%%

program: statement';' { (*(struct AstElement**)astDest) = $1; };

block: TOKEN_BEGIN statements TOKEN_END{ $$ = $2; };

statements: {$$=0;}
    | statements statement ';' {$$=makeStatement($1, $2);}
    | statements block';' {$$=makeStatement($1, $2);};

statement: 
      assignment {$$=$1;}
    | whileStmt {$$=$1;}
    | block {$$=$1;}
    | call {$$=$1;}

assignment: TOKEN_ID '=' expression {$$=makeAssignment($1, $3);}

expression: TOKEN_ID {$$=makeExpByName($1);}
    | TOKEN_NUMBER {$$=makeExpByNum($1);}
    | expression TOKEN_OPERATOR expression {$$=makeExp($1, $3, $2);}

whileStmt: TOKEN_WHILE expression TOKEN_DO statement{$$=makeWhile($2, $4);};

call: TOKEN_ID '(' expression ')' {$$=makeCall($1, $3);};

%%

#include "astexec.h"
#include <stdlib.h>

void yyerror(const char* const message)
{
    fprintf(stderr, "Parse error:%s\n", message);
    exit(1);
}

int main()
{
    yydebug = 0;
    struct AstElement *a;
    yyparse(&a);
}

如您所见，生成 AST 的主要部分是创建节点 通过解析器的某个规则时的 AST。由于 Bison 保持 当前解析过程本身的堆栈，只需要分配 当前对堆栈元素的解析状态 (这些是 $$=foo(bar) 行)

目标是内存中的如下结构:

ekStatements
  .count = 2
  .statements
    ekAssignment
      .name = "x"
      .right
        ekNumber
          .val = 23
    ekWhile
      .cond
        ekBinExpression
        .left
          ekId
            .name = "x"
        .right
          ekNumber
            .val=0
        .op = '>'
      .statements
        ekAssignment
          .name = "x"
          .right
            ekBinExpression
              .left
                ekId
                  .name = "x"
              .right
                ekNumber
                  .val = 1
              .op = '-'
        ekCall
          .name = "print"
          .param
            ekBinExpression
              .left
                ekId
                  .name = "x"
              .right
                ekId
                  .name = "x"
              .op = '*'

要得到这个图，需要生成代码，astgen.h:

#ifndef ASTGEN_H
#define ASTGEN_H

struct AstElement
{
    enum {ekId, ekNumber, ekBinExpression, ekAssignment, ekWhile, ekCall, ekStatements, ekLastElement} kind;
    union
    {
        int val;
        char* name;
        struct
        {
            struct AstElement *left, *right;
            char op;
        }expression;
        struct
        {
            char*name;
            struct AstElement* right;
        }assignment;
        struct
        {
            int count;
            struct AstElement** statements;
        }statements;
        struct
        {
            struct AstElement* cond;
            struct AstElement* statements;
        } whileStmt;
        struct
        {
            char* name;
            struct AstElement* param;
        }call;
    } data;
};

struct AstElement* makeAssignment(char*name, struct AstElement* val);
struct AstElement* makeExpByNum(int val);
struct AstElement* makeExpByName(char*name);
struct AstElement* makeExp(struct AstElement* left, struct AstElement* right, char op);
struct AstElement* makeStatement(struct AstElement* dest, struct AstElement* toAppend);
struct AstElement* makeWhile(struct AstElement* cond, struct AstElement* exec);
struct AstElement* makeCall(char* name, struct AstElement* param);
#endif

astgen.c:

#include "astgen.h"
#include <stdio.h>
#include <stdlib.h>
#include <assert.h>

static void* checkAlloc(size_t sz)
{
    void* result = calloc(sz, 1);
    if(!result)
    {
        fprintf(stderr, "alloc failed\n");
        exit(1);
    }
}

struct AstElement* makeAssignment( char*name, struct AstElement* val)
{
    struct AstElement* result = checkAlloc(sizeof(*result));
    result->kind = ekAssignment;
    result->data.assignment.name = name;
    result->data.assignment.right = val;
    return result;
}

struct AstElement* makeExpByNum(int val)
{
    struct AstElement* result = checkAlloc(sizeof(*result));
    result->kind = ekNumber;
    result->data.val = val;
    return result;
}

struct AstElement* makeExpByName(char*name)
{
    struct AstElement* result = checkAlloc(sizeof(*result));
    result->kind = ekId;
    result->data.name = name;
    return result;
}

struct AstElement* makeExp(struct AstElement* left, struct AstElement* right, char op)
{
    struct AstElement* result = checkAlloc(sizeof(*result));
    result->kind = ekBinExpression;
    result->data.expression.left = left;
    result->data.expression.right = right;
    result->data.expression.op = op;
    return result;
}

