我有以下这些 Java.lang.String 值代表 TIMESTAMPTZ 的 String 值。我需要将这些 Java.lang.String 转换为 oracle.sql.TIMESTAMPTZ。

"2016-04-19 17:34:43.781 Asia/Calcutta",
"2016-04-30 20:05:02.002 8:00",
"2003-11-11 00:22:15.0 -7:00",
"2003-01-01 02:00:00.0 -7:00",
"2007-06-08 15:01:12.288 Asia/Bahrain",
"2016-03-08 17:17:35.301 Asia/Calcutta",
"1994-11-24 11:57:17.303"

我尝试了很多方法。

示例 1:

使用 SimpleDateFormat 进行了尝试

String[] timeZoneValues = new String[]{"2016-04-19 17:34:43.781 Asia/Calcutta", "2016-04-30 20:05:02.002 8:00", "2003-11-11 00:22:15.0 -7:00", "2003-01-01 02:00:00.0 -7:00", "2007-06-08 15:01:12.288 Asia/Bahrain", "2016-03-08 17:17:35.301 Asia/Calcutta", "1994-11-24 11:57:17.303"};
        for(String timeZoneValue: timeZoneValues){
            SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS XXX");
            try {
                simpleDateFormat.parse(timeZoneValue);
            } catch (ParseException e) {
                e.printStackTrace();
            }
        }

抛出异常:

java.text.ParseException: Unparseable date: "2016-04-19 17:34:43.781 Asia/Calcutta"
    at java.text.DateFormat.parse(DateFormat.java:357)

示例 2:

尝试将这些 String 值直接转换为 Timestamp 或 oracle.sql.TIMESTAMPTZ

String parse = "2016-04-19 17:34:43.781 8:00";
        try {
            Timestamp timestamp = Timestamp.valueOf("2016-04-19 17:34:43.781 8:00");
        }catch (Exception ex){
            ex.printStackTrace();
        }

异常(exception):

java.lang.NumberFormatException: For input string: "781 8:000"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:492)
    at java.lang.Integer.parseInt(Integer.java:527)
    at java.sql.Timestamp.valueOf(Timestamp.java:253)

示例 3:

String parse = "2016-04-19 17:34:43.781 Asia/Calcutta";
DateTimeFormatter dateTimeFormatter = ISODateTimeFormat.dateTimeNoMillis();
DateTime dateTime = dateTimeFormatter.parseDateTime(parse);
Timestamp timeStamp = new Timestamp(dateTime.getMillis());

异常(exception):

Invalid format: "2016-04-19 17:34:43.781 Asia/Calcutta" is malformed at " 17:34:43.781 Asia/Calcutta"

示例 4:

try {
TIMESTAMPTZ timestamptz = new TIMESTAMPTZ(connection, (String) colValue);
}catch (Exception ex){
ex.printStackTrace();
}

异常(exception):

java.lang.IllegalArgumentException: Timestamp format must be yyyy-mm-dd hh:mm:ss[.fffffffff]
    at java.sql.Timestamp.valueOf(Timestamp.java:249)
    at oracle.sql.TIMESTAMPTZ.toBytes(TIMESTAMPTZ.java:1919)
    at oracle.sql.TIMESTAMPTZ.<init>(TIMESTAMPTZ.java:253)

我正在尝试使用 Apache Metamodel 将 TIMESTAMPTZ 值插入到 Oracle 数据库中，并且我有 Java 1.7安装在我的系统上。

最佳答案

您的时间戳不是标准的 java 可解析格式。因此，为了解析它们，您需要编写自定义代码来处理此类格式。

Couple of observations:

Asia/Calcutta is not a valid Parseable TimeZone, hence you need some mechanism to get corresponding timezone.

8:00 is also not a valid Parseable Timezone in java, hence you need some mechanism to format it in a valid value +08:00

请牢记以上几点，以下代码将为您完成所需的工作。

    SimpleDateFormat dateFormatTZGeneral = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS z");
    SimpleDateFormat dateFormatTZISO = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS XXX");
    SimpleDateFormat dateFormatWithoutTZ = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");


    String[][] zoneStrings = DateFormatSymbols.getInstance().getZoneStrings();

    Date date = null;

    String[] timeStampSplits = timestamp.split(" ");
    if(timeStampSplits.length>2) {

        String timezone = timeStampSplits[2];
        //First Case Asia/Calcutta
        if(Character.isAlphabetic(timezone.charAt(timezone.length()-1))) {

            for(String[] zoneString: zoneStrings) {
                if(zoneString[0].equalsIgnoreCase(timezone)) {
                    timeStampSplits[2] = zoneString[2];
                    break;
                }
            }

            timestamp = createString(timeStampSplits," ");
            date = getDate(timestamp, dateFormatTZGeneral);
        } else {
            //Second Case 8:00
            timeStampSplits[2] = formatTimeZone(timeStampSplits[2]);

            timestamp = createString(timeStampSplits," ");
            date = getDate(timestamp, dateFormatTZISO);
        }

    } else {
        // Third Case without timezone
        date = getDate(timestamp, dateFormatWithoutTZ);
    }

    System.out.println(date);

    TIMESTAMPTZ oraTimeStamp = new TIMESTAMPTZ(<connection object>,new java.sql.Timestamp(date.getTime());

以上代码使用了以下实用方法

private static Date getDate(String timestamp, SimpleDateFormat dateFormat) {
    Date date = null;
    try {
        date = dateFormat.parse(timestamp);
    } catch (ParseException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return date;
}

private static String createString(String[] contents, String separator) {
    StringBuilder builder = new StringBuilder();
    for (String content : contents) {
        builder.append(content).append(separator);
    }
    builder.deleteCharAt(builder.length()-separator.length());

    return builder.toString();
}

private static String formatTimeZone(String timeZone) {
    String[] timeZoneSplits = timeZone.split(":");
    DecimalFormat formatter = new DecimalFormat("+##;-#");
    formatter.setMinimumIntegerDigits(2);

    timeZoneSplits[0] = formatter.format(Integer.parseInt(timeZoneSplits[0]));
    return createString(timeZoneSplits, ":");
}

此代码是专门为满足您的时间戳示例而编写的，任何偏差都可能无法由此处理，并且需要更多定制。

希望对你有帮助。

关于java - 将 `Java.lang.String` 转换为 `oracle.sql.TIMESTAMPTZ`，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36911917/