我正在尝试生成一个与初始文件几乎相同的 xml 文件，但我需要我的 xsl 工作表将其转换为仅包含 为“公寓”或“单元”的文件，并且在 中的值超过 1 我完全迷路了，任何帮助将不胜感激!

我的初始 xml 表如下:

<rentalProperties> 
<property available="yes" contact="0423020892"> 
    <type>house</type> 
    <price>800</price> 
    <address> 
        <streetNo>116</streetNo> 
        <street>Warrigal Road</street> 
        <suburb>Camberwell</suburb> 
        <state>VIC</state> 
    <zipcode>3124</zipcode>
    </address> 
    <numberOfBedrooms>4</numberOfBedrooms> 
    <description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are served by a stylishly renovated central bathroom and second sky-lit bathroom to the rear.</description>
</property>
</rentalproperties>

我的 xsl:

<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/">
<xsl:element name="RentalProperties">
   <xsl:apply-templates select="rentalProperties/property"/>
</xsl:element>
</xsl:template>

<xsl:template match="rentalProperties/property/type">
<xsl:element name="type" >
  <xsl:value-of select="."/>
</xsl:element>
</xsl:template>

<xsl:template match="rentalProperties/property/price">
<xsl:element name="price" >
  <xsl:value-of select="."/>
</xsl:element>
</xsl:template>

<xsl:template match="rentalProperties/property/address">
<xsl:element name="address" >
  <xsl:value-of select="streetNo"/><xsl:value-of select="street"/><xsl:value-of select="suburb"/><xsl:value-of select="state"/><xsl:value-of select="zipcode"/>
</xsl:element>
</xsl:template>

<xsl:template match="rentalProperties/property/numberOfBedrooms">
<xsl:element name="numberOfBedrooms" >
  <xsl:value-of select="."/>
</xsl:element>
</xsl:template>

<xsl:template match="rentalProperties/property/description">
<xsl:element name="description" >
  <xsl:value-of select="."/>
</xsl:element>
</xsl:template>

输出会是这样的:

<RentalProperties>
<property>
<type>apartment</type>
<price>400</price>
<address>4/3,Acheron Avenue,Camberwell,VIC,3124, Australia</address>
<numberOfBedrooms>2</numberOfBedrooms>
<description>This two bedroom apartment is located in quiet tree lined street, just minutes from tram and easy walk to Camberwell Junction and train. Positioned on the 1st floor with sunny north facing lounge and balcony.
</description>
</property>
</RentalProperties>

谢谢

最佳答案

这可能是最简单的解决方案之一(根本没有显式条件，所有输出仅由标识模板生成):

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match=
 "property
   [not(contains('|unit|apartment|',
                 concat('|',type,'|')
                 )
        )
    or
     not(numberOfBedrooms > 1)
   ]
 "/>
</xsl:stylesheet>

应用于此 XML 文档时(提供的文档 -- 更正和放大):

<rentalProperties>
<property available="yes" contact="0423020892">
    <type>house</type>
    <price>800</price>
    <address>
        <streetNo>116</streetNo>
        <street>Warrigal Road</street>
        <suburb>Camberwell</suburb>
        <state>VIC</state>
    <zipcode>3124</zipcode>
    </address>
    <numberOfBedrooms>4</numberOfBedrooms>
    <description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are served by a stylishly renovated central bathroom and second sky-lit bathroom to the rear.</description>
</property>
<property available="yes" contact="0423020899">
    <type>apartment</type>
    <price>500</price>
    <address>
        <streetNo>116</streetNo>
        <street>Water St.</street>
        <suburb>Hornsby</suburb>
        <state>NSW</state>
    <zipcode>2012</zipcode>
    </address>
    <numberOfBedrooms>2</numberOfBedrooms>
    <description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are served by a stylishly renovated central bathroom and second sky-lit bathroom to the rear.</description>
</property>
<property available="yes" contact="0423011111">
    <type>unit</type>
    <price>800</price>
    <address>
        <streetNo>7</streetNo>
        <street>Ryan St</street>
        <suburb>Isacs</suburb>
        <state>ACT</state>
    <zipcode>2603</zipcode>
    </address>
    <numberOfBedrooms>1</numberOfBedrooms>
    <description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are served by a stylishly renovated central bathroom and second sky-lit bathroom to the rear.</description>
</property>
<property available="yes" contact="04231234567">
    <type>hotel</type>
    <price>1200</price>
    <address>
        <streetNo>4</streetNo>
        <street>Bench St.</street>
        <suburb>Deakin</suburb>
        <state>ACT</state>
    <zipcode>2600</zipcode>
    </address>
    <numberOfBedrooms>4</numberOfBedrooms>
    <description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are served by a stylishly renovated central bathroom and second sky-lit bathroom to the rear.</description>
</property>
</rentalProperties>

产生想要的、正确的结果(仅输出满足所有约束的属性之一):

<rentalProperties>
   <property available="yes" contact="0423020899">
      <type>apartment</type>
      <price>500</price>
      <address>
         <streetNo>116</streetNo>
         <street>Water St.</street>
         <suburb>Hornsby</suburb>
         <state>NSW</state>
         <zipcode>2012</zipcode>
      </address>
      <numberOfBedrooms>2</numberOfBedrooms>
      <description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are served by a stylishly renovated central bathroom and second sky-lit bathroom to the rear.</description>
   </property>
</rentalProperties>

说明:用匹配任何不需要的属性的空模板覆盖 identity rule 。

关于XML 到 XML，XSLT 根据值省略特定元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7863660/