struct AstElement* makeStatement(struct AstElement* result, struct AstElement* toAppend)
{
    if(!result)
    {
        result = checkAlloc(sizeof(*result));
        result->kind = ekStatements;
        result->data.statements.count = 0;
        result->data.statements.statements = 0;
    }
    assert(ekStatements == result->kind);
    result->data.statements.count++;
    result->data.statements.statements = realloc(result->data.statements.statements, result->data.statements.count*sizeof(*result->data.statements.statements));
    result->data.statements.statements[result->data.statements.count-1] = toAppend;
    return result;
}

struct AstElement* makeWhile(struct AstElement* cond, struct AstElement* exec)
{
    struct AstElement* result = checkAlloc(sizeof(*result));
    result->kind = ekWhile;
    result->data.whileStmt.cond = cond;
    result->data.whileStmt.statements = exec;
    return result;
}

struct AstElement* makeCall(char* name, struct AstElement* param)
{
    struct AstElement* result = checkAlloc(sizeof(*result));
    result->kind = ekCall;
    result->data.call.name = name;
    result->data.call.param = param;
    return result;
}

你可以在这里看到 AST 元素的生成是相当单调的 工作。步骤完成后，程序仍然什么都不做，但是AST可以 在调试器中查看。

下一步是编写解释器。这是 astexec.h:

#ifndef ASTEXEC_H
#define ASTEXEC_H

struct AstElement;
struct ExecEnviron;

/* creates the execution engine */
struct ExecEnviron* createEnv();

/* removes the ExecEnviron */
void freeEnv(struct ExecEnviron* e);

/* executes an AST */
void execAst(struct ExecEnviron* e, struct AstElement* a);

#endif

嗯，这看起来很友好。解释器本身很简单，尽管它是 长度。大多数函数只处理特定种类的 AstElement。这 dispatchExpression 和 dispatchStatement 选择了正确的函数 功能。调度函数在 valExecs 中查找目标函数 和 runExecs 数组。

astexec.c:

#include "astexec.h"
#include "astgen.h"
#include <stdlib.h>
#include <assert.h>
#include <stdio.h>

struct ExecEnviron
{
    int x; /* The value of the x variable, a real language would have some name->value lookup table instead */
};

static int execTermExpression(struct ExecEnviron* e, struct AstElement* a);
static int execBinExp(struct ExecEnviron* e, struct AstElement* a);
static void execAssign(struct ExecEnviron* e, struct AstElement* a);
static void execWhile(struct ExecEnviron* e, struct AstElement* a);
static void execCall(struct ExecEnviron* e, struct AstElement* a);
static void execStmt(struct ExecEnviron* e, struct AstElement* a);

/* Lookup Array for AST elements which yields values */
static int(*valExecs[])(struct ExecEnviron* e, struct AstElement* a) =
{
    execTermExpression,
    execTermExpression,
    execBinExp,
    NULL,
    NULL,
    NULL,
    NULL
};

/* lookup array for non-value AST elements */
static void(*runExecs[])(struct ExecEnviron* e, struct AstElement* a) =
{
    NULL, /* ID and numbers are canonical and */
    NULL, /* don't need to be executed */
    NULL, /* a binary expression is not executed */
    execAssign,
    execWhile,
    execCall,
    execStmt,
};

/* Dispatches any value expression */
static int dispatchExpression(struct ExecEnviron* e, struct AstElement* a)
{
    assert(a);
    assert(valExecs[a->kind]);
    return valExecs[a->kind](e, a);
}

static void dispatchStatement(struct ExecEnviron* e, struct AstElement* a)
{
    assert(a);
    assert(runExecs[a->kind]);
    runExecs[a->kind](e, a);
}

static void onlyName(const char* name, const char* reference, const char* kind)
{
    if(strcmp(reference, name))
    {
        fprintf(stderr,
            "This language knows only the %s '%s', not '%s'\n",
            kind, reference, name);
        exit(1);
    }
}

static void onlyX(const char* name)
{
    onlyName(name, "x", "variable");
}

static void onlyPrint(const char* name)
{
    onlyName(name, "print", "function");
}

static int execTermExpression(struct ExecEnviron* e, struct AstElement* a)
{
    /* This function looks ugly because it handles two different kinds of
     * AstElement. I would refactor it to an execNameExp and execVal
     * function to get rid of this two if statements. */
    assert(a);
    if(ekNumber == a->kind)
    {
        return a->data.val;
    }
    else
    {
        if(ekId == a->kind)
        {
            onlyX(a->data.name);
            assert(e);
            return e->x;
        }
    }
    fprintf(stderr, "OOPS: tried to get the value of a non-expression(%d)\n", a->kind);
    exit(1);
}

