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java - Spring Data JPA Update @Query 没有更新?

coder 2023-05-14 原文

我有一个更新查询:

@Modifying
@Transactional
@Query("UPDATE Admin SET firstname = :firstname, lastname = :lastname, login = :login, superAdmin = :superAdmin, preferenceAdmin = :preferenceAdmin, address =  :address, zipCode = :zipCode, city = :city, country = :country, email = :email, profile = :profile, postLoginUrl = :postLoginUrl WHERE id = :id")
public void update(@Param("firstname") String firstname, @Param("lastname") String lastname, @Param("login") String login, @Param("superAdmin") boolean superAdmin, @Param("preferenceAdmin") boolean preferenceAdmin, @Param("address") String address, @Param("zipCode") String zipCode, @Param("city") String city, @Param("country") String country, @Param("email") String email, @Param("profile") String profile, @Param("postLoginUrl") String postLoginUrl, @Param("id") Long id);

我正在尝试在集成测试中使用它:

adminRepository.update("Toto", "LeHeros", admin0.getLogin(), admin0.getSuperAdmin(), admin0.getPreferenceAdmin(), admin0.getAddress(), admin0.getZipCode(), admin0.getCity(), admin0.getCountry(), admin0.getEmail(), admin0.getProfile(), admin0.getPostLoginUrl(), admin0.getId());
Admin loadedAdmin = adminRepository.findOne(admin0.getId());
assertEquals("Toto", loadedAdmin.getFirstname());
assertEquals("LeHeros", loadedAdmin.getLastname());

但是这些字段没有更新并保留它们的初始值,因此测试失败。

我尝试在 findOne 查询之前添加一个刷新:

adminRepository.flush();

但失败的断言保持不变。

在日志中可以看到更新sql语句:

update admin set firstname='Toto', lastname='LeHeros', login='stephane', super_admin=0, preference_admin=0,
address=NULL, zip_code=NULL, city=NULL, country=NULL, email='stephane@thalasoft.com', profile=NULL,
post_login_url=NULL where id=2839

但日志显示没有可能与查找器相关的 sql:

Admin loadedAdmin = adminRepository.findOne(admin0.getId());
The finder sql statement is not making its way to the database.

是否因为某些缓存原因而被忽略?

如果我随后添加对 findByEmail 和 findByLogin 查找器的调用,如下所示:

adminRepository.update("Toto", "LeHeros", "qwerty", admin0.getSuperAdmin(), admin0.getPreferenceAdmin(), admin0.getAddress(), admin0.getZipCode(), admin0.getCity(), admin0.getCountry(), admin0.getEmail(), admin0.getProfile(), admin0.getPostLoginUrl(), admin0.getId());
Admin loadedAdmin = adminRepository.findOne(admin0.getId());
Admin myadmin = adminRepository.findByEmail(admin0.getEmail());
Admin anadmin = adminRepository.findByLogin("qwerty");
assertEquals("Toto", anadmin.getFirstname());
assertEquals("Toto", myadmin.getFirstname());
assertEquals("Toto", loadedAdmin.getFirstname());
assertEquals("LeHeros", loadedAdmin.getLastname());

然后我可以在日志中看到正在生成的 sql 语句:

但是断言:

assertEquals("Toto", myadmin.getFirstname());

即使跟踪显示检索到相同的域对象,仍然失败:

TRACE [BasicExtractor] found [1037] as column [id14_]

另一个 finder 让我感到困惑的另一件事是,它显示了一个限制 2 子句,即使它应该只返回一个 Admin 对象。

我认为返回一个域对象时总会有一个限制 1。这是对 Spring Data 的错误假设吗?

在 MySQL 客户端中粘贴时,控制台日志中显示的 sql 语句,逻辑工作正常:

mysql> insert into admin (version, address, city, country, email, firstname, lastname, login, password, 
-> password_salt, post_login_url, preference_admin, profile, super_admin, zip_code) values (0,
-> NULL, NULL, NULL, 'zemail@thalasoft.com039', 'zfirstname039', 'zlastname039', 'zlogin039',
-> 'zpassword039', '', NULL, 0, NULL, 1, NULL);
Query OK, 1 row affected (0.07 sec)

mysql> select * from admin;
+------+---------+---------------+--------------+-----------+--------------+---------------+-------------+------------------+---------+----------+------+---------+-------------------------+---------+----------------+
| id | version | firstname | lastname | login | password | password_salt | super_admin | preference_admin | address | zip_code | city | country | email | profile | post_login_url |
+------+---------+---------------+--------------+-----------+--------------+---------------+-------------+------------------+---------+----------+------+---------+-------------------------+---------+----------------+
| 1807 | 0 | zfirstname039 | zlastname039 | zlogin039 | zpassword039 | | 1 | 0 | NULL | NULL | NULL | NULL | zemail@thalasoft.com039 | NULL | NULL | 
+------+---------+---------------+--------------+-----------+--------------+---------------+-------------+------------------+---------+----------+------+---------+-------------------------+---------+----------------+
1 row in set (0.00 sec)

