我一直在论坛中搜索，但没有任何帮助。 我在一个 View Controller 中使用 4 个文本字段，对于每个文本字段，我使用一个单独的 pickerView 作为 textFields (4pickers) 的输入 View 。

当我点击第一个 textField 时，pickerView1 成功出现并且 textfield 显示数据，但是当我点击第二个、第三个和第四个 textfield 时，第一个 pickerView 出现。 我怀疑错误出在 inputView 声明中。

如果您能帮助将“完成”按钮添加到 pickerView，我将不胜感激。

我的代码:

class ViewController1: UIViewController, UIPickerViewDelegate
{

    @IBOutlet var pickerView1: UIPickerView!
    @IBOutlet var pickerView2: UIPickerView!
    @IBOutlet var pickerView3: UIPickerView!
    @IBOutlet var pickerView4: UIPickerView!

    @IBOutlet var textField1: UITextField!
    @IBOutlet var textField2: UITextField!
    @IBOutlet var textField3: UITextField!
    @IBOutlet var textField4: UITextField!

    var hazards = ["a","b", "c"]
    var reasons = ["d", "e", "f"]
    var site = ["v","h","i","j"]
    var line = ["k", "l","m", "n"]

    override func viewDidLoad() {

        super.viewDidLoad()
        pickerView1 = UIPickerView()
        pickerView2 = UIPickerView()
        pickerView3 = UIPickerView()
        pickerView4 = UIPickerView()
        pickerView1.delegate = self
        pickerView2.delegate = self
        pickerView3.delegate = self
        pickerView4.delegate = self

        self.textField1.inputView = self.pickerView1;
        self.textField2.inputView = self.pickerView2;
        self.textField3.inputView = self.pickerView3;
        self.textField4.inputView = self.pickerView4;
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int  {
        return 1
    }

    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {

        if pickerView.tag == 0 {
            return hazards.count
        } else if pickerView.tag == 1 {
            return reasons.count
        } else if pickerView.tag == 2 {
            return  site.count
        } else if  pickerView.tag == 3 {
            return line.count
        }
        return 1
    }

    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {

        if pickerView.tag == 0 {
            return hazards[row]
        } else if pickerView.tag == 1 {
            return reasons[row]
        } else if pickerView.tag == 2 {
            return site[row]
        } else if pickerView.tag == 3 {
            return line[row]
        }

        return ""
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int)  {

        if pickerView.tag == 0 {
            textField1.text = hazards[row]
        } else if pickerView.tag == 1 {
            textField2.text = reasons[row]
        } else if pickerView.tag == 2 {
            textField3.text = site[row]
        } else if pickerView.tag == 3 {
            textField4.text = line[row]
        }
    }
}

最佳答案

您正在使用选择器 View 的 tag 属性来决定哪个数组是给定选择器 View 的数据源，但您最初没有设置标签。 标签 默认为零，因此所有四个选择器 View 都显示相同的数据。实例化您的选择器 View 后，添加以下内容:

pickerView1.tag = 0
pickerView2.tag = 1
pickerView3.tag = 2
pickerView4.tag = 3

关于swift - 具有多个文本字段输入 View 的多个选择器 View Swift，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/26488250/