static int execBinExp(struct ExecEnviron* e, struct AstElement* a)
{
    assert(ekBinExpression == a->kind);
    const int left = dispatchExpression(e, a->data.expression.left);
    const int right = dispatchExpression(e, a->data.expression.right);
    switch(a->data.expression.op)
    {
        case '+':
            return left + right;
        case '-':
            return left - right;
        case '*':
            return left * right;
        case '<':
            return left < right;
        case '>':
            return left > right;
        default:
            fprintf(stderr,  "OOPS: Unknown operator:%c\n", a->data.expression.op);
            exit(1);
    }
    /* no return here, since every switch case returns some value (or bails out) */
}

static void execAssign(struct ExecEnviron* e, struct AstElement* a)
{
    assert(a);
    assert(ekAssignment == a->kind);
    onlyX(a->data.assignment.name);
    assert(e);
    struct AstElement* r = a->data.assignment.right;
    e->x = dispatchExpression(e, r);
}

static void execWhile(struct ExecEnviron* e, struct AstElement* a)
{
    assert(a);
    assert(ekWhile == a->kind);
    struct AstElement* const c = a->data.whileStmt.cond;
    struct AstElement* const s = a->data.whileStmt.statements;
    assert(c);
    assert(s);
    while(dispatchExpression(e, c))
    {
        dispatchStatement(e, s);
    }
}

static void execCall(struct ExecEnviron* e, struct AstElement* a)
{
    assert(a);
    assert(ekCall == a->kind);
    onlyPrint(a->data.call.name);
    printf("%d\n", dispatchExpression(e, a->data.call.param));
}

static void execStmt(struct ExecEnviron* e, struct AstElement* a)
{
    assert(a);
    assert(ekStatements == a->kind);
    int i;
    for(i=0; i<a->data.statements.count; i++)
    {
        dispatchStatement(e, a->data.statements.statements[i]);
    }
}

void execAst(struct ExecEnviron* e, struct AstElement* a)
{
    dispatchStatement(e, a);
}

struct ExecEnviron* createEnv()
{
    assert(ekLastElement == (sizeof(valExecs)/sizeof(*valExecs)));
    assert(ekLastElement == (sizeof(runExecs)/sizeof(*runExecs)));
    return calloc(1, sizeof(struct ExecEnviron));
}

void freeEnv(struct ExecEnviron* e)
{
    free(e);
}

现在解释器已经完成，可以运行示例了，主函数更新后:

#include <assert.h>

int main()
{
    yydebug = 0;
    struct AstElement *a = 0;
    yyparse(&a);
    /* Q&D WARNING: in production code this assert must be replaced by
     * real error handling. */
    assert(a);
    struct ExecEnviron* e = createEnv();
    execAst(e, a);
    freeEnv(e);
    /* TODO: destroy the AST */
}

现在这种语言的解释器可以工作了。请注意，此解释器存在一些限制:

• 它只有一个变量和一个函数
  • 一个函数只有一个参数
• 只有 int 类型的值
• 很难添加 goto 支持，因为对于每个 AST 元素，解释器都会调用一个解释函数。转到 execStmt 可以在一个 block 内实现。功能，但要在不同的 block 或级别之间跳转，必须显着改变执行机制(这是因为不能在解释器的不同堆栈帧之间跳转)。例如，AST 可以转换为字节码，并且该字节码由虚拟机解释。
• 其他一些我需要查找的 :)

您需要为您的语言定义语法。像这样的事情(词法分析器和解析器都不完整):

/* foo.y */
%token ID IF ELSE OR AND /* First list all terminal symbols of the language */
%%

statements: /* allow empty statements */ | stm | statements ';' stm;

stm: ifStatement
   | NAME
   | NAME expList
   | label;

expList: expression | expList expression;

label: ':' NAME { /* code to store the label */ };

ifStatement: IF expression statements
           | IF expression statements ELSE statements;

expression: ID                          { /* Code to handle the found ID */ }
          | expression AND expression   { /* Code to con cat two expression with and */ }
          | expression OR expression
          | '(' expression ')';

然后你用bison -d foo.y -o foo.c编译这个文件. -d switch 指示 bison 生成一个 header ，其中包含解析器使用的所有标记。现在你创建你的词法分析器

/* bar.l */
%{
#include "foo.h"
%}

%%

IF   return IF;
ELSE return ELSE;
OR   return OR;
AND  return AND;
[A-Z]+  { /*store yylval somewhere to access it in the parser*/ return ID; }

在此之后，您已经完成了词法分析器和解析器，并且“只”需要为您的语言编写语义操作。

关于c++ - 我如何在 Flex/bison 中实现 If 语句，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/2644597/