mysql> update admin set firstname='Toto', lastname='LeHeros', login='qwerty', super_admin=0, preference_admin=0, address=NULL, zip_code=NULL, city=NULL, country=NULL, email='stephane@thalasoft.com', profile=NULL, post_login_url=NULL where id=1807;
Query OK, 1 row affected (0.07 sec)
Rows matched: 1 Changed: 1 Warnings: 0

mysql> select * from admin; +------+---------+-----------+----------+--------+--------------+---------------+-------------+------------------+---------+----------+------+---------+------------------------+---------+----------------+
| id | version | firstname | lastname | login | password | password_salt | super_admin | preference_admin | address | zip_code | city | country | email | profile | post_login_url |
+------+---------+-----------+----------+--------+--------------+---------------+-------------+------------------+---------+----------+------+---------+------------------------+---------+----------------+
| 1807 | 0 | Toto | LeHeros | qwerty | zpassword039 | | 0 | 0 | NULL | NULL | NULL | NULL | stephane@thalasoft.com | NULL | NULL | 
+------+---------+-----------+----------+--------+--------------+---------------+-------------+------------------+---------+----------+------+---------+------------------------+---------+----------------+
1 row in set (0.00 sec)

mysql> select admin0_.id as id14_, admin0_.version as version14_, admin0_.address as address14_, admin0_.city as city14_, admin0_.country as country14_, admin0_.email as email14_, admin0_.firstname as firstname14_, admin0_.lastname as lastname14_, admin0_.login as login14_, admin0_.password as password14_, admin0_.password_salt as password11_14_, admin0_.post_login_url as post12_14_, admin0_.preference_admin as preference13_14_, admin0_.profile as profile14_, admin0_.super_admin as super15_14_, admin0_.zip_code as zip16_14_ from admin admin0_ where admin0_.email='stephane@thalasoft.com' limit 2;
+-------+------------+------------+---------+------------+------------------------+--------------+-------------+----------+--------------+----------------+------------+------------------+------------+-------------+-----------+
| id14_ | version14_ | address14_ | city14_ | country14_ | email14_ | firstname14_ | lastname14_ | login14_ | password14_ | password11_14_ | post12_14_ | preference13_14_ | profile14_ | super15_14_ | zip16_14_ |
+-------+------------+------------+---------+------------+------------------------+--------------+-------------+----------+--------------+----------------+------------+------------------+------------+-------------+-----------+
| 1807 | 0 | NULL | NULL | NULL | stephane@thalasoft.com | Toto | LeHeros | qwerty | zpassword039 | | NULL | 0 | NULL | 0 | NULL | 
+-------+------------+------------+---------+------------+------------------------+--------------+-------------+----------+--------------+----------------+------------+------------------+------------+-------------+-----------+
1 row in set (0.00 sec)

mysql> select admin0_.id as id14_, admin0_.version as version14_, admin0_.address as address14_, admin0_.city as city14_, admin0_.country as country14_, admin0_.email as email14_, admin0_.firstname as firstname14_, admin0_.lastname as lastname14_, admin0_.login as login14_, admin0_.password as password14_, admin0_.password_salt as password11_14_, admin0_.post_login_url as post12_14_, admin0_.preference_admin as preference13_14_, admin0_.profile as profile14_, admin0_.super_admin as super15_14_, admin0_.zip_code as zip16_14_ from admin admin0_ where admin0_.login='qwerty' limit 2;
+-------+------------+------------+---------+------------+------------------------+--------------+-------------+----------+--------------+----------------+------------+------------------+------------+-------------+-----------+
| id14_ | version14_ | address14_ | city14_ | country14_ | email14_ | firstname14_ | lastname14_ | login14_ | password14_ | password11_14_ | post12_14_ | preference13_14_ | profile14_ | super15_14_ | zip16_14_ |
+-------+------------+------------+---------+------------+------------------------+--------------+-------------+----------+--------------+----------------+------------+------------------+------------+-------------+-----------+
| 1807 | 0 | NULL | NULL | NULL | stephane@thalasoft.com | Toto | LeHeros | qwerty | zpassword039 | | NULL | 0 | NULL | 0 | NULL | 
+-------+------------+------------+---------+------------+------------------------+--------------+-------------+----------+--------------+----------------+------------+------------------+------------+-------------+-----------+
1 row in set (0.00 sec)

那么为什么这没有反射(reflect)在 Java 级别呢?

最佳答案

默认情况下,EntityManager 不会自动刷新更改。您应该在查询语句中使用以下选项:

@Modifying(clearAutomatically = true)
@Query("update RssFeedEntry feedEntry set feedEntry.read =:isRead where feedEntry.id =:entryId")
void markEntryAsRead(@Param("entryId") Long rssFeedEntryId, @Param("isRead") boolean isRead);

关于java - Spring Data JPA Update @Query 没有更新?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17121620/

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