我想通过数据创建 XML，并且我在 DataSet 中收到了来自数据库的数据。或 IList<Booking> . 现在我正在使用 DataSet通过此代码创建 XML。

string result = String.Empty;

using (StringWriter sw = new StringWriter())
 {
   ds.WriteXml(sw);
   result = sw.ToString();
 }

我的 XML 就是这种形式。

<Booking> 
    <ID>32</ID> 
    <BookingNumber>12120001</BLNumber> 
    <ReferenceNo>ABCED11212280007</ReferenceNo> 
    <Name>Customer Name1</Name> 
    <Address>Customer Address</Address>
</Booking>

<Booking> 
    <ID>33</ID> 
    <BookingNumber>12120002</BLNumber> 
    <ReferenceNo>ABCED11212280008</ReferenceNo> 
    <Name>Customer Name2</Name> 
    <Address>Customer Address2</Address>
</Booking>



<BookingDetail> 
   <ID>206</ID> 
   <BookingID>32</BookingID> 
   <OrderItem>Item1</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>207</ID> 
   <BookingID>32</BookingID> 
   <OrderItem>Item2</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>208</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item1</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>209</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item2</OrderItem> 
</BookingDetail>

<BookingDetail> 
   <ID>210</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item3</OrderItem> 
</BookingDetail>

但我想要这种形式的 XML。

<CompleteBooking>
 <Booking> 
    <ID>32</ID> 
    <BookingNumber>12120001</BLNumber> 
    <ReferenceNo>ABCED11212280007</ReferenceNo> 
    <Name>Customer Name1</Name> 
    <Address>Customer Address</Address>
 </Booking>

 <BookingDetail> 
   <ID>206</ID> 
   <BookingID>32</BookingID> 
   <OrderItem>Item1</OrderItem> 
 </BookingDetail>

 <BookingDetail> 
   <ID>207</ID> 
   <BookingID>32</BookingID> 
   <OrderItem>Item2</OrderItem> 
 </BookingDetail>

</CompleteBooking>

<CompleteBooking>
 <Booking> 
    <ID>33</ID> 
    <BookingNumber>12120002</BLNumber> 
    <ReferenceNo>ABCED11212280008</ReferenceNo> 
    <Name>Customer Name2</Name> 
    <Address>Customer Address2</Address>
 </Booking>

 <BookingDetail> 
   <ID>208</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item1</OrderItem> 
 </BookingDetail>

 <BookingDetail> 
   <ID>209</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item2</OrderItem> 
 </BookingDetail>

 <BookingDetail> 
   <ID>210</ID> 
   <BookingID>33</BookingID> 
   <OrderItem>Item3</OrderItem> 
 </BookingDetail>

</CompleteBooking>

谁能帮我创建这种类型的 XML？

最佳答案

使用 System.Xml.Serialization，创建您的预订对象:

public class XMLEntities
{   
  [XmlRoot(ElementName = "CompleteBooking")]
  public class CompleteBooking
  {
    [XmlElement(ElementName = "Booking")]
    public Booking Bookings { get; set; }

    [XmlElement(ElementName = "BookingDetail")]
    public List<BookingDetail> BookingDetail { get; set; }
  }

  public class Booking
  {
    [XmlElement("ID")]
    public int ID { get; set; }

    [XmlElement("BookingNumber")]
    public int BookingNumber { get; set; }

    [XmlElement("ReferenceNumber")]
    public string ReferenceNumber { get; set; }

    [XmlElement("Name")]
    public string Name { get; set; }

    [XmlElement("Address")]
    public string Address { get; set; }
  }

  public class BookingDetail
  {
    [XmlElement("ID")]
    public int ID { get; set; }

    [XmlElement("BookingID")]
    public int BookingID { get; set; }

    [XmlElement("OrderItem")]
    public string OrderItem { get; set; }
  }
}

现在，对于序列化器对象(用于实际将对象序列化为字符串):

 public class XMLEntitiesSerializer
 {
   public string Serialize(XMLEntities.CompleteBooking completeBooking)
   {
     var serializedXml = string.Empty;

     var serializer = new XmlSerializer(typeof (XMLEntities.CompleteBooking));
     var stringWriter = new System.IO.StringWriter();

     try
     {
       serializer.Serialize(stringWriter, completeBooking);
       serializedXml = stringWriter.ToString();
     }
     catch(Exception ex)
     {
       //Log the stuff
     }
     finally
     {
       stringWriter.Close();
     }

     return serializedXml;
   }
 }

现在，您只需创建正确定义的对象并在某种函数中进行序列化。例如，在控制台应用程序的主要方法中:

public static void Main(string[] args)
{
  //Create new booking objects
  var booking1 = new XMLEntities.Booking()
                  {
                    ID = 32,
                    BookingNumber = 1212001,
                    ReferenceNumber = "ABCED11212280007",
                    Name = "Customer Name1",
                    Address = "Customer Address"
                  };
  var booking2 = new XMLEntities.Booking()
                   {
                     ID = 33,
                     BookingNumber = 12120002,
                     ReferenceNumber = "ABCED11212280008",
                     Name = "Customer Name2",
                     Address = "Customer Address2"
                   };

  //Create the booking details objects

  var booking1Detail1 = new XMLEntities.BookingDetail()
                         {
                           ID = 206,
                           BookingID = 32,
                           OrderItem = "Item1"
                         };
  var booking1Detail2 = new XMLEntities.BookingDetail()
                          {
                            ID = 207,
                            BookingID = 32,
                            OrderItem = "Item2"
                          };

  var booking2Detail1 = new XMLEntities.BookingDetail()
                          {
                            ID = 208,
                            BookingID = 33,
                            OrderItem = "Item1"
                          };
  var booking2Detail2 = new XMLEntities.BookingDetail()
                          {
                            ID = 209,
                            BookingID = 32,
                            OrderItem = "Item2"
                          };
  var booking2Detail3 = new XMLEntities.BookingDetail()
                          {
                            ID = 210,
                            BookingID = 32,
                            OrderItem = "Item3"
                          };

  //Smash them together so we can serialize as one

  var completeBooking1 = new XMLEntities.CompleteBooking()
                          {
                            Bookings = booking1,
                            BookingDetail = new List<XMLEntities.BookingDetail>()
                                              {
                                                booking1Detail1,
                                                booking1Detail2
                                              }
                          };
  var completeBooking2 = new XMLEntities.CompleteBooking()
                           {
                             Bookings = booking2,
                             BookingDetail = new List<XMLEntities.BookingDetail>()
                                               {
                                                 booking2Detail1,
                                                 booking2Detail2,
                                                 booking2Detail3
                                               }
                           };

  //Serialize the data for each of the booking objects

  var serializedXML = new XMLEntitiesSerializer();
  var xml = string.Empty;

  var booking1XmlString = serializedXML.Serialize(completeBooking1);
  var booking2XmlString = serializedXML.Serialize(completeBooking2);

  Console.ReadLine();
}

显然，您可以在重构函数中使用它(这会让生活更轻松)，但这会为您提供所需的一般输出。

关于c# - 从数据创建的 XML 结构中面临的问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14889419/