嗨,我是改造服务的新手,并遵循了本教程 https://www.simplifiedcoding.net/retrofit-android-tutorial-to-get-json-from-server/它运行良好并且想创建我自己的所以我使用了一个新的 json web http://api.androidhive.info/contacts/包含
{
"contacts": [
{
"id": "c200",
"name": "Ravi Tamada",
"email": "ravi@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c201",
"name": "Johnny Depp",
"email": "johnny_depp@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c202",
"name": "Leonardo Dicaprio",
"email": "leonardo_dicaprio@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c203",
"name": "John Wayne",
"email": "john_wayne@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c204",
"name": "Angelina Jolie",
"email": "angelina_jolie@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c205",
"name": "Dido",
"email": "dido@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c206",
"name": "Adele",
"email": "adele@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c207",
"name": "Hugh Jackman",
"email": "hugh_jackman@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c208",
"name": "Will Smith",
"email": "will_smith@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c209",
"name": "Clint Eastwood",
"email": "clint_eastwood@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c2010",
"name": "Barack Obama",
"email": "barack_obama@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c2011",
"name": "Kate Winslet",
"email": "kate_winslet@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c2012",
"name": "Eminem",
"email": "eminem@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
}
]
我实现了自己的接口(interface)ContactAPI.java
public interface ContactsAPI {
@GET("/contacts/")
public void getContacts(Callback<List<Contact>> response);}
并实现了像这样的 Contact.java 模型类
public class Contact {
@SerializedName("id")
@Expose
private String id;
@SerializedName("name")
@Expose
private String name;
@SerializedName("email")
@Expose
private String email;
@SerializedName("address")
@Expose
private String address;
@SerializedName("gender")
@Expose
private String gender;
public String getId() {return id;}
public void setId(String id) {this.id = id;}
public String getName() {return name;}
public void setName(String name) {this.name = name;}
public String getEmail() {return email;}
public void setEmail(String email) {this.email = email;}
public String getAddress() {return address;}
public void setAddress(String address) {this.address = address;}
public String getGender() {return gender;}
public void setGender(String gender) {this.gender = gender;}}
然后终于在MainActivity.class中实现了我的Restadapter
public static final String ROOT_URL = "http://api.androidhive.info";
private ListView listView;
private List<Contact> contacts;
RestAdapter adapter = new RestAdapter.Builder().setEndpoint(ROOT_URL).build();
ContactsAPI api = adapter.create(ContactsAPI.class);
api.getContacts(new Callback<List<Contact>>() {
@Override
public void success(List<Contact> list, Response response) {
Toast.makeText(MainActivity.this,list.toString(),Toast.LENGTH_SHORT).show();
showList();
}
@Override
public void failure(RetrofitError error) {
//you can handle the errors here
Toast.makeText(MainActivity.this,"Error Occured:"+error.toString(),Toast.LENGTH_SHORT).show();
}
});
该应用程序运行顺利,但在延迟 4 秒后,它会提示一个错误,这是 public void failure(RetrofitError 错误)我不知道我错过了什么我检查了我的代码并没有发现任何错误请帮助我谢谢提前。
最佳答案
如果 json 是这个你需要一个类:
public class Contacts {
@SerializedName("contacts")
@Expose
private List<Contact> contacts = new ArrayList<Contact>();
/**
*
* @return
* The contacts
*/
public List<Contact> getContacts() {
return contacts;
}
/**
*
* @param contacts
* The contacts
*/
public void setContacts(List<Contact> contacts) {
this.contacts = contacts;
}
}
也在你的界面ContactAPI.java
public interface ContactsAPI {
@GET("/contacts/")
public void getContacts(Callback<Contacts> response);
}
还要检查这个链接,因为“+”有问题,这个 error
关于java - Android Retrofit 无响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38324306/
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