我创建了一个聊天机器人，它会通知用户我的(大)家庭成员以及他们住在哪里。我用 MySQL 创建了一个小型数据库，其中存储了这些数据，并在适当的时候使用 PHP 脚本获取它们，具体取决于用户与聊天机器人的交互。

除了 Default Fallback Intent 之外，我的聊天机器人还包含两个意图。和 Default Welcome Intent :

<?php

$dbServername = '******************';
$dbUsername = '******************';
$dbPassword = '******************';
$dbName = '******************';
$conn = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName);

// error_reporting(E_ALL);
// ini_set('display_errors', 'on');

header('Content-Type: application/json');
$method = $_SERVER['REQUEST_METHOD'];

if($method == 'POST'){
    $requestBody = file_get_contents('php://input');
    $json = json_decode($requestBody);

    $action = $json->result->action;
    $first_name = $json->result->contexts[0]->parameters->{'given-name'};
    $last_name = $json->result->contexts[0]->parameters->{'last-name'};
    $lifespan = $json->result->contexts[0]->lifespan;

    $sql = "SELECT * FROM family WHERE name LIKE '%$first_name%$last_name%';";
    $result = mysqli_query($conn, $sql);
    $resultCheck = mysqli_num_rows($result);
    if ($resultCheck > 0) {
       while ($row = mysqli_fetch_assoc($result)) {
            $person = $row;
       }

       switch ($action) {
           case 'Name':
               $speech= "$first_name is my" . $person["name"] . ".";
               break;  
           case 'Location':
               $speech = "$first_name is living in {$person["location"]}.";
               break;
           default:
               $speech = "Please ask me something more relevant to my family";
               break;
       } 
    }
    else {

        $speech = "Sorry, $first_name $last_name is not a member of my family.";

    }

    $response = new \stdClass();
    $response->speech = $speech;
    $response->displayText = $speech;
    $response->source = "agent";
    echo json_encode($response);
}
else
{
    echo "Method not allowed";
}
?>

{
  "id": "*****************************",
  "timestamp": "2018-04-04T08:26:39.993Z",
  "lang": "en",
  "result": {
    "source": "agent",
    "resolvedQuery": "Where is he living"
    "action": "Location",
    "actionIncomplete": false,
    "parameters": {},
    "contexts": [
      {
        "name": "context",
        "parameters": {
          "given-name.original": "John",
          "last-name.original": "Smith",
          "given-name": "John",
          "last-name": "Smith"
        },
        "lifespan": 9
      }
    ],
    "metadata": {
      "intentId": "*****************************",
      "webhookUsed": "true",
      "webhookForSlotFillingUsed": "false",
      "webhookResponseTime": 93,
      "intentName": "Location_context"
    },
    "fulfillment": {
      "speech": "John is living in New York.”,
      "displayText": "John is living in New York.",
      "messages": [
        {
          "type": 0,
          "speech": "John is living in New York."
        }
      ]
    },
    "score": 1
  },
  "status": {
    "code": 200,
    "errorType": "success",
    "webhookTimedOut": false
  },
  "sessionId": "*****************************"
}

"contexts": [
          {
            "name": "actions_capability_screen_output",
            "parameters": {},
            "lifespan": 0
          }
        ]

"contexts": [
      {
        "name": "context",
        "parameters": {
          "given-name.original": "John",
          "last-name.original": "Smith",
          "given-name": "John",
          "last-name": "Smith"
        },
        "lifespan": 9
      }
    ]

最佳答案

除了你的问题，这里还有很多事情要做。让我们试着一点一点地分解它们。

为什么我最初在响应中收到错误？

因为 ini_set('display_errors', 'on');将任何错误发送到标准输出，这是您发送回 Dialogflow 的内容。 Dialogflow 向 Google 发送信息的解析器是严格的，因此额外的输出在这里造成了问题。

我怎样才能看到发生了什么？

你应该使用类似 error_log() 的东西来记录事情。 .这会将您想要的任何内容记录在一个文件中，因此您可以看到来自 Dialogflow 的确切 JSON 以及您认为要发回的确切内容。

您可以将其与类似的东西一起使用

error_log( $request_body );

error_log( $json->result->context );

关于php - Google Assistant 出错，而 Dialogflow 没有错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49626687/