我正在使用以下代码在 Hive 中解析 xml 数据。在我的 xml 数据中，一些标签在重复，所以我使用 brickhouse jar 和横向 View 来解析标签并放置在 Hive 表中。但是当我执行我的代码时，我收到了一个错误。请帮忙，因为我无法理解我做错了什么。

代码:

add jar /home/cloudera/brickhouse-0.5.5.jar;
CREATE TEMPORARY FUNCTION numeric_range AS 'brickhouse.udf.collect.NumericRange';
CREATE TEMPORARY FUNCTION array_index AS 'brickhouse.udf.collect.ArrayIndexUDF';
add jar /home/cloudera/hivexmlserde-1.0.5.3.jar;
set hive.exec.mode.local.auto=false;
DROP TABLE IF EXISTS medinfo2;
create table medinfo2 as
select array_index(statusCode,n) AS statusCode,
    array_index(startTime,n) AS startTime,
    array_index(endTime,n) AS endTime,
    array_index(strengthValue,n) AS strengthValue,
    array_index(strengthUnits,n) AS strengthUnits
from medications_info7 lateral view numeric_range(size( statusCode )) n1 as n;

错误:

Caused by: java.lang.IndexOutOfBoundsException: Index: 7, Size: 7 at java.util.ArrayList.rangeCheck(ArrayList.java:635) at java.util.ArrayList.get(ArrayList.java:411) at com.ibm.spss.hive.serde2.xml.objectinspector.XmlListObjectInspector.getListElement(XmlListObjectInspector.java:79) at brickhouse.udf.collect.ArrayIndexUDF.evaluate(ArrayIndexUDF.java:59) at org.apache.hadoop.hive.ql.exec.ExprNodeGenericFuncEvaluator._evaluate(ExprNodeGenericFuncEvaluator.java:186) at org.apache.hadoop.hive.ql.exec.ExprNodeEvaluator.evaluate(ExprNodeEvaluator.java:77) at org.apache.hadoop.hive.ql.exec.ExprNodeEvaluatorHead._evaluate(ExprNodeEvaluatorHead.java:44) at org.apache.hadoop.hive.ql.exec.ExprNodeEvaluator.evaluate(ExprNodeEvaluator.java:77) at org.apache.hadoop.hive.ql.exec.ExprNodeEvaluator.evaluate(ExprNodeEvaluator.java:65) at org.apache.hadoop.hive.ql.exec.SelectOperator.processOp(SelectOperator.java:77) ... 25 more

FAILED: Execution Error, return code 2 from org.apache.hadoop.hive.ql.exec.mr.MapRedTask MapReduce Jobs Launched: Stage-Stage-1: Map: 1 HDFS Read: 0 HDFS Write: 0 FAIL Total MapReduce CPU Time Spent: 0 msec

示例:

<document>
 <code>10160-0</code>
 <entryInfo> 
    <statusCode>completed</statusCode>
    <startTime>20110729</startTime>
    <endTime>20110822</endTime>
    <strengthValue>24</strengthValue>
    <strengthUnits>h</strengthUnits>
 </entryInfo> 
 <entryInfo>
    <statusCode>completed</statusCode>
    <startTime>20120130</startTime>
    <endTime>20120326</endTime>
    <strengthValue>12</strengthValue>
    <strengthUnits>h</strengthUnits>
 </entryInfo>
 <entryInfo>
    <statusCode>completed</statusCode>
    <startTime>20100412</startTime>
    <endTime>20110822</endTime>
    <strengthValue>8</strengthValue>
    <strengthUnits>d</strengthUnits>
 </entryInfo>  
</document>

我的实际样本很大，包含很多重复的标签。

最佳答案

我不知道您的数据在 Hive 中是什么样子，因为您没有提供该信息，所以这里是我如何将您的 XML 加载到 Hive 中。

加载程序:

ADD JAR /path/to/jar/hivexmlserde-1.0.5.3.jar;

DROP TABLE IF EXISTS db.tbl;
CREATE TABLE IF NOT EXISTS db.tbl (
  code STRING,
  entryInfo ARRAY<MAP<STRING,STRING>>
)
ROW FORMAT SERDE 'com.ibm.spss.hive.serde2.xml.XmlSerde'
WITH SERDEPROPERTIES (
  "column.xpath.code"="/document/code/text()",
  "column.xpath.entryInfo"="/document/entryInfo/*"
)
STORED AS
INPUTFORMAT 'com.ibm.spss.hive.serde2.xml.XmlInputFormat'
OUTPUTFORMAT 'org.apache.hadoop.hive.ql.io.IgnoreKeyTextOutputFormat'
TBLPROPERTIES (
  "xmlinput.start"="<document>",
  "xmlinput.end"="</document>"
);

LOAD DATA LOCAL INPATH 'someFile.xml' INTO TABLE db.tbl;

在Hive-XML-SerDe 3 - 数组 部分下的文档，您可以看到他们使用数组结构来处理重复的标签，而在 4 - map 部分，您可以看到他们使用 map 来处理条目在子标签下。所以，entryInfo将是 ARRAY<MAP<STRING,STRING>> 类型.

然后你可以分解这个数组，像键/值一样收集，然后重新组合。

查询:

ADD JAR /path/to/jar/hivexmlserde-1.0.5.3.jar;
ADD JAR /path/to/jars/brickhouse-0.7.1.jars;

CREATE TEMPORARY FUNCTION COLLECT AS 'brickhouse.udf.collect.CollectUDAF';

SELECT code
  , m_map['statusCode']    AS status_code
  , m_map['startTime']     AS start_time
  , m_map['endTime']       AS end_time
  , m_map['strengthValue'] AS strength_value
  , m_map['strengthUnits'] AS strength_units
FROM (
  SELECT code
    , COLLECT(m_keys, m_vals) AS m_map
  FROM (
    SELECT code
      , idx
      , MAP_KEYS(entry_info_map)[0]   AS m_keys
      , MAP_VALUES(entry_info_map)[0] AS m_vals
    FROM (
      SELECT code
        , entry_info_map
        , CASE
           WHEN FLOOR(tmp / 5) = 0 THEN 0
           WHEN FLOOR(tmp / 5) = 1 THEN 1
           WHEN FLOOR(tmp / 5) = 2 THEN 2
           ELSE -1
         END AS idx
      FROM db.tbl
      LATERAL VIEW POSEXPLODE(entryInfo) exptbl AS tmp, entry_info_map ) x ) y
  GROUP BY code, idx ) z

输出:

code    status_code     start_time      end_time    strength_value  strength_units
10160-0 completed       20110729        20110822    24              h
10160-0 completed       20120130        20120326    12              h
10160-0 completed       20100412        20110822    8               d

此外，您基本上已经问过这个问题 4 次(one、two、three、four)。这不是一个好主意。只需询问一次，编辑以添加更多信息，并耐心等待。

关于xml - 在 Hive 中使用横向 View 时出现异常，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41481582/