我有一个填充的 CodeIgniter form_multiselect。里面有值

代码如下:

<select multiple="multiple" name="EMPLOYEES_id[]">
 <option value="8">Employee 8</option>
 <option value="1">Employee 1</option>
 <option value="12">Employee 12</option>
</select>

这在您可以向多个用户发送消息的系统上运行。所以我想做的是说用户选择值 1 和值 8。我想使用相同的数据运行两次插入，但唯一的区别是数据库中的 EMPLOYEES_id 字段每次都不同。

我的模型如下:

function create()
{
    $this->template->set('title', 'Create Message');


    // Validate the form input
    $this->form_validation->set_error_delimiters('<span class="help-inline">', '</span>');
    $this->form_validation->set_rules('MESSAGE_summary', 'Message Summary', 'trim|required|xss_clean');
    $this->form_validation->set_rules('MESSAGE_body', 'Message Body', 'trim|required|xss_clean');


    if($this->form_validation->run() == FALSE)
    {

        // Get all users in same company as logged in user
        $comapny_contacts = $this->Employees_model->read_company_contacts($this->viewinguser->BUSINESSES_id);
        $comapny_contacts = $comapny_contacts->result();

        foreach($comapny_contacts as $contacts)
        {
            $comapny_contacts_options[$contacts->EMPLOYEES_id] = $contacts->EMPLOYEES_firstname . ' ' . $contacts->EMPLOYEES_surname;
        }

        $this->template->set('comapny_contacts_options', $comapny_contacts_options);


        // form has not been run or there are validation errors
        $this->template->build('messages/create');
    }
    else
    {

        /*
         * Lets create the new message in the database
         */
        $insert_data = new stdClass();
        $insert_data->MESSAGES_summary = $this->input->post('MESSAGE_summary');
        $insert_data->MESSAGES_body = $this->input->post('MESSAGE_body');
        $insert_data->MESSAGES_level = $this->input->post('MESSAGES_level');
        $insert_data->MESSAGES_type = $this->input->post('MESSAGES_type');
        $insert_data->MESSAGES_createdby = $this->activeuser->EMPLOYEES_id;
        //$insert_data->EMPLOYEES_id = $this->input->post('EMPLOYEES_id');
        foreach($this->input->post('EMPLOYEES_id') as $employee_id)
        {
            $insert_data->EMPLOYEES_id = $employee_id;

            // Save to new message in the database
            $this->Messages_model->create($insert_data);
        }

        /*
         * Now lets save a notification email in the database to be sent to the user
        */
        $notification_body = '
        <p>A new message has been added for you  by ' . $this->session->userdata('activeuser')->EMPLOYEES_firstname . '<br />
        ------------------------------</p>
        <p><strong>Summary:</strong> ' . $this->input->post('MESSAGE_summary') . '</p>
        <p>------------------------------<br />
        <a class="btn" href="' . base_url('messages') . '">Click to view full messages</a>';

        // Get the info for the user who the notification is for
        $notify_user_info = $this->Employees_model->read_single_switch($this->input->post('EMPLOYEES_id'));
        $notify_user_info = $notify_user_info->result();

        // Set all the data
        $insert_data = new stdClass();
        $insert_data->NOTIFICATIONS_toname = $notify_user_info[0]->EMPLOYEES_firstname . ' ' . $notify_user_info[0]->EMPLOYEES_surname;
        $insert_data->NOTIFICATIONS_toemail = $notify_user_info[0]->EMPLOYEES_email;
        $insert_data->NOTIFICATIONS_subject = 'A new message has been added for you';
        $insert_data->NOTIFICATIONS_htmlbody = $notification_body;
        //$insert_data->EMPLOYEES_id = $this->input->post('EMPLOYEES_id');
        foreach($this->input->post('EMPLOYEES_id') as $employee_id)
        {
            $insert_data->EMPLOYEES_id = $employee_id;

            // Save to new notification to the database
            $this->Notifications_model->create($insert_data);
        }

        // show user confirmation
        $this->session->set_flashdata('success_message', 'New message created successfully.');
        redirect('messages');
    }

最佳答案

最简单的方法是设置所有通用参数，然后在每个 foreach 上插入数据$this->input->post('EMPLOYEES_id') 的迭代.

 foreach($this->input->post('EMPLOYEES_id') as $eid){
      // insert data using $uid as the employer id here
 }

关于php - CodeIgniter 表单多选，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/10721733/