我正在尝试使用 prepare 语句创建最佳全局选择查询，一切正常，除了我收到警告:

警告:mysqli_stmt_bind_result():绑定(bind)变量的数量与准备语句中的字段数量不匹配

独特的全局选择功能

function querysp($selectquery, $type_bind, $colval) {
    global $db;
    $stmt = $db->prepare($selectquery);
    $stmt->bind_param($type_bind,$colval);
    $stmt->execute();
    mysqli_stmt_bind_result($stmt, $colval);
    $arr = array();
    if ($stmt) {
        while ($result = mysqli_stmt_fetch($stmt)) {
            array_push($arr, $result);
        }
    }
    return $arr;    
}

示例使用:

$select = "SELECT * from advertising WHERE status = ?";
$status = 1;
$advertising = querysp($select, 'i', $status);
foreach ($advertising as $ad) {
    $banner[] = $ad['banner'];
    $bannercode[] = $ad['bannercode'];
    $location[] = $ad['location'];
    $status = $ad['status'];
}

我错过了什么？抱歉，没有得到准确的准备，也在 SO 和 Google 上进行了检查，但无法解决这个问题。

编辑 2

我更改了选择查询，因为我将绑定(bind)参数的类型从 b(我认为是 bool 值)更改为 i，但仍然出现错误。

编辑 3 - 当前版本 - 仍然出现相同的错误:

$select = "SELECT banner, bannercode, location, status from advertising WHERE status = ?";
$status = 1;
$advertising = querysp($select, 'i', $status);
foreach ($advertising as $ad) {
    $banner[] = $ad['banner'];
    $bannercode[] = $ad['bannercode'];
    $location[] = $ad['location'];
    $status = $ad['status'];
}

和函数

function querysp($selectquery, $type_bind, $colval) {
    global $db;
    $stmt = $db->prepare($selectquery);
    $stmt->bind_param($type_bind,$colval);
    $stmt->execute();
    $stmt->bind_result($result);
    $arr = array();
    while($stmt->fetch()) {
        $arr[] = $result;
    }
    $stmt->close();
    return $arr;
}

最佳答案

花了一些时间，但这是我准备好的语句的版本，它是一堵墙，但它几乎捕获了可能出现的大多数错误。我试着在这里和那里添加一些文档来解释发生了什么。只需逐步阅读它，您就有望理解发生了什么。如果有任何不清楚的地方，请提出问题。

要使用下面发布的类，请执行此操作。

$query  = "SELECT ? FROM ?"; // can be any query
$params = array($param1, $param2); //must equal to ammount of "?" in query.
//an error will occur if $param1 or 2 is not of the type string, int, 
//bool or double, it can however be a double like this 2,1 instead of 2.1
$db = new databaseHandler();
$result = $db->runQuery($query, $params);
//or for short runQuery("SELECT * FROM *" , array());
if($result !== false){
    while($row = mysqli_fetch_array($result){
        $column1 = $row['columnname'];
        //just do with the result what you want.
    }
}else{
    echo "error occured";
}

这是能够处理数据库交互的类。不要以为您需要按照自己感觉最好的方式来设置连接。您可以对此运行所有类型的查询。

class databaseHandler{

private $x = ""; //required

//$query = the query, $params = array with params can be empty.
public function runQuery($query, Array $params){
    if($this->checkparams($params, $query)){
        //starts and returns the database connection
        $con = startConnection();    //<--- CHANGE THIS SO IT WORKS FOR YOU
        if($stmt = $con->prepare($query)){
            //obtains type of params if there are any.
            if(count($params) < 0){
                $type = "";
                $i=0;
                foreach($params as $par){
                    $par = $this->checktype($par);
                    $params[$i] = $par;
                    $type = $this->setType($type);
                    if($type === false){
                        echo "type error occured"
                        return false;
                    }
                    $i++;
                }
                //sets $type on the first spot of the array.
                array_unshift($params, $type)
                //binds the params
                call_user_func_array(array($stmt, 'bind_param'), $this->refValues($params));
            }
            $stmt->execute();
            $result - $stmt->get_result();
            stmt->close();
            return $result; // return the result of the query.
        }else{
            echo "error occured, bad connection";
            return false;
    }else{
        echo "params dont match prepared statement";
        return false;
    }
}

//checks if params are equal to prepared statement requirements.
checkparams($params, $query){
    //counts occurences of ? in query.
    $count = substr_count($q, "?");
    $i = count($params);
    if($count == $i){
        return true;
    }else{
        return false;
    }
}

//Checks the type of a param
public function checktype($par){
    $this->x = gettype($par);
    if($this->x == "string"){
        $npar = str_replace(",", ".", $par);
        if(is_numeric($npar)){
            $this->x = "integer";
            if(strpos($npar, ".")){
                $this->x="double";
                return $npar;
            }
        }
    }
    return $par;
}

//sets/adds to the type.
public function setType($type){
    //$this->x from checktype;
    switch($this->x){
        case "string":
        $type = $type."s";
        break;
        case "integer":
        $type = $type."i";
        break;
        case "double":
        $type = $type."d";
        break;
        case "boolean":
        $type = $type."b";
        break;
        case "NULL":
        $type = $type."s";
        default:
            return false;
    }
    return $type; 
}

//This function exist to resolve a few version errors in php.
//not sure what it does exactly, but it resolved some errors I had in the past.               
function refValues($arr){
    if(strnatcmp(phpversion(),'5.3') >= 0){
        $refs = array();
        foreach($arr as $key => $value)
            $refs[$key] = &$arr[$key];
        return $refs;
    }
    return $arr;
}
}
}

这里发生的几乎是一组执行查询的检查，如果出现任何错误，它返回 false 如果没有错误，它返回查询的结果，即使结果为空。也可以不在一个类中完成所有这些，尽管这会使 $x 全局化。我认为如果您修改某些内容以使其最适合您的应用程序，那将是最好的。比如错误处理/消息变量名等。

此代码唯一不能保护您的是查询中的错误。

编辑 ---- 我确实发现了这段代码也没有防止的东西，插入 NULL 值。我更改了此代码以防止插入 NULL 值，它们将作为字符串类型插入。数据库将看到它的 NULL 并将其作为 NULL 值插入。

只是不要尝试插入对象或空值，因为无论如何那都是无用的。

关于php - 添加准备语句会导致警告，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23995711/