我必须将以下数据发送到 URl 的网络服务

发送的数据格式为:

new_member=[{"email":"himanshu@avigma.com","username":"himanshu01","pwd":"himanshu01"}]

其中email,username 和pwd 是key，通过edittext string 获取相应的value string。我在单击按钮时发布此数据。

我没有收到任何回复，因为我已经尝试与我的合作开发人员在他的 iphone 相同的应用程序 iphone 版本中进行反核对，因为服务器说用户名和密码无效。

我的 Signup.java 类是:

    Button b1=(Button)findViewById(R.id.button1);
    b1.setOnClickListener(new OnClickListener()
    {
        EditText e=(EditText)findViewById(R.id.editText1);
        String a=e.getText().toString();
        EditText e1=(EditText)findViewById(R.id.editText1);
        String b=e1.getText().toString();
        EditText e2=(EditText)findViewById(R.id.editText1);
        String c=e2.getText().toString();
        public void onClick(View v) {
            // TODO Auto-generated method stub
             HttpClient client = new DefaultHttpClient(); 
                HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit 
                HttpResponse response; 
                JSONObject json = new JSONObject(); 
                try{ 
                    HttpPost post = new HttpPost("URL"); 
                    //System.out.println(post);
                    json.put("email", a);
                    json.put("username", b);
                    json.put("pwd",c); 
                    StringEntity se = new StringEntity( "JSON: " + json.toString());   
                    se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json")); 
                    post.setEntity(se); 
                    response = client.execute(post); 
                    /*Checking response */ 
                    if(response!=null){ 
                        InputStream in = response.getEntity().getContent(); //Get the data in the entity 
 //System.out.println(response);
                }
                }
                catch(Exception e){ 
                    e.printStackTrace(); 
                    System.out.println(e.toString());
                    //createDialog("Error", "Cannot Estabilish Connection"); 
                } 
        }

    }
            );

请帮助我，我是 JSON 和 Android.Thanx 解析方面的新手。

最佳答案

这是例子

HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(
    "https://api.dailymile.com/entries.json?oauth_token="
    + token);

httpPost.setHeader("content-type", "application/json");
JSONObject data = new JSONObject();

data.put("message", dailyMilePost.getMessage());
JSONObject workoutData = new JSONObject();
data.put("workout", workoutData);
workoutData.put("activity_type", dailyMilePost.getActivityType());
workoutData.put("completed_at", dailyMilePost.getCompletedAt());
JSONObject distanceData = new JSONObject();
workoutData.put("distance", distanceData);
distanceData.put("value", dailyMilePost.getDistanceValue());
distanceData.put("units", dailyMilePost.getDistanceUnits());
workoutData.put("duration", dailyMilePost.getDurationInSeconds());
workoutData.put("title", dailyMilePost.getTitle());
workoutData.put("felt", dailyMilePost.getFelt());

StringEntity entity = new StringEntity(data.toString(), HTTP.UTF_8);
httpPost.setEntity(entity);

HttpResponse response = httpClient.execute(httpPost);

查看此博客的完整信息 http://simpleprogrammer.com/2011/06/04/oauth-and-rest-in-android-part-2/

关于android - 如何使用 JSON 将数据发布到 Web 服务？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/8520011/