您好，我已经阅读了许多论坛和网站，这些论坛和网站告诉您如何将图像上传到服务器，并且我已经设法让它工作，我可以将文件上传到我的服务器，但存储文件名确实适用于以下我找到的示例，我还需要创建一个允许将更多数据输入数据库的表单。我坚持这一点，因为以前做过很多 PHP。我已经尝试了不同的网站教程，但没有取得多大成功，任何人都可以帮助我!我需要为我正在做的项目完成它。

我基本上是在尝试制作一个 CMS，它允许用户上传乐队成员的照片并存储有关他们的信息，以便将其显示在网页上供公众查看。

我的表是这样的:

Field              Type             Null    Default     
id                 int(10)          No                   
nameMember         varchar(25)      No                   
bandMember         text             No                   
photo              varchar(30)      No                   
aboutMember        text             No                   
otherBands         text             No      

我想要的表格是这样的:

   <h1>Adding a new Band Member or Affiliate</h1>
      <form method="post" action="addMember.php" enctype="multipart/form-data">
       <p>
              Please Enter the Band Members Name.
            </p>
            <p>
              Band Member or Affiliates Name:
            </p>
            <input type="text" name="nameMember"/>
            <p>
              Please Enter the Band Members Position. Example:Drums.
            </p>
            <p>
              Member's Position:
            </p>
            <input type="text" name="bandMember"/>
            <p>
              Please Upload a Photo in gif or jpeg format. The file name should be named after the Members name. If the same file name is uploaded twice it will be overwritten!
            </p>
            <p>
              Photo:
            </p>
            <input type="file" name="filep" size=35 />
            <p>
              Please Enter any other information about the band member here.
            </p>
            <p>
              Other Member Information:
            </p>
<textarea rows="10" cols="35" name="aboutMember">
</textarea>
            <p>
              Please Enter any other Bands the Member has been in.
            </p>
            <p>
              Other Bands:
            </p>
            <input type="text" name="otherBands" size=30 />
            <br/>
            <br/>
            <input TYPE="submit" title="Add data to the Database" value="Add Member"/>
          </form>

上传图片到服务器的例子，也就是这样:

<?

if ($_POST["action"] == "Load")
{
$folder = "images/";

move_uploaded_file($_FILES["filep"]["tmp_name"] , "$folder".$_FILES["filep"]["name"]);

echo "
<p align=center>File ".$_FILES["filep"]["name"]."loaded...";

$result = mysql_connect("localhost", "******", "*****") or die ("Could not save image name

Error: " . mysql_error());

mysql_select_db("project") or die("Could not select database");
mysql_query("INSERT into dbProfiles (photo) VALUES('".$_FILES['filep']['name']."')");
if($result) { echo "Image name saved into database

"; }

}

?>

我必须使用的示例表单是这样的:

<form action=addMember.php method=post enctype="multipart/form-data">
<table border="0" cellspacing="0" align=center cellpadding="3" bordercolor="#cccccc">
<tr>
<td>File:</td>
<td><input type="file" name="filep" size=45></td>
</tr>
<tr>
<td colspan=2><p align=center>
<input type=submit name=action value="Load">
</td>
</tr>
</table>
</form>

PS:图像文件已打开以供写入。

最佳答案

这里是答案，供那些看起来像我在整个网络上试图找出如何完成这项任务的人使用。将照片上传到服务器，文件名存储在 mysql 数据库中，其他表单数据存储在数据库中。如果有帮助，请告诉我。

首先你需要的表格:

    <form method="post" action="addMember.php" enctype="multipart/form-data">
    <p>
              Please Enter the Band Members Name.
            </p>
            <p>
              Band Member or Affiliates Name:
            </p>
            <input type="text" name="nameMember"/>
            <p>
              Please Enter the Band Members Position. Example:Drums.
            </p>
            <p>
              Band Position:
            </p>
            <input type="text" name="bandMember"/>
            <p>
              Please Upload a Photo of the Member in gif or jpeg format. The file name should be named after the Members name. If the same file name is uploaded twice it will be overwritten! Maxium size of File is 35kb.
            </p>
            <p>
              Photo:
            </p>
            <input type="hidden" name="size" value="350000">
            <input type="file" name="photo"> 
            <p>
              Please Enter any other information about the band member here.
            </p>
            <p>
              Other Member Information:
            </p>
<textarea rows="10" cols="35" name="aboutMember">
</textarea>
            <p>
              Please Enter any other Bands the Member has been in.
            </p>
            <p>
              Other Bands:
            </p>
            <input type="text" name="otherBands" size=30 />
            <br/>
            <br/>
            <input TYPE="submit" name="upload" title="Add data to the Database" value="Add Member"/>
          </form>

然后这段代码处理表单中的数据:

   <?php

// This is the directory where images will be saved
$target = "your directory";
$target = $target . basename( $_FILES['photo']['name']);

// This gets all the other information from the form
$name=$_POST['nameMember'];
$bandMember=$_POST['bandMember'];
$pic=($_FILES['photo']['name']);
$about=$_POST['aboutMember'];
$bands=$_POST['otherBands'];


// Connects to your Database
mysqli_connect("yourhost", "username", "password") or die(mysqli_error()) ;
mysqli_select_db("dbName") or die(mysqli_error()) ;

// Writes the information to the database
mysqli_query("INSERT INTO tableName (nameMember,bandMember,photo,aboutMember,otherBands)
VALUES ('$name', '$bandMember', '$pic', '$about', '$bands')") ;

// Writes the photo to the server
if(move_uploaded_file($_FILES['photo']['tmp_name'], $target))
{

// Tells you if its all ok
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
}
else {

// Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
?> 

代码编辑自 www.about.com

关于php - 如何在使用 PHP 将图像上传到服务器时将文件名与其他信息一起存储在数据库中？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/450876/