我创建了一个不同级别的问答游戏，每个级别包含一个问题。我没有用数据库创建它。我只是用字符串。当用户在第一级回答问题时，他会被带到第二级，但当用户返回第一级时，他必须再次输入答案，即使他之前已经解决了。 JAVA 中有没有在不必创建数据库的情况下将答案保留在类型面板中(如果用户已经解决了)？此外，在类型面板中键入时，用户必须删除“在此处键入...”然后回答。无论如何，当用户点击键入时，“在此处键入...”是否会自动删除？

这是我的一级 activity.xml:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:background="@drawable/background"
    android:weightSum="1"
    android:textAlignment="center"
    android:id="@+id/level1">

    <TextView
        android:layout_width="300dp"
        android:layout_height="200dp"
        android:text="What has 88 keys but cannot open a single door?"
        android:id="@+id/que1"
        android:width="255dp"
        android:textSize="30dp"
        android:layout_margin="50dp"
        android:textStyle="italic"
        android:gravity="center" />

    <EditText
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:id="@+id/type1"
        android:layout_gravity="center_horizontal"
        android:text="Type here..." />

    <Button
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="Check answer..."
        android:id="@+id/check1"
        android:layout_gravity="center_horizontal" />
</LinearLayout>

这是我的 Oneactivity.java

package com.golo.user.gaunkhanekatha;

import android.app.Activity;
import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import android.os.Handler;



public class OneActivity extends Activity {
public SharedPreferences preferences; //ADDED THIS LINE
    public Button check;
    public EditText typeh;
    private Toast toast;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_one);
        toast = Toast.makeText(OneActivity.this, "", Toast.LENGTH_SHORT);
        check = (Button)findViewById(R.id.check1); //R.id.button is the id on your xml
        typeh = (EditText)findViewById(R.id.type1); //this is the EditText id
        check.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                // Perform action on click
                //Here you must get the text on your EditText
                String Answer = (String) typeh.getText().toString(); //here you have the text typed by the user
                //You can make an if statement to check if it's correct or not
                if(Answer.equals("Piano") || (Answer.equals("Keyboard")))
                {
                    preferences = PreferenceManager.getDefaultSharedPreferences(v.getContext());
                SharedPreferences.Editor editor = preferences.edit();
                editor.putInt("Level 1 question 1 ", 1); //Depends of the level he have passed.
                editor.apply();
                ///Correct Toast
                toast.setText("Correct");
                toast.setGravity(Gravity.TOP | Gravity.LEFT, 500, 300);
                toast.show();
                Intent i = new Intent(OneActivity.this, TwoActivity.class);
                startActivity(i);
                finish();

                }
                else{
                    //It's not the correct answer
                    toast.setText("Wrong! Try again...");
                    toast.show();
                }
            }
        });
    }

    @Override
    protected void onDestroy() {
        super.onDestroy();
        if(toast!= null) {
            toast.cancel();
        }
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.menu_aboutus, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item) {
        // Handle action bar item clicks here. The action bar will
        // automatically handle clicks on the Home/Up button, so long
        // as you specify a parent activity in AndroidManifest.xml.
        int id = item.getItemId();

        //noinspection SimplifiableIfStatement
        if (id == R.id.action_settings) {
            return true;
        }

        return super.onOptionsItemSelected(item);
    }
}

此外， toast 显示在有键盘的地方。有没有办法将 toast 屏幕移动到屏幕上清晰可见的某个位置？

最佳答案

我会给你两种方法来做到这一点:

创建一个 LevelEarned 类如下:

public class LevelEarned {
 public static int level = 0;
}

每次你得到一个Intent(因为用户已经正确回答了问题)只需输入:

LevelEarned.level = 1; // 1 depends with the level you have answered correctly

我为此使用的最好方法叫做 SharedPreferences

You can use SharedPreferences to save any primitive data: booleans, floats, ints, longs, and strings. This data will persist across user sessions (even if your application is killed).

您要做的第一件事是将此数据存储在 SharedPreferences 上，然后使用 Editor 执行此操作，如下所示:

SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(v.getContext());
SharedPreferences.Editor editor = preferences.edit();
editor.putInt("player_level",1); //Depends of the level he have passed.
editor.apply();

注意

我猜你会在用户接受问题时立即执行此操作，因此，你将在单击 Button 时执行此操作，因此你必须将 v.getContext 作为上下文传递() 如果你不在 ButtonClick 而你在你的 onCreate() 只需调用 this 来引用你的 上下文。

要获取存储的数据(级别)，您需要执行以下操作:

SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(this);
int level = preferences.getInt("player_level", 0);

让我们稍微解释一下。

第一个参数是找到 SharedPreference 的关键，所以它不会改变，第二个参数是默认值，在找不到任何 "player_level 时使用" SharedPreferences。

希望它能帮助您继续编写代码:)

编辑2

创建 SharedPreferences preferences 作为全局变量，如下所示:

public SharedPreferences preferences;

然后在您的 onClick() 方法中添加这些 channel :

check.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            // Perform action on click
            //Here you must get the text on your EditText
            String Answer = (String) typeh.getText().toString(); //here you have the text typed by the user
            //You can make an if statement to check if it's correct or not
            if(Answer.equals("4") || (Answer.equals("four")))
            {
                preferences = PreferenceManager.getDefaultSharedPreferences(v.getContext());
                SharedPreferences.Editor editor = preferences.edit();
                editor.putInt("player_level",1); //Depends of the level he have passed.
                editor.apply();
                //Create a Toast because it's correct
                Toast.makeText(OneActivity.this, "Correct!",
                        Toast.LENGTH_LONG).show();
            }
            else{
                //It's not the correct answer
                Toast.makeText(OneActivity.this, "Wrong! Try Again",
                        Toast.LENGTH_LONG).show();
            }
        }
    });

而你想知道你只需要做的水平的地方:

SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(this);
int level = preferences.getInt("player_level", 0); //level is the current level of the player.

编辑 3

创建一个类如下:

 public static class LevelPlayer(){

     public int static getLevelPlayer(){

     SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(this);
     int level = preferences.getInt("player_level", 0); //level is the current level of the playe


     return level;
     }

  }

每次你想问你的玩家水平时:

int Level = LevelPlayer.getLevelPlayer(); //that's the level

所以在每个问题之后你可以问级别并提出下一个问题。

编辑4

我做了一些更改，删除了你的 lvl 类并放置了这段代码:

public class lvl{
public Context mcontext;

public lvl(Context context){
    this.mcontext = context;

}
public int getLevelPlayer(){

    SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(mcontext);
    int level = preferences.getInt("player_level", 0); //level is the current level of the playe
    return level;
}

然后在你的MainActivity(或者任何你必须知道玩家等级的地方)你必须把这个:

public levelplayer mlevelplayer;

然后在你的 onCreate() 中添加:

mlevelplayer = new levelplayer(this);
int level  = mlevelplayer.getLevelPlayer();

关于java - 如何在不创建数据库的情况下保存谜语游戏中的答案？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32324876/