我有一个如下所示的 XMl 文件:

<?xml version="1.0" encoding="UTF-8"?>
<game >
  <moves>
    <turn>2</turn>
    <piece nr="1" />
    <turn>4</turn>
    <piece nr="1" />

  </moves>
</game>

我正在编写一个 Java 程序，它将 XML 文件作为输入，然后使用 SAX 和 SAX 过滤器对其进行解析并计算:

• turn元素内容之和(这里=6)
• 片元素的数量(此处=2)

然后我想使用 SAX 过滤器来生成与输入文件相同但具有附加元素的输出 XML 文件，例如:

<s:statistics>
    <s:turn-total>6</s:turn-total>
    <s:piece-count>2</s:piece-count>
</s:statistics>

前缀 s 是对 namespace 的引用.

到目前为止我的程序是:

 public class test{     
         public static void main(String[] args) throws Exception {
                if (args.length != 2) {
                System.err.println("error ");
                System.exit(1);
                }
                String xmlInput = args[0];
                String filteredXML = args[1];
                test test1 = new test();
                    test1.sax(xmlInput, filteredXML);
            }
    private void sax(String gameXML, String filteredGameXML)throws Exception{
        FileInputStream fis = new FileInputStream( gameXML);
        InputSource is = new InputSource(fis);
        XMLReader xr = XMLReaderFactory.createXMLReader();
        XMLFilter xf = new MyFilter();
        xf.setParent(xr);
        xr = xf;
        xr.parse(is);
        xr.setFeature("http://xml.org/sax/features/namespaces", true);
        DefaultHandler handler = new DefaultHandler();
        xr.setContentHandler(handler);
    }
    private class MyFilter extends XMLFilterImpl{
             StringBuffer buffer;
         int temp=0;
             int sum=0;
             String ff;
             int numof=0;
             private MyFilter() {}

            @Override
                public void startDocument() throws SAXException {
                     System.out.println( "START DOCUMENT" );
                    numof=0;        
                }

                public void startElement(String namespaceURI, String localName, String  name,   Attributes attributes) throws SAXException{
                    if(localName.equals("turn")){
                        buffer=new StringBuffer();
                        }
                    if("piece".equals(name)){
                        numof++;
                    }
                }

                public void characters(char[] ch, int start, int length) throws SAXException {
                    String s=new String(ch, start, length);
                    if(buffer!=null){
                        buffer.append(s);
                        }
                }

                public void endElement(String uri, String localName, String name)throws SAXException {
                    if(buffer!=null ){
                        ff=buffer.toString();
                        temp=Integer.valueOf(ff);
                        sum=sum+temp;
                        }
                        buffer=null;
                }
                public void endDocument() throws SAXException {
                    System.out.println( "END DOCUMENT" );
                    System.out.println("sum of turn: "+ sum);
                    System.out.println("sum of piece: "+ numof);
                }
         }

    }

接下来我该做什么？

最佳答案

您的 XMLFilter 应该委托(delegate)给另一个 ContentHandler，它根据 sax 事件序列化文档。

SAXTransformerFactory factory = (SAXTransformerFactory)TransformerFactory.newInstance();
TransformerHandler serializer = factory.newTransformerHandler();
Result result = new StreamResult(...);
serializer.setResult(result);

XMLFilterImpl filter = new MyFilter();
filter.setContentHandler(serializer);

XMLReader xmlreader = XMLReaderFactory.createXMLReader();
xmlreader.setFeature("http://xml.org/sax/features/namespaces", true);
xmlreader.setFeature("http://xml.org/sax/features/namespace-prefixes", true);
xmlreader.setContentHandler(filter);

xmlreader.parse(new InputSource(...));

您的回调应该委托(delegate)给 super 实现，它将事件转发给序列化 ContentHandler。

public void startElement(String namespaceURI, String localName, String qName, Attributes atts) throws SAXException {
    super.startElement(namespaceURI, localName, qName, atts);
    ...
}

在您的 endElement 回调中，您可以检查您是否位于最终结束标记处并添加额外的 sax 事件。

public void endElement(String namespaceURI, String localName, String qName) throws SAXException {
    super.endElement(namespaceURI, localName, qName);
    if ("game".equals(localName)) {
        super.startElement("", "statistics", "statistics", new AttributesImpl());
        char[] chars = String.valueOf(num).toCharArray();
        super.characters(chars, 0, chars.length);
        super.endElement("", "statistics", "statistics");
    }
    ...
}

关于java - 使用 SAX 过滤器将新元素插入 XML 文件，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/10598035/