您能告诉我如何读取 Python 包中的文件吗？

我的情况

我加载的包有许多我想从程序中加载的模板(用作字符串的文本文件)。但是如何指定此类文件的路径？

假设我想从以下位置读取文件:

package\templates\temp_file

某种路径操作？包基本路径跟踪？

最佳答案

TLDR; 使用标准库的 importlib.resources module如下面方法 2 中所述。

传统 pkg_resources from setuptools 不再推荐，因为新方法:

• 它是 significantly more performant ;
• 更安全，因为使用包(而不是路径字符串)会引发编译时错误；
• 它更直观，因为您不必“加入”路径；
• 开发时速度更快，因为您不需要额外的依赖项 (setuptools)，而只依赖 Python 的标准库。

我把传统的先列出来，以说明移植现有代码时与新方法的区别(也移植explained here)。

假设您的模板位于嵌套在模块包内的文件夹中:

  <your-package>
    +--<module-asking-the-file>
    +--templates/
          +--temp_file                         <-- We want this file.

Note 1: For sure, we should NOT fiddle with the __file__ attribute (e.g. code will break when served from a zip).

Note 2: If you are building this package, remember to declatre your data files as package_data or data_files in your setup.py.

1) 使用 pkg_resources来自 setuptools (慢)

您可以使用 pkg_resources 来自 setuptools 发行版的软件包，但 需要付费，performance-wise :

import pkg_resources

# Could be any dot-separated package/module name or a "Requirement"
resource_package = __name__
resource_path = '/'.join(('templates', 'temp_file'))  # Do not use os.path.join()
template = pkg_resources.resource_string(resource_package, resource_path)
# or for a file-like stream:
template = pkg_resources.resource_stream(resource_package, resource_path)

Tips:

• This will read data even if your distribution is zipped, so you may set zip_safe=True in your setup.py, and/or use the long-awaited zipapp packer from python-3.5 to create self-contained distributions.

• Remember to add setuptools into your run-time requirements (e.g. in install_requires`).

...请注意，根据 Setuptools/pkg_resources docs，您不应该使用 os.path.join :

Basic Resource Access

Note that resource names must be /-separated paths and cannot be absolute (i.e. no leading /) or contain relative names like "..". Do not use os.path routines to manipulate resource paths, as they are not filesystem paths.

2) Python >= 3.7，或使用向后移植的 importlib_resources 图书馆

使用标准库的 importlib.resources module比 setuptools 更有效, 上:

try:
    import importlib.resources as pkg_resources
except ImportError:
    # Try backported to PY<37 `importlib_resources`.
    import importlib_resources as pkg_resources

from . import templates  # relative-import the *package* containing the templates

template = pkg_resources.read_text(templates, 'temp_file')
# or for a file-like stream:
template = pkg_resources.open_text(templates, 'temp_file')

Attention:

Regarding the function read_text(package, resource):

• The package can be either a string or a module.
• The resource is NOT a path anymore, but just the filename of the resource to open, within an existing package; it may not contain path separators and it may not have sub-resources (i.e. it cannot be a directory).

对于问题中提出的示例，我们现在必须:

• 制作<your_package>/templates/通过创建一个空的 __init__.py 到一个适当的包中文件，
• 所以现在我们可以使用一个简单的(可能是相对的)import声明(不再解析包/模块名称)，
• 只需询问 resource_name = "temp_file" (没有路径)。

Tips:

• To access a file inside the current module, set the package argument to __package__, e.g. pkg_resources.read_text(__package__, 'temp_file') (thanks to @ben-mares).
• Things become interesting when an actual filename is asked with path(), since now context-managers are used for temporarily-created files (read this).
• Add the backported library, conditionally for older Pythons, with install_requires=[" importlib_resources ; python_version<'3.7'"] (check this if you package your project with setuptools<36.2.1).
• Remember to remove setuptools library from your runtime-requirements, if you migrated from the traditional method.
• Remember to customize setup.py or MANIFEST to include any static files.
• You may also set zip_safe=True in your setup.py.

关于python - 如何从 Python 包中读取(静态)文件？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6